Chapter 11: Problem 38
An equation of a surface is given in rectangular coordinates. Find an equation of the surface in (a) cylindrical coordinates and (b) spherical coordinates. $$ z=\sqrt{3 x^{2}+3 y^{2}} $$
Short Answer
Expert verified
Cylindrical: \(z = \sqrt{3}r\); Spherical: \(\cos \phi = \sqrt{3}\sin \phi\).
Step by step solution
01
Understanding the Problem
We need to convert a surface equation from rectangular coordinates to both cylindrical and spherical coordinates. Our given equation is \(z = \sqrt{3x^2 + 3y^2}\). First, identify that this is a surface equation containing \(x\), \(y\), and \(z\).
02
Convert to Cylindrical Coordinates
In cylindrical coordinates, we have the relationships: \(x = r\cos \theta\), \(y = r\sin \theta\), and \(z = z\). Substituting these into the equation, \(z = \sqrt{3(r\cos \theta)^2 + 3(r\sin \theta)^2}\) becomes \(z = \sqrt{3r^2(cos^2 \theta + sin^2 \theta)}\). Using the Pythagorean identity \(cos^2 \theta + sin^2 \theta = 1\), the equation simplifies to \(z = \sqrt{3r^2}\). So, the cylindrical form is \(z = \sqrt{3}r\).
03
Convert to Spherical Coordinates
In spherical coordinates, \(x = \rho\sin \phi\cos \theta\), \(y = \rho\sin \phi\sin \theta\), and \(z = \rho\cos \phi\). Substitute these into the given equation: \(\rho\cos \phi = \sqrt{3(\rho\sin \phi\cos \theta)^2 + 3(\rho\sin \phi\sin \theta)^2}\). This simplifies to \(\rho\cos \phi = \sqrt{3\rho^2\sin^2 \phi (cos^2 \theta + sin^2 \theta)}\), which further simplifies to \(\rho\cos \phi = \sqrt{3\rho^2\sin^2 \phi}\). Simplifying, we have \(\rho\cos \phi = \sqrt{3}\rho\sin \phi\). Divide both sides by \(\rho\) (assuming \(\rho eq 0\)): \(\cos \phi = \sqrt{3}\sin \phi\).
04
Final Equations in New Coordinates
Now we summarize the findings:- The equation of the surface in **cylindrical coordinates** is \(z = \sqrt{3}r\).- The equation of the surface in **spherical coordinates** is \(\cos \phi = \sqrt{3}\sin \phi\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cylindrical Coordinates
Cylindrical coordinates provide a straightforward way to describe points in 3D space by extending polar coordinates with a height component. Instead of moving around and across flat planes like in polar or rectangular coordinates, you use cylindrical coordinates which add depth by introducing a new dimension, often height or depth.
- The cylindrical system allows you to describe any point using three values: the radial distance from the origin (\(r\)), the angular position around the origin (\(\theta\)), and the height above or below the plane (\(z\)).
- It's especially useful for scenarios where symmetry around an axis (like a cylinder) makes its parameters more intuitive.
Spherical Coordinates
Moving into spherical coordinates adds another layer of complexity and flexibility, as they describe a point in 3D space using a radial component, and two angles. This is ideal for scenarios involving spheres or concentric layers.
- Spherical coordinates consist of three values: the radius (\(\rho\)), which is the distance from a point to the origin, the polar angle (\(\phi\)), which is the angle from the zenith direction, and the azimuthal angle (\(\theta\)), similar to that in polar coordinates.
- This way, any point can be located with precision by referencing the center of a sphere.
Rectangular Coordinates
Rectangular or Cartesian coordinates are the most familiar coordinate system, where every point in space is represented by an (\(x,y,z\)) triplet. Each value represents a linear distance from the origin along perpendicular axes.
- While rectangular coordinates are straightforward and ideal for describing grids, planes, and aligned elements in space, they might not always provide the simplest expressions for surfaces involving rotation or symmetry.
- They work best when you're dealing with straightforward, axis-aligned shapes, thanks to their perpendicular nature.