/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 19 Determine whether the statement ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Determine whether the statement is true or false. Explain your answer. If \(\mathbf{r}(s)\) parametrizes the graph of \(y=|x|\) in 2 -space by arc length, then \(\mathbf{r}(s)\) is smooth.

Short Answer

Expert verified
False, \( \mathbf{r}(s) \) is not smooth due to the cusp at \( x = 0 \).

Step by step solution

01

Understand the Problem

The problem asks whether the parametrization \( \mathbf{r}(s) \) of the graph of \( y = |x| \) by arc length is smooth. A parametrization is smooth if its derivative exists and is continuous everywhere along its domain.
02

Analyzing the Function

The function \( y = |x| \) is graphed as two linear segments meeting at \( x = 0 \). It is continuous everywhere but has a corner or cusp at \( x = 0 \), which implies discontinuity in its derivative at that point.
03

Assessing Smoothness at Critical Points

For a parametrization \( \mathbf{r}(s) \) by arc length to be smooth, \( \mathbf{r}'(s) \) must exist and be continuous. At \( x = 0 \) in \( y = |x| \), a cusp is present, which means the direction of the tangent vector changes abruptly. Thus, the derivative is undefined at this point.
04

Conclusion on Smoothness

Since the derivative \( \mathbf{r}'(s) \) does not exist at \( x = 0 \) due to the discontinuity in the tangent direction, \( \mathbf{r}(s) \) is not smooth across its entire domain.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Arc Length
Arc length represents the distance along a curve from one point to another. When dealing with curves, such as those mapped by equations, understanding how arc length works is key to grasping how curves and paths behave. The arc length of a parameterized curve, especially with respect to a variable like \( s \), can provide insights into the geometry of the curve. Calculating the arc length involves integrating the speed of the curve over the interval, essentially summing up the small pieces of distance to get the total length.

When a curve is parameterized by arc length, the parameter \( s \) itself represents the distance traveled along the curve. This parameterization can simplify problems since each unit increment in \( s \) corresponds directly to one unit of distance traveled down the path of the curve. However, given the curve needs to be smooth for a proper parameterization by arc length, any discontinuity or sharp corner could disrupt this ease of parameterization.
Graph of y=|x|
The graph of \( y = |x| \) is quite straightforward yet geometrically interesting. It consists of two linear sections joined at a point, forming a 'V' shape. For \( x \geq 0 \), the graph is a straight line with a slope of 1, while for \( x < 0 \), it’s a straight line with a slope of -1. At \( x = 0 \), these two lines meet, creating a sharp corner known as a 'cusp'.

This cusp at the origin point (0,0) poses significant challenges when attempting to perform certain mathematical operations, such as differentiating. While the graph is continuous, meaning that there’s no break in the curve, the direction of the slope changes abruptly at this corner. This critical point is central to discussions on smoothness and parametric curves, particularly when exploring the nature of derivatives.
Smooth Curves
In mathematics, a curve is considered smooth if its first derivative exists and is continuous over its entire length. A smooth curve means no sharp corners or cusps are present along it. This property ensures that as you move along the curve, the direction changes in a gentle, flowing manner.

For parametrizations, like with \( \mathbf{r}(s) \), smoothness indicates that there's a continuous rate of change throughout the entire curve, with no abrupt shifts. It's akin to a car smoothly driving without any sudden turns or stops. When a curve is not smooth, it signifies places where the mathematical description of the curve becomes problematic, such as where the derivative is undefined, like at the corners in \( y = |x| \). Ensuring a curve is smooth often simplifies calculations and improves the understanding of the path's nature.
Discontinuity in Derivative
A function's derivative represents the rate at which its dependent variable changes concerning its independent variable. When a discontinuity occurs in a derivative, it signals that the rate of change undergoes a sudden shift. This often indicates issues like cusps, corners, or vertical tangents. In the graph of \( y = |x| \), such a discontinuity in the derivative arises at the origin, \( x = 0 \).

Here, while the graph of \( y = |x| \) itself is continuous, its derivative is not defined. The abrupt direction change at \( x = 0 \) makes it impossible to assign a single tangent direction, highlighting a break in the derivative's continuity. Understanding derivatives and their discontinuities can provide deeper insights into a curve's shape, behavior, and inherent properties, particularly in real-world applications where smooth transitions are often paramount.

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Most popular questions from this chapter

What can you say about the trajectory of a particle that moves in 2 -space or 3 -space with zero acceleration? Justify your answer.

In these exercises \(\mathbf{v}\) and a are given at a certain instant of time. Find \(a_{T}, a_{N}, \mathbf{T},\) and \(\mathbf{N}\) at this instant.. $$ \mathbf{v}=3 \mathbf{i}-4 \mathbf{k}, \mathbf{a}=\mathbf{i}-\mathbf{j}+2 \mathbf{k} $$

These exercises are concerned with the problem of creating a single smooth curve by piecing together two separate smooth curves. If two smooth curves \(C_{1}\) and \(C_{2}\) are joined at a point \(P\) to form a curve \(C,\) then we will say that \(C_{1}\) and \(C_{2}\) make a smooth transition at \(P\) if the curvature of \(C\) is continuous at \(P\). Assume that \(f\) is a function for which \(f^{\prime \prime \prime}(x)\) is defined for all \(x \leq 0 .\) Explain why it is always possible to find numbers \(a, b,\) and \(c\) such that there is a smooth transition at \(x=0\) from the curve \(y=f(x), x \leq 0,\) to the parabola \(y=a x^{2}+b x+c\)

In these exercises \(\mathbf{r}(t)\) is the position vector of a particle moving in the plane. Find the velocity, acceleration, and speed at an arbitrary time \(t .\) Then sketch the path of the particle together with the velocity and acceleration vectors at the indicated time \(t .\) $$ \mathbf{r}(t)=e^{t} \mathbf{i}+e^{-t} \mathbf{j} ; t=0 $$

Show that in cylindrical coordinates a curve given by the parametric equations \(r=r(t), \theta=\theta(t), z=z(t)\) for \(a \leq t \leq b\) has arc length $$ L=\int_{a}^{b} \sqrt{\left(\frac{d r}{d t}\right)^{2}+r^{2}\left(\frac{d \theta}{d t}\right)^{2}+\left(\frac{d z}{d t}\right)^{2}} d t $$ [Hint: Use the relationships \(x=r \cos \theta, y=r \sin \theta .]\)

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