Chapter 14: Problem 27
Find the volume enclosed by \(x^{2}+y^{2}+z^{2}=a^{2}\) using (a) cylindrical coordinates (b) spherical coordinates.
Short Answer
Expert verified
The volume of the sphere is \(\frac{4\pi}{3}a^3\) using both cylindrical and spherical coordinates.
Step by step solution
01
(a): Identify the conversion in cylindrical coordinates
Cylindrical coordinates relate to Cartesian coordinates as follows: \[ x = r \cos(\theta), \quad y = r \sin(\theta), \quad z = z \]where \( r \) is the radial distance \( r = \sqrt{x^2 + y^2} \) and \( \theta \) is the azimuthal angle. The equation of the sphere \( x^2 + y^2 + z^2 = a^2 \) can be expressed in cylindrical coordinates as:\[ r^2 + z^2 = a^2 \]
02
(a): Set up the integral for volume in cylindrical coordinates
To find the volume, we integrate the volume element \( dV = r \, dr \, d\theta \, dz \) over the domain described by \( r^2 + z^2 \leq a^2 \). We need to choose bounds for \( z \) and \( \theta \):- \( \theta \) ranges from 0 to \( 2\pi \)- For each \( z \), \( r \) ranges from 0 to \( \sqrt{a^2 - z^2} \)- \( z \) ranges from \( -a \) to \( a \)
03
(a): Evaluate the integral in cylindrical coordinates
The integral for volume in cylindrical coordinates becomes:\[ V = \int_{0}^{2\pi} \int_{-a}^{a} \int_{0}^{\sqrt{a^2 - z^2}} r \, dr \, dz \, d\theta \]Calculate the innermost integral (with respect to \( r \)), the result is:\[ \int_{0}^{\sqrt{a^2 - z^2}} r \, dr = \frac{1}{2}(a^2 - z^2) \]Then, integrate with respect to \( z \):\[ \int_{-a}^{a} \frac{1}{2}(a^2 - z^2) \, dz = \frac{2}{3}a^3 \]Finally, integrate with respect to \( \theta \):\[ \int_{0}^{2\pi} \frac{2}{3}a^3 \, d\theta = \frac{4\pi}{3}a^3 \]
04
(b): Identify the conversion in spherical coordinates
Spherical coordinates are given by \((\rho, \phi, \theta)\), where:\[ x = \rho \sin(\phi) \cos(\theta), \; y = \rho \sin(\phi) \sin(\theta), \; z = \rho \cos(\phi) \]The equation for the sphere \( x^2 + y^2 + z^2 = a^2 \) becomes \( \rho^2 = a^2 \), thus \( \rho = a \).
05
(b): Set up the integral for volume in spherical coordinates
The volume element in spherical coordinates is \( dV = \rho^2 \sin(\phi) \, d\rho \, d\phi \, d\theta \). Integrate over the sphere defined by \( 0 \leq \rho \leq a \), \( 0 \leq \phi \leq \pi \), and \( 0 \leq \theta \leq 2\pi \).
06
(b): Evaluate the integral in spherical coordinates
Write the volume integral in spherical coordinates:\[ V = \int_{0}^{2\pi} \int_{0}^{\pi} \int_{0}^{a} \rho^2 \sin(\phi) \, d\rho \, d\phi \, d\theta \]First, compute the innermost integral (with respect to \( \rho \)):\[ \int_{0}^{a} \rho^2 \, d\rho = \frac{1}{3}a^3 \]Next, integrate with respect to \( \phi \):\[ \int_{0}^{\pi} \sin(\phi) \, d\phi = 2 \]Lastly, integrate with respect to \( \theta \):\[ \int_{0}^{2\pi} \frac{1}{3}a^3 \, \cdot 2 \, d\theta = \frac{4\pi}{3}a^3 \]
07
Conclusion: Compare both methods
Both (a) cylindrical and (b) spherical coordinate methods give the same result for the volume enclosed by the sphere:\[\frac{4\pi}{3}a^3\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cylindrical Coordinates
Cylindrical coordinates extend the idea of two-dimensional polar coordinates into three dimensions by introducing an additional coordinate for height, often denoted as \( z \). These coordinates are expressed as \((r, \theta, z)\):
- \( r \) is the radial distance from the origin to the point's projection onto the \( xy \)-plane, calculated as \( r = \sqrt{x^2 + y^2} \).
- \( \theta \) is the angle between the positive \( x \)-axis and the line from the origin to the projection of the point onto the \( xy \)-plane.
- \( z \) is the height of the point above or below the \( xy \)-plane, the same as in Cartesian coordinates.
- \( x = r \cos(\theta) \)
- \( y = r \sin(\theta) \)
- \( z = z \)
Spherical Coordinates
Spherical coordinates are a system that extends the concept of polar coordinates into three dimensions using three parameters: radius, polar angle, and azimuthal angle. In spherical coordinates, a point is represented by \((\rho, \phi, \theta)\):
- \( \rho \) is the radial distance from the origin to the point, equivalent to the radius. In the case of a sphere of radius \( a \), \( \rho \) equals \( a \).
- \( \phi \) is the polar angle measured from the positive \( z \)-axis downwards, ranging from 0 to \( \pi \).
- \( \theta \) is the azimuthal angle in the \( xy \)-plane, similar to \( \theta \) in cylindrical coordinates, ranging from 0 to \( 2\pi \).
- \( x = \rho \sin(\phi) \cos(\theta) \)
- \( y = \rho \sin(\phi) \sin(\theta) \)
- \( z = \rho \cos(\phi) \)
Triple Integration
Triple integration is an extension of double integration to find the volume under a surface in three-dimensional space. It calculates the integral over a three-dimensional region, often involving a volume element. For the sphere, the volume element differs based on the coordinate system:
- In cylindrical coordinates, the volume element is \( dV = r \, dr \, d\theta \, dz \).
- In spherical coordinates, the volume element is \( dV = \rho^2 \sin(\phi) \, d\rho \, d\phi \, d\theta \).