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Describe the graph of the equation. $$ \mathbf{r}=-3 \mathbf{i}+\left(1-t^{2}\right) \mathbf{j}+t \mathbf{k} $$

Short Answer

Expert verified
The graph is a parabolic curve on the vertical plane \( x = -3 \) opening downwards in the yz-plane.

Step by step solution

01

Identify the Parametric Equation

The given equation is a vector valued function: \( \mathbf{r} = -3 \mathbf{i} + (1 - t^2) \mathbf{j} + t \mathbf{k} \). This describes the position of a point \( (x, y, z) \) in 3D space as a function of \( t \).
02

Express as Coordinates

Identify the coordinates: \( x = -3 \), \( y = 1 - t^2 \), and \( z = t \). These represent the path of the point as \( t \) varies.
03

Recognize the Fixed Component

Observe that \( x = -3 \) is a constant, meaning that the graph is confined to the plane where \( x \) is always \(-3\).
04

Analyze the Form of (y, z)

Consider the relationship between \( y \) and \( z \). Since \( y = 1 - z^2 \) because \( z = t \) and \( y = 1 - t^2 \), the pair \( (y, z) \) traces a parabola in the \( yz \)-plane.
05

Describe the Graph in Space

Since \( x \) is fixed and \( (y, z) \) trace a parabola, the graph is a parabolic curve on the vertical plane \( x = -3 \). The parabola opens downwards along the \( y \)-axis as \( z \) increases or decreases.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Parametric Equation
In mathematics, a parametric equation uses parameters to define a set of related mathematical equations. Here, each variable is expressed as a function of one or more independent parameters. This is particularly useful in describing curves in space or on a plane.
In the context of vector valued functions, we represent our curve through a parametric form that describes the position of a point in terms of a parameter, typically denoted by \( t \). For our given equation \( \mathbf{r} = -3 \mathbf{i} + (1 - t^2) \mathbf{j} + t \mathbf{k} \), each component can be understood as:
  • \( x = -3 \): a constant value for the \( x \)-coordinate.
  • \( y = 1 - t^2 \): a changing \( y \)-coordinate depending on \( t \).
  • \( z = t \): the \( z \)-coordinate directly controlled by \( t \).
This parametric form allows us to visualize how a point moves through 3D space as \( t \) varies, producing what is known as a parametric curve. Such descriptions are fundamental in physics and engineering for describing motion and paths of objects.
3D Space
3D space, short for three-dimensional space, refers to the geometric setting in which three values (coordinates) determine the position of an element, such as a point. This consists of three axes usually labeled as \( x \), \( y \), and \( z \).
The concept of 3D space is vital to understanding how objects and shapes are positioned and oriented in our physical world. For a vector valued function like \( \mathbf{r} = -3 \mathbf{i} + (1 - t^2) \mathbf{j} + t \mathbf{k} \), it shows us how a point's position changes in this space horizontally along the \( x \)-axis, vertically along the \( y \)-axis, and depth-wise along the \( z \)-axis.
  • The \( x \)-coordinate stays constant, representing a vertical plane where \( x = -3 \).
  • The \( y \) and \( z \) coordinates demonstrate changes as functions of the parameter \( t \).
Understanding 3D space is crucial to visualize and interpret the geometrical arrangement of points, lines, and shapes, especially when considering problems involving movement and trajectories.
Parabola in yz-plane
A parabola is a symmetric curve defined by a quadratic function, commonly found in mathematics. When focusing on the \( yz \)-plane, we consider a 2D vertical plane parallel to both the \( y \)- and \( z \)-axes.
In the provided equation \( \mathbf{r} = -3 \mathbf{i} + (1 - t^2) \mathbf{j} + t \mathbf{k} \), observing the relationship between \( y \) and \( z \) helps describe the shape. Since \( y = 1 - z^2 \) when \( z = t \), we see a parabolic curve formed within the \( yz \)-plane. Important characteristics include:
  • Vertex at the point \( (y, z) = (1, 0) \).
  • Opens downwards, as indicated by the negative coefficient of \( z^2 \).
  • Symmetry along the \( z \)-axis where \( z = 0 \).
This parabola is restricted to the plane \( x = -3 \), resulting in a cylindrical parabolic form in 3D space. Understanding such curves is useful in various fields, including physics, where parabolic paths describe projectile motion under uniform gravity, and computer graphics for rendering authentic trajectories and shapes.

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Most popular questions from this chapter

Consider the various forces that a passenger in a car would sense while traveling over the crest of a hill or around a curve. Relate these sensations to the tangential and normal vector components of the acceleration vector for the car's motion. Discuss how speeding up or slowing down (e.g., doubling or halving the car's speed) affects these components.

(a) Sketch the graph of \(\mathbf{r}(t)=t \mathbf{i}+t^{2} \mathbf{j}\). Show that \(\mathbf{r}(t)\) is a smooth vector-valued function but the change of parameter \(t=\tau^{3}\) produces a vector-valued function that is not smooth, yet has the same graph as \(\mathbf{r}(t) .\) (b) Examine how the two vector-valued functions are traced, and see if you can explain what causes the problem.

Suppose that the position vector of a particle moving in the plane is \(\mathbf{r}=12 \sqrt{t} \mathbf{i}+t^{3 / 2} \mathbf{j}, t>0 .\) Find the minimum speed of the particle and its location when it has this speed.

Show that in cylindrical coordinates a curve given by the parametric equations \(r=r(t), \theta=\theta(t), z=z(t)\) for \(a \leq t \leq b\) has arc length $$ L=\int_{a}^{b} \sqrt{\left(\frac{d r}{d t}\right)^{2}+r^{2}\left(\frac{d \theta}{d t}\right)^{2}+\left(\frac{d z}{d t}\right)^{2}} d t $$ [Hint: Use the relationships \(x=r \cos \theta, y=r \sin \theta .]\)

In these exercises \(\mathbf{v}\) and a are given at a certain instant of time. Find \(a_{T}, a_{N}, \mathbf{T},\) and \(\mathbf{N}\) at this instant. $$ \mathbf{v}=-4 \mathbf{j}, \quad \mathbf{a}=2 \mathbf{i}+3 \mathbf{j} $$

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