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Use an appropriate form of the chain rule to find dw/dt. $$ w=5 x^{2} y^{3} z^{4} ; x=t^{2}, y=t^{3}, z=t^{5} $$

Short Answer

Expert verified
\( \frac{dw}{dt} = 10t^7 + 45t^{11} + 100t^{23} \).

Step by step solution

01

Understanding the Problem

We want to find the derivative \( \frac{dw}{dt} \) of the function \( w = 5x^2y^3z^4 \), where \( x = t^2 \), \( y = t^3 \), and \( z = t^5 \). We need to use the chain rule to solve it.
02

Applying the Chain Rule

The chain rule states that \( \frac{dw}{dt} = \frac{dw}{dx}\frac{dx}{dt} + \frac{dw}{dy}\frac{dy}{dt} + \frac{dw}{dz}\frac{dz}{dt} \). We will need to find these partial derivatives.
03

Calculating Partial Derivatives: dw/dx, dw/dy, dw/dz

For \( w = 5x^2y^3z^4 \), the partial derivatives are: \( \frac{\partial w}{\partial x} = 10xy^3z^4 \), \( \frac{\partial w}{\partial y} = 15x^2y^2z^4 \), \( \frac{\partial w}{\partial z} = 20x^2y^3z^3 \).
04

Calculating Derivatives: dx/dt, dy/dt, dz/dt

From the given \( x = t^2 \), \( y = t^3 \), \( z = t^5 \), we find derivatives: \( \frac{dx}{dt} = 2t \), \( \frac{dy}{dt} = 3t^2 \), \( \frac{dz}{dt} = 5t^4 \).
05

Substituting and Simplifying

Substitute the partial derivatives and derivatives into the chain rule formula: \( \frac{dw}{dt} = (10xy^3z^4)(2t) + (15x^2y^2z^4)(3t^2) + (20x^2y^3z^3)(5t^4) \). Simplify it.
06

Final Simplification

Substitute \( x = t^2 \), \( y = t^3 \), \( z = t^5 \) into the expression and simplify to get \( \frac{dw}{dt} = 10t^7 + 45t^{11} + 100t^{23} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Derivative
In calculus, a derivative represents how a function changes as its input changes. Imagine you have a graph of a function; the derivative helps you find the slope of the tangent line at any point on the graph. This gives an idea of how fast or slow a function is changing at that particular point.
  • The derivative of a function is often represented by \( \frac{dy}{dx} \) when describing the rate of change of \( y \) with respect to \( x \).

  • Derivatives are helpful in understanding rates of change in various fields like physics, economics, and biology.

Calculating a derivative involves different rules, such as the power rule, product rule, and chain rule. The chain rule is particularly useful when dealing with compositions of functions. If we have a function \( w = f(x, y, z) \), the chain rule helps us find the rate of change of \( w \) in terms of another variable, like \( t \), by considering how \( x \), \( y \), and \( z \) change with \( t \).
Partial Derivatives
Partial derivatives focus on how a function changes with respect to one variable while keeping others constant. This is useful in multivariable calculus where functions depend on more than one variable. If a function is defined as \( w = f(x, y, z) \), we can take partial derivatives \( \frac{\partial w}{\partial x} \), \( \frac{\partial w}{\partial y} \), and \( \frac{\partial w}{\partial z} \) to understand how changes in each variable affect \( w \).
  • The notation \( \frac{\partial }{\partial x} \) indicates the partial derivative with respect to \( x \), treating other variables as constants.

  • To find \( \frac{\partial w}{\partial x} \), we only differentiate components of \( w \) involving \( x \) while treating \( y \) and \( z \) as constant factors.

In the given problem, identifying \( \frac{\partial w}{\partial x} \), \( \frac{\partial w}{\partial y} \), and \( \frac{\partial w}{\partial z} \) is crucial because they represent how much \( w \) changes due to individual contributions of \( x \), \( y \), and \( z \).
Calculus
Calculus is a branch of mathematics focused on change and motion. It's divided into two main branches: differential calculus (concerned with derivatives and rates of change) and integral calculus (focused on accumulation and area under curves). In our exercise, differential calculus plays a major role.
  • Calculus allows us to understand and quantify changes, which is essential in fields ranging from engineering to biology.

  • Common tools in calculus include derivatives, integrals, limits, and infinite series.

The chain rule, which is a core concept in differential calculus, enables calculations involving composite functions. This is crucial when functions are nested or expressed in terms of other variables, as seen with \( w = 5x^2y^3z^4 \) where \( x \), \( y \), and \( z \) themselves depend on \( t \).
Grasping these fundamental calculus concepts helps understand complex changes and the interactions between different variable rates of change.

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Most popular questions from this chapter

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The length, width, and height of a rectangular box are \(l=5, w=2,\) and \(h=3,\) respectively. (a) Find the instantaneous rate of change of the volume of the box with respect to the length if \(w\) and \(h\) are held constant. (b) Find the instantaneous rate of change of the volume of the box with respect to the width if \(l\) and \(h\) are held constant. (c) Find the instantaneous rate of change of the volume of the box with respect to the height if \(l\) and \(w\) are held constant.

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