Chapter 13: Problem 57
Find a unit vector in the direction in which \(f\) decreases most rapidly at \(P,\) and find the rate of change of \(f\) at \(P\) in that direction. $$ f(x, y)=\cos (3 x-y) ; \quad P(\pi / 6, \pi / 4) $$
Short Answer
Expert verified
Unit vector: \(\left\langle \frac{3}{\sqrt{10}}, \frac{-1}{\sqrt{10}} \right\rangle\); Rate of change: \(-\sqrt{10}\).
Step by step solution
01
Find the Gradient of the Function
The gradient of a function, \(f(x, y)\), is the vector of its partial derivatives. Let's calculate the gradient of \(f(x, y) = \cos(3x - y)\). The partial derivatives are given by: \[\frac{\partial f}{\partial x} = -3\sin(3x - y) \quad \text{and} \quad \frac{\partial f}{\partial y} = \sin(3x - y)\]Thus, the gradient is:\[abla f(x, y) = \langle -3\sin(3x - y), \sin(3x - y) \rangle\]Evaluate this at point \(P(\pi/6, \pi/4)\).
02
Evaluate the Gradient at P(\pi/6, \pi/4)
Substitute \(x = \pi/6\) and \(y = \pi/4\) into the gradient:\[abla f\left(\frac{\pi}{6}, \frac{\pi}{4}\right) = \left\langle -3\sin(\frac{\pi}{2}), \sin(\frac{\pi}{2}) \right\rangle = \langle -3, 1 \rangle\]The gradient at \(P\) is \(\langle -3, 1 \rangle\).
03
Determine the Unit Vector in the Most Rapid Decrease Direction
The direction of most rapid decrease is the negative gradient direction. The gradient at \(P\) is \(\langle -3, 1 \rangle\), so the direction of fastest decrease is \(\langle 3, -1 \rangle\). To find the unit vector in this direction, calculate its magnitude and then divide the vector by its magnitude:\[\text{Magnitude} = \sqrt{3^2 + (-1)^2} = \sqrt{10}\]The unit vector is:\[\left\langle \frac{3}{\sqrt{10}}, \frac{-1}{\sqrt{10}} \right\rangle\]
04
Calculate the Rate of Change in that Direction
The rate of change of \(f\) at \(P\) in the direction \(\langle 3, -1 \rangle\) is the negative magnitude of the gradient:\[\text{Rate of change} = -\|abla f(P)\| = -\sqrt{10}\]Therefore, the rate of change in the direction of decrease is \(-\sqrt{10}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Gradient Vector
The gradient vector of a function is a crucial concept in multivariable calculus. It represents the direction and rate of the steepest ascent of a scalar field. For a function of two variables, like our function, the gradient is a two-dimensional vector containing the partial derivatives with respect to each variable.
Evaluating at point \(P(\pi/6, \pi/4)\) gives us the vector \(\langle -3, 1 \rangle\), showing that the function's steepest ascent at this point is in this direction.
- The gradient of a function \(f(x, y)\) is denoted as \(abla f(x, y)\).
- The components include \(\frac{\partial f}{\partial x}\) and \(\frac{\partial f}{\partial y}\), representing the rate of change of the function in the directions of the x-axis and y-axis, respectively.
Evaluating at point \(P(\pi/6, \pi/4)\) gives us the vector \(\langle -3, 1 \rangle\), showing that the function's steepest ascent at this point is in this direction.
Directional Derivative
The directional derivative is a fundamental concept when analyzing changes in functions. It generalizes the concept of a derivative from one-dimensional functions to functions of multiple variables. Essentially, it measures how a function changes as you move in a specific direction.
- The directional derivative of a function \(f\) at a point \(P\) in the direction of a vector \(\mathbf{v}\) is given by the dot product of the gradient \(abla f(P)\) and the unit vector \(\mathbf{u}\) in the direction of \(\mathbf{v}\).
- If \(\mathbf{v}\) is not a unit vector, you first normalize it, dividing it by its magnitude to get \(\mathbf{u}\).
Partial Derivatives
Partial derivatives are the building blocks for understanding gradients and directional derivatives. When dealing with functions of several variables, a partial derivative represents how the function changes as you vary one variable while keeping others constant.
- The partial derivative with respect to \(x\), denoted \(\frac{\partial f}{\partial x}\), considers changes only along the x-axis.
- Similarly, \(\frac{\partial f}{\partial y}\) examines changes along the y-axis.