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Find \(f_{x}, f_{y},\) and \(f_{z}\) $$ f(x, y, z)=\cosh (\sqrt{z}) \sinh ^{2}\left(x^{2} y z\right) $$

Short Answer

Expert verified
The partial derivatives are: \( f_x = 4xyz \cosh(\sqrt{z}) \sinh(x^2yz) \cosh(x^2yz) \), \( f_y = 2x^2z \cosh(\sqrt{z}) \sinh(x^2yz) \cosh(x^2yz) \), \( f_z = \frac{1}{2\sqrt{z}} \sinh(\sqrt{z}) \sinh^2(x^2yz) + 2x^2y \cosh(\sqrt{z}) \sinh(x^2yz) \cosh(x^2yz) \).

Step by step solution

01

Understanding the Partial Derivatives

We need to find the partial derivatives \( f_x, f_y, \) and \( f_z \) of the function \( f(x, y, z) = \cosh (\sqrt{z}) \sinh^{2}(x^2 y z) \). Each partial derivative is found by treating the other variables as constants.
02

Finding the Partial Derivative with Respect to \( x \)

Start by differentiating \( f \) with respect to \( x \). The derivative of \( \sinh^2(u) \) with respect to \( u \) is \( 2 \sinh(u) \cosh(u) \). Let \( u = x^2yz \), then \( \frac{\partial}{\partial x}(u) = 2xyz \). Thus, using the chain rule: \[ f_x = \cosh(\sqrt{z}) \cdot 2 \sinh(u) \cosh(u) \cdot 2xyz \] Substitute \( u \) back: \[ f_x = 4xyz \cosh(\sqrt{z}) \sinh(x^2yz) \cosh(x^2yz) \]
03

Finding the Partial Derivative with Respect to \( y \)

Differentiate \( f \) with respect to \( y \). With \( u = x^2 y z \), the derivative is \( \frac{\partial}{\partial y}(u) = x^2z \). Thus, applying the chain rule gives: \[ f_y = \cosh(\sqrt{z}) \cdot 2 \sinh(u) \cosh(u) \cdot x^2z \] Substitute \( u \): \[ f_y = 2x^2z \cosh(\sqrt{z}) \sinh(x^2yz) \cosh(x^2yz) \]
04

Finding the Partial Derivative with Respect to \( z \)

Differentiate \( f \) with respect to \( z \). The function is a product of two functions: \( \cosh(\sqrt{z}) \) and \( \sinh^2(x^2yz) \). Using the product rule: \[ f_z = \frac{d}{dz}[\cosh(\sqrt{z})] \sinh^2(x^2yz) + \cosh(\sqrt{z}) \frac{d}{dz}[\sinh^2(x^2yz)] \] The derivative of \( \cosh(\sqrt{z}) \) with respect to \( z \) is \( \sinh(\sqrt{z}) \cdot \frac{1}{2\sqrt{z}} \). For \( \sinh^2(u) \) with \( u = x^2yz \), \( \frac{d}{dz}(u) = x^2y \), so: \[ f_z = \sinh(\sqrt{z}) \cdot \frac{1}{2\sqrt{z}} \cdot \sinh^2(x^2yz) + \cosh(\sqrt{z}) \cdot 2\sinh(x^2yz) \cosh(x^2yz) \cdot x^2y \] Simplifying: \[ f_z = \frac{1}{2\sqrt{z}} \sinh(\sqrt{z}) \sinh^2(x^2yz) + 2x^2y \cosh(\sqrt{z}) \sinh(x^2yz) \cosh(x^2yz) \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Calculus
Calculus is a branch of mathematics that studies how things change. It is used to find rates of change (derivatives) and the area under curves (integrals). One important concept in calculus is the derivative, which measures how a function changes as its input changes. In the context of this exercise, we're discussing partial derivatives. These are a type of derivative used when dealing with functions of multiple variables. For a function like \( f(x, y, z) \), the partial derivative with respect to \( x \) tells us how \( f \) changes as \( x \) changes, keeping \( y \) and \( z \) constant. Partial derivatives form the basis for understanding more complex processes in multivariable functions, such as describing the slope or change of a function in various directions.

When we differentiate \( f(x, y, z) \) with respect to \( x \), \( y \), or \( z \), each of these acts as a partial derivative. Notably, we simplify the task by temporarily treating all other variables as constant. This feature is key for solving complex multivariable problems in real-life applications like physics and engineering, where systems often depend on several changing variables.
Chain Rule
The chain rule is an essential concept in calculus, especially when working with composite functions. It allows us to differentiate functions that are nested within other functions. Simply put, it provides a method for differentiating a function based on its inner and outer components. This becomes particularly useful when dealing with functions of several variables, as in this exercise.

Let's break down how the chain rule works in the context of our function \( f(x, y, z) \). Consider the expression \( \sinh^2(x^2 y z) \). Here, the inner function is \( x^2 y z \), and the outer function is \( \sinh^2(u) \) with respect to \( u \). To find the derivative, apply the chain rule, which simplifies the process by first differentiating the outer function and then the inner one:

  • Differentiate the outer function: \( 2 \sinh(u) \cosh(u) \)
  • Then multiply it by the derivative of the inner function based on the variable of interest. For instance, \( \frac{\partial}{\partial x}(x^2 y z) = 2xy z \).

This application effectively demonstrates how the chain rule simplifies the differentiation of complex nested functions, resulting in a clear pathway to derive the required partial derivatives.
Multivariable Functions
Multivariable functions extend the concept of a mathematical function to more than one variable. Unlike single-variable functions, multivariable functions involve several independent variables, influencing how we approach problem-solving and differentiation. In our given problem, \( f(x, y, z) = \cosh(\sqrt{z}) \sinh^2(x^2 y z) \), this means the function's behavior depends on three variables: \( x \), \( y \), and \( z \).

Understanding how each variable affects the overall function is crucial. That's where partial derivatives come into play, enabling us to observe how changing one variable at a time impacts the function. For each partial derivative—\( f_x \), \( f_y \), and \( f_z \)—we take into account the specific influence of one variable while treating others as constants.

These methods are widely utilized in fields like physics, economics, and engineering, where multiple factors can simultaneously affect system behavior. Being able to analyze each variable's contribution separately simplifies complex analyses, making it easier to address practical real-world problems. This breakdown of each contributing variable through multivariable calculus is vital for detailed and accurate modeling.

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Most popular questions from this chapter

Solve using Lagrange multipliers. Find the point on the line \(2 x-4 y=3\) that is closest to the origin.

Find three positive numbers whose sum is 27 and such that the sum of their squares is as small as possible.

Find \(f_{x}, f_{y},\) and \(f_{z}\) $$ f(x, y, z)=\tan ^{-1}\left(\frac{1}{x y^{2} z^{3}}\right) $$

A common problem in experimental work is to obtain a mathematical relationship \(y=f(x)\) between two variables \(x\) and \(y\) by "fitting" a curve to points in the plane that correspond to experimentally determined values of \(x\) and \(y,\) say $$ \left(x_{1}, y_{1}\right),\left(x_{2}, y_{2}\right), \ldots,\left(x_{n}, y_{n}\right) $$ The curve \(y=f(x)\) is called a mathematical model of the data. The general form of the function \(f\) is commonly determined by some underlying physical principle, but sometimes it is just determined by the pattern of the data. We are concerned with fitting a straight line \(y=m x+b\) to data. Usually, the data will not lie on a line (possibly due to experimental error or variations in experimental conditions), so the problem is to find a line that fits the data "best" according to some criterion. One criterion for selecting the line of best fit is to choose \(m\) and \(b\) to minimize the function $$ g(m, b)=\sum_{i=1}^{n}\left(m x_{i}+b-y_{i}\right)^{2} $$ This is called the method of least squares, and the resulting line is called the regression line or the least squares line of best fit. Geometrically, \(\left|m x_{i}+b-y_{i}\right|\) is the vertical distance between the data point \(\left(x_{i}, y_{i}\right)\) and the line \(y=m x+b\) These vertical distances are called the residuals of the data points, so the effect of minimizing \(g(m, b)\) is to minimize the sum of the squares of the residuals. In these exercises, we will derive a formula for the regression line. The purpose of this exercise is to find the values of \(m\) and \(b\) that produce the regression line. (a) To minimize \(g(m, b),\) we start by finding values of \(m\) and \(b\) such that \(\partial g / \partial m=0\) and \(\partial g / \partial b=0 .\) Show that these equations are satisfied if \(m\) and \(b\) satisfy the conditions $$ \left(\sum_{i=1}^{n} x_{i}^{2}\right) m+\left(\sum_{i=1}^{n} x_{i}\right) b=\sum_{i=1}^{n} x_{i} y_{i} $$ \(\left(\sum_{i=1}^{n} x_{i}\right) m+n b=\sum_{i=1}^{n} y_{i}\) (b) Let \(\bar{x}=\left(x_{1}+x_{2}+\cdots+x_{n}\right) / n\) denote the arithmetic average of \(x_{1}, x_{2}, \ldots, x_{n} .\) Use the fact that $$ \sum_{i=1}^{n}\left(x_{i}-\bar{x}\right)^{2} \geq 0 $$ to show that $$ n\left(\sum_{i=1}^{n} x_{i}^{2}\right)-\left(\sum_{i=1}^{n} x_{i}\right)^{2} \geq 0 $$ with equality if and only if all the \(x_{i}\) 's are the same. (c) Assuming that not all the \(x_{i}\) 's are the same, prove that the equations in part (a) have the unique solution $$ \begin{aligned} m=& \frac{n \sum_{i=1}^{n} x_{i} y_{i}-\sum_{i=1}^{n} x_{i} \sum_{i=1}^{n} y_{i}}{n \sum_{i=1}^{n} x_{i}^{2}-\left(\sum_{i=1}^{n} x_{i}\right)^{2}} \\ b=& \frac{1}{n}\left(\sum_{i=1}^{n} y_{i}-m \sum_{i=1}^{n} x_{i}\right) \end{aligned} $$ [Note: We have shown that \(g\) has a critical point at these values of \(m\) and \(b\). In the next exercise we will show that \(g\) has an absolute minimum at this critical point. Accepting this to be so, we have shown that the line \(y=m x+b\) is the regression line for these values of \(m \text { and } b .]\)

Solve using Lagrange multipliers. Find the points on the surface \(x y-z^{2}=1\) that are closest to the origin.

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