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Find the Jacobian \(\partial(x, y) / \partial(u, v)\). $$ x=\frac{2 u}{u^{2}+v^{2}}, y=-\frac{2 v}{u^{2}+v^{2}} $$

Short Answer

Expert verified
The Jacobian determinant is 0.

Step by step solution

01

Identify Variables and Functions

We have functions for variables: \[ x = \frac{2u}{u^2 + v^2} \] and \[ y = -\frac{2v}{u^2 + v^2} \].We aim to find the Jacobian, \( \frac{\partial(x, y)}{\partial(u, v)} \), which represents the determinant of the matrix formed by their partial derivatives.
02

Compute Partial Derivatives

To fill the Jacobian matrix, compute partial derivatives. The partial derivative \( \frac{\partial x}{\partial u} \) is obtained using the quotient rule:\[ \frac{\partial x}{\partial u} = \frac{(u^2 + v^2)(2) - 2u(2u)}{(u^2 + v^2)^2} = \frac{2v^2 - 2u^2}{(u^2 + v^2)^2}. \]
03

Compute Partial Derivatives Continued

Now compute \( \frac{\partial x}{\partial v} \) using the quotient rule:\[ \frac{\partial x}{\partial v} = \frac{0 - 2u(2v)}{(u^2 + v^2)^2} = -\frac{4uv}{(u^2 + v^2)^2}. \]
04

Compute Partial Derivatives for y

Repeat the process for \( y \):\[ \frac{\partial y}{\partial u} = \frac{0 - 2v(2u)}{(u^2 + v^2)^2} = -\frac{4uv}{(u^2 + v^2)^2}. \]
05

Compute Partial Derivatives for y Continued

Now find \( \frac{\partial y}{\partial v} \):\[ \frac{\partial y}{\partial v} = \frac{(u^2 + v^2)(-2) - (-2v)(2v)}{(u^2 + v^2)^2} = \frac{-2u^2 + 2v^2}{(u^2 + v^2)^2}. \]
06

Formulate the Jacobian Matrix

The Jacobian matrix \( J \) is:\[J = \begin{bmatrix} \frac{2v^2 - 2u^2}{(u^2 + v^2)^2} & -\frac{4uv}{(u^2 + v^2)^2} \-\frac{4uv}{(u^2 + v^2)^2} & \frac{-2u^2 + 2v^2}{(u^2 + v^2)^2} \end{bmatrix}. \]
07

Calculate the Determinant of the Jacobian

The determinant of \( J \) is found using:\[\text{det}(J) = \left(\frac{2v^2 - 2u^2}{(u^2 + v^2)^2}\right)\left(\frac{-2u^2 + 2v^2}{(u^2 + v^2)^2}\right) - \left(-\frac{4uv}{(u^2 + v^2)^2}\right)^2. \]This simplifies to:\[\text{det}(J) = 0.\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Partial Derivatives
Partial derivatives are an essential concept when dealing with functions of several variables. Unlike the regular derivative, which measures the rate of change of a function with respect to one variable, partial derivatives allow us to understand how a function changes as each individual variable changes separately.

For example, in the exercise, we have the functions:
  • \( x = \frac{2u}{u^2 + v^2} \)
  • \( y = -\frac{2v}{u^2 + v^2} \)
To find the Jacobian, which is a matrix of these partial derivatives, we take the derivative of each function \((x, y)\) with respect to each variable \((u, v)\).
By studying these derivatives, we can see how each variable influences a function while keeping all other variables constant. This process requires evaluating expressions involving complex fractions, often using rules like the quotient rule to simplify the steps.
Determinant
The determinant is a special value that can be calculated from a square matrix. In the context of the Jacobian, the determinant helps us understand the change in volume or area as a transformation is applied by a function.

For the task of finding the Jacobian determinant \( \frac{\partial(x, y)}{\partial(u, v)} \), the determinant is calculated from the 2x2 matrix formed by the partial derivatives. In our solution, the determinant of this matrix indicates how much distortion occurs when mapping points from one coordinate system to another.
The computation involves:
  • Multiplying the diagonal elements.
  • Subtracting the product of the off-diagonal elements.
Mathematically, this is expressed for our specific problem as:\[\text{det}(J) = \left(\frac{2v^2 - 2u^2}{(u^2 + v^2)^2}\right)\left(\frac{-2u^2 + 2v^2}{(u^2 + v^2)^2}\right) - \left(-\frac{4uv}{(u^2 + v^2)^2}\right)^2\]which simplifies to zero, indicating a special kind of transformation.
Quotient Rule
The quotient rule is a method used in calculus to find the derivative of a ratio of two differentiable functions. It is particularly useful when you are dealing with functions like in this exercise, where both numerators and denominators are variable expressions.

The quotient rule states that if you have a function \( f(x) = \frac{g(x)}{h(x)} \), then the derivative \( f'(x) \) is given by:\[f'(x) = \frac{g'(x)h(x) - g(x)h'(x)}{[h(x)]^2}\]In our exercise, this rule allows us to compute complex partial derivatives efficiently. For instance, in computing \( \frac{\partial x}{\partial u} \), we found:\[\frac{(u^2 + v^2)(2) - 2u(2u)}{(u^2 + v^2)^2}\]The expression shows how the numerator's derivative is adjusted by the denominator's influence, ensuring accurate results when functions are not straightforward. Understanding this rule is vital for tackling problems where variables are interdependent.

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Most popular questions from this chapter

The tendency of a solid to resist a change in rotational motion about an axis is measured by its moment of inertia about that axis. If the solid occupies a region \(G\) in an \(x y z\) -coordinate system, and if its density function \(\delta(x, y, z)\) is continuous on \(G,\) then the moments of inertia about the \(x\) -axis, the \(y\) -axis, and the \(z\) -axis are denoted by \(I_{x}, I_{y},\) and \(I_{z},\) respectively, and are defined by $$\begin{aligned} I_{x} &=\iiint_{G}\left(y^{2}+z^{2}\right) \delta(x, y, z) d V \\ I_{y} &=\iiint_{G}\left(x^{2}+z^{2}\right) \delta(x, y, z) d V \\ I_{z} &=\iiint_{G}\left(x^{2}+y^{2}\right) \delta(x, y, z) d V \end{aligned}$$ In these exercises, find the indicated moments of inertia of the solid, assuming that it has constant density \(\delta .\) \(I_{z}\) for the hollow cylinder \(a_{1}^{2} \leq x^{2}+y^{2} \leq a_{2}^{2}, 0 \leq z \leq h\)

Find the centroid of the solid. The solid in the first octant bounded by the surface \(z=x y\) and the planes \(z=0, x=2,\) and \(y=2\)

Use spherical coordinates. Find the mass of the solid enclosed between the spheres \(x^{2}+y^{2}+z^{2}=1\) and \(x^{2}+y^{2}+z^{2}=4\) if the density is \(\delta(x, y, z)=\left(x^{2}+y^{2}+z^{2}\right)^{-1 / 2}\)

Use a double integral in polar coordinates to find the area of the region described. The region inside the circle \(x^{2}+y^{2}=4\) and to the right of the line \(x=1\)

Evaluate the iterated integral by converting to polar coordinates. $$ \int_{0}^{1} \int_{y}^{\sqrt{y}} \sqrt{x^{2}+y^{2}} d x d y $$

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