Chapter 13: Problem 7
Use an appropriate form of the chain rule to find dw/dt. $$ w=5 x^{2} y^{3} z^{4} ; x=t^{2}, y=t^{3}, z=t^{5} $$
Short Answer
Expert verified
\( \frac{dw}{dt} = 10t^7 + 45t^{11} + 100t^{23} \).
Step by step solution
01
Understanding the Problem
We want to find the derivative \( \frac{dw}{dt} \) of the function \( w = 5x^2y^3z^4 \), where \( x = t^2 \), \( y = t^3 \), and \( z = t^5 \). We need to use the chain rule to solve it.
02
Applying the Chain Rule
The chain rule states that \( \frac{dw}{dt} = \frac{dw}{dx}\frac{dx}{dt} + \frac{dw}{dy}\frac{dy}{dt} + \frac{dw}{dz}\frac{dz}{dt} \). We will need to find these partial derivatives.
03
Calculating Partial Derivatives: dw/dx, dw/dy, dw/dz
For \( w = 5x^2y^3z^4 \), the partial derivatives are: \( \frac{\partial w}{\partial x} = 10xy^3z^4 \), \( \frac{\partial w}{\partial y} = 15x^2y^2z^4 \), \( \frac{\partial w}{\partial z} = 20x^2y^3z^3 \).
04
Calculating Derivatives: dx/dt, dy/dt, dz/dt
From the given \( x = t^2 \), \( y = t^3 \), \( z = t^5 \), we find derivatives: \( \frac{dx}{dt} = 2t \), \( \frac{dy}{dt} = 3t^2 \), \( \frac{dz}{dt} = 5t^4 \).
05
Substituting and Simplifying
Substitute the partial derivatives and derivatives into the chain rule formula: \( \frac{dw}{dt} = (10xy^3z^4)(2t) + (15x^2y^2z^4)(3t^2) + (20x^2y^3z^3)(5t^4) \). Simplify it.
06
Final Simplification
Substitute \( x = t^2 \), \( y = t^3 \), \( z = t^5 \) into the expression and simplify to get \( \frac{dw}{dt} = 10t^7 + 45t^{11} + 100t^{23} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Derivative
In calculus, a derivative represents how a function changes as its input changes. Imagine you have a graph of a function; the derivative helps you find the slope of the tangent line at any point on the graph. This gives an idea of how fast or slow a function is changing at that particular point.
- The derivative of a function is often represented by \( \frac{dy}{dx} \) when describing the rate of change of \( y \) with respect to \( x \).
- Derivatives are helpful in understanding rates of change in various fields like physics, economics, and biology.
Partial Derivatives
Partial derivatives focus on how a function changes with respect to one variable while keeping others constant. This is useful in multivariable calculus where functions depend on more than one variable. If a function is defined as \( w = f(x, y, z) \), we can take partial derivatives \( \frac{\partial w}{\partial x} \), \( \frac{\partial w}{\partial y} \), and \( \frac{\partial w}{\partial z} \) to understand how changes in each variable affect \( w \).
- The notation \( \frac{\partial }{\partial x} \) indicates the partial derivative with respect to \( x \), treating other variables as constants.
- To find \( \frac{\partial w}{\partial x} \), we only differentiate components of \( w \) involving \( x \) while treating \( y \) and \( z \) as constant factors.
Calculus
Calculus is a branch of mathematics focused on change and motion. It's divided into two main branches: differential calculus (concerned with derivatives and rates of change) and integral calculus (focused on accumulation and area under curves). In our exercise, differential calculus plays a major role.
Grasping these fundamental calculus concepts helps understand complex changes and the interactions between different variable rates of change.
- Calculus allows us to understand and quantify changes, which is essential in fields ranging from engineering to biology.
- Common tools in calculus include derivatives, integrals, limits, and infinite series.
Grasping these fundamental calculus concepts helps understand complex changes and the interactions between different variable rates of change.