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A vector \(\mathbf{w}\) is said to be a linear combination of the vectors \(\mathbf{v}_{1}\) and \(\mathbf{v}_{2}\) if \(\mathbf{w}\) can be expressed as \(\mathbf{w}=c_{1} \mathbf{v}_{1}+c_{2} \mathbf{v}_{2},\) where \(c_{1}\) and \(c_{2}\) are scalars. (a) Find scalars \(c_{1}\) and \(c_{2}\) to express the vector \(4 \mathrm{j}\) as a linear combination of the vectors \(\mathrm{v}_{1}=2 \mathrm{i}-\mathrm{j}\) and \(\mathrm{v}_{2}=4 \mathrm{i}+2 \mathrm{j}\). (b) Show that the vector \((3,5)\) cannot be expressed as a linear combination of the vectors \(\mathrm{v}_{1}=\langle 1,-3\rangle\) and \(\mathrm{v}_{2}=\langle- 2,6\rangle\)

Short Answer

Expert verified
(a) \(c_{1} = -2\), \(c_{2} = 1\). (b) Cannot be expressed as a linear combination.

Step by step solution

01

Identify and Set up the Equation for Part (a)

To express the vector \( 4\mathbf{j} \) as a linear combination of \( \mathbf{v}_{1} = 2 \mathbf{i} - \mathbf{j} \) and \( \mathbf{v}_{2} = 4 \mathbf{i} + 2 \mathbf{j} \), we must find scalars \( c_{1} \) and \( c_{2} \) such that:\[ 4 \mathbf{j} = c_{1}(2 \mathbf{i} - \mathbf{j}) + c_{2}(4 \mathbf{i} + 2 \mathbf{j}) \]Therefore, the problem becomes solving:\[ 0 = 2c_{1} + 4c_{2} \] (for the \( \mathbf{i} \) component) \[ 4 = -c_{1} + 2c_{2} \] (for the \( \mathbf{j} \) component).
02

Solve the System of Equations for Part (a)

The system of equations is:1. \( 0 = 2c_{1} + 4c_{2} \) 2. \( 4 = -c_{1} + 2c_{2} \).From equation 1, solve for one of the variables, say \( c_{1} \):\[ 2c_{1} + 4c_{2} = 0 \] implies \[ c_{1} = -2c_{2} \]. Substitute \( c_{1} = -2c_{2} \) into equation 2:\[ 4 = -(-2c_{2}) + 2c_{2} = 2c_{2} + 2c_{2} \]\[ 4 = 4c_{2} \]\[ c_{2} = 1 \]. Substitute \( c_{2} = 1 \) back into \( c_{1} = -2c_{2} \):\[ c_{1} = -2 \times 1 = -2 \].
03

Interpretation for Part (a)

The scalars are \( c_{1} = -2 \) and \( c_{2} = 1 \). Thus, \( 4 \mathbf{j} \) can be written as a combination of the vectors by:\[ 4 \mathbf{j} = -2(2 \mathbf{i} - \mathbf{j}) + 1(4 \mathbf{i} + 2 \mathbf{j}) \].
04

Set up the Equation for Part (b)

To determine if the vector \((3,5)\) can be expressed as a linear combination of \(\mathbf{v}_{1}=\langle 1,-3\rangle\) and \(\mathbf{v}_{2}=\langle -2,6\rangle\), we assume there exist \(c_{1}\) and \(c_{2}\) such that:\[ (3,5) = c_{1}(1,-3) + c_{2}(-2,6) \]. This gives us the system of equations:\[ 3 = c_{1} - 2c_{2} \]\[ 5 = -3c_{1} + 6c_{2} \].
05

Analyze the System of Equations for Part (b)

The system of equations is:1. \( 3 = c_{1} - 2c_{2} \) 2. \( 5 = -3c_{1} + 6c_{2} \).Notice that equation 2 can be rewritten as:\[ 5 = -3(c_{1} - 2c_{2}) \]Rearrange equation 1: \( c_{1} - 2c_{2} = 3 \), thus we substitute:\[ 5 = -3 \times 3 = -9 \], which is a contradiction since \( 5 eq -9 \).
06

Conclusion for Part (b)

The contradiction shows that no scalars \( c_{1} \) and \( c_{2} \) exist such that \( (3,5) \) can be formed from \( \mathbf{v}_{1} \) and \( \mathbf{v}_{2} \). Thus, \((3,5)\) cannot be expressed as a linear combination of these vectors.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vector Spaces
In mathematics, a vector space is a collection of objects called vectors, which can be added together and multiplied (scaled) by numbers, known as scalars. Scalars in this context are typically real numbers.

Vectors in a vector space can be visualized as arrows pointing in a particular direction, each with its own magnitude (length). For example, a vector in the plane could be represented by components along the x and y-axis, such as \( \mathbf{v} = (x, y) \).

A key property of vector spaces is that they must satisfy certain axioms, such as closure under addition and scalar multiplication.
  • Closure under addition: If you take any two vectors in the space and add them together, the result is still a vector in that space.
  • Closure under scalar multiplication: If you multiply any vector by a scalar, the result is also a vector in the space.
When vectors are said to be a linear combination within a vector space, it implies one vector can be constructed through the addition of other vectors multiplied by scalars. This is crucial because it defines how vectors relate and combine within the vector space. Determining linear combinations helps us understand the structure of the space and can solve problems like representing directions and forces in physics.
System of Equations
A system of equations is a set of two or more equations that you deal with all together at once. When expressing a linear combination, you usually need to solve a system of equations to find the specific scalars needed.

Let's consider the example where we found scalars \( c_1 \) and \( c_2 \) to define a vector \( 4\mathbf{j} \) as a linear combination. This involved setting up equations based on the vector components.
  • The first equation is based on the \( \mathbf{i} \) components of the vectors: \( 0 = 2c_{1} + 4c_{2} \).
  • The second equation is based on the \( \mathbf{j} \) components: \( 4 = -c_{1} + 2c_{2} \).
By solving these equations simultaneously, you find the scalars that make the linear combination possible. This is a technique often used in algebra to find unknown variables that satisfy more than one condition. In this case, each equation represents a condition that the vectors must meet to express your target vector as a linear combination, illustrating their independence and relation within a space.
Scalars in Algebra
Scalars are real numbers that appear in linear combinations, acting as multipliers for vectors. When you multiply a vector by a scalar, you're essentially stretching or compressing its length by that scalar's magnitude while maintaining the direction.

In algebra, scalars play a crucial role in manipulating equations and expressions, especially within vector spaces. In the given exercise, two scalars \( c_1 \) and \( c_2 \) are utilized to modify the vectors \( \mathbf{v}_1 \) and \( \mathbf{v}_2 \) so they combine to form another vector \( \mathbf{w} \).
  • By adjusting these scalars, you can see how varying their values affects the magnitude and direction of resulting vectors.
  • When referring to a compatibility issue, as shown in the failed linear combination of \( (3,5) \), it's because there's no set of scalars that satisfy both equations in the system for those specific vectors.
Understanding scalars and their relationship with vectors is vital for solving equations and discovering whether a vector lies within a span in a vector space. When used appropriately, scalars allow for the translation and transformation of vectors, helping to solve practical and theoretical problems in areas such as physics and engineering.

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Most popular questions from this chapter

A vector w is a linear combination of the vectors \(\mathbf{v}_{1}, \mathbf{v}_{2},\) and \(\mathbf{v}_{3}\) if \(\mathbf{w}\) can be expressed as \(\mathbf{w}=c_{1} \mathbf{v}_{1}+c_{2} \mathbf{v}_{2}+c_{3} \mathbf{v}_{3},\) where \(c_{1}, c_{2},\) and \(c_{3}\) are scalars. (a) Find scalars \(c_{1}, c_{2},\) and \(c_{3}\) to express \(\langle- 1,1,5\rangle\) as a linear combination of \(\mathbf{v}_{1}=\langle 1,0,1\rangle, \mathbf{v}_{2}=\langle 3,2,0\rangle,\) and \(\mathbf{v}_{3}=\langle 0,1,1\rangle\) (b) Show that the vector \(2 \mathbf{i}+\mathbf{j}-\mathbf{k}\) cannot be expressed as a linear combination of \(\mathbf{v}_{1}=\mathbf{i}-\mathbf{j}, \mathbf{v}_{2}=3 \mathbf{i}+\mathbf{k},\) and \(\mathbf{v}_{3}=4 \mathbf{i}-\mathbf{j}+\mathbf{k} .\)k} .$

Show that the line \(x=-1+t, y=3+2 t, z=-t\) and the plane \(2 x-2 y-2 z+3=0\) are parallel, and find the distance between them.

Describe the region in 3-space that satisfies the given inequalities. $$ 1 \leq \rho \leq 3 $$

Two bugs are walking along lines in 3 -space. At time \(t\) bug 1 is at the point \((x, y, z)\) on the line $$ x=4-t, \quad y=1+2 t, \quad z=2+t $$ and at the same time \(t\) bug 2 is at the point \((x, y, z)\) on the line $$ x=t, \quad y=1+t, \quad z=1+2 t $$ Assume that distance is in centimeters and that time is in minutes. (a) Find the distance between the bugs at time \(t=0\). (b) Use a graphing utility to graph the distance between the bugs as a function of time from \(t=0\) to \(t=5\). (c) What does the graph tell you about the distance between the bugs? (d) How close do the bugs get?

Let \(L_{1}\) and \(L_{2}\) be the lines whose parametric equations are $$ \begin{array}{ll}{L_{1}: x=4 t,} & {y=1-2 t, \quad z=2+2 t} \\ {L_{2}: x=1+t,} & {y=1-t, \quad z=-1+4 t}\end{array} $$ (a) Show that \(L_{1}\) and \(L_{2}\) intersect at the point \((2,0,3) .\) (b) Find, to the nearest degree, the acute angle between \(L_{1}\) and \(L_{2}\) at their intersection. (c) Find parametric equations for the line that is perpendicular to \(L_{1}\) and \(L_{2}\) and passes through their point of intersection.

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