Chapter 11: Problem 23
Find the vectors that satisfy the stated conditions. (a) Oppositely directed to \(\mathbf{v}=\langle 3,-4\rangle\) and half the length of \(\mathbf{v} .\) (b) Length \(\sqrt{17}\) and same direction as \(\mathbf{v}=\langle 7,0,-6\rangle\)
Short Answer
Expert verified
(a) \(\langle -1.5, 2 \rangle\), (b) \(\frac{\sqrt{17}}{\sqrt{85}} \langle 7, 0, -6 \rangle\)
Step by step solution
01
Understand the Direction of the Vector
For part (a), interpret 'oppositely directed' as meaning the vector is in the exact opposite direction as \(\mathbf{v}\). This involves reversing the direction of the vector \(\mathbf{v} = \langle 3, -4 \rangle\) to \(-\mathbf{v} = \langle -3, 4 \rangle\).
02
Calculate the Magnitude
Determine the length of the vector \(\mathbf{v} = \langle 3, -4 \rangle\). Use the formula for the magnitude of a vector: \(||\mathbf{v}|| = \sqrt{3^2 + (-4)^2} = \sqrt{9 + 16} = \sqrt{25} = 5\).
03
Adjust for Half Length
To find a vector that is half the length of the original in the opposite direction, the magnitude should be \(\frac{5}{2} = 2.5\). Scale \(-\mathbf{v}\) to have this magnitude: find \(\mathbf{w}\) such that \(\mathbf{w} = \frac{1}{2}\langle -3, 4 \rangle\). This gives \(\mathbf{w} = \langle -1.5, 2 \rangle\).
04
Understand the Direction for Same Direction
For part (b), we need a vector in the same direction as \(\mathbf{v} = \langle 7, 0, -6 \rangle\). It means the proportional direction vector should be \(\frac{\mathbf{v}}{||\mathbf{v}||}\).
05
Calculate the Required Magnitude
The target magnitude for the vector in part (b) is given as \(\sqrt{17}\). First, calculate the current magnitude: \(||\mathbf{v}|| = \sqrt{7^2 + 0^2 + (-6)^2} = \sqrt{49 + 36} = \sqrt{85}\).
06
Scale the Vector to the Target Magnitude
To have the same direction and achieve the desired magnitude, scale the unit vector formed from \(\mathbf{v}\). The appropriate scaling factor is \(\frac{\sqrt{17}}{\sqrt{85}}\). Thus, the desired vector is \(\frac{\sqrt{17}}{\sqrt{85}} \langle 7, 0, -6 \rangle\).
07
Final Result
The vector for part (a) is \(\mathbf{w} = \langle -1.5, 2 \rangle\), and for part (b), it is \(\mathbf{u} = \frac{\sqrt{17}}{\sqrt{85}} \langle 7, 0, -6 \rangle\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vector Magnitude
The magnitude of a vector is like its size or length. Think of it as the distance from the start point of the vector to its tip. For a vector in two dimensions, such as \(\mathbf{v} = \langle 3, -4 \rangle\), the magnitude can be found using the Pythagorean theorem. You simply take the square root of the sum of the squares of its components. So here, \[||\mathbf{v}|| = \sqrt{3^2 + (-4)^2} = \sqrt{9 + 16} = \sqrt{25} = 5\]This indicates that the vector \(\mathbf{v}\) has a length of 5 units.
For three-dimensional vectors like \(\mathbf{v} = \langle 7, 0, -6 \rangle\), the process is similar, you just include the third component: \[||\mathbf{v}|| = \sqrt{7^2 + 0^2 + (-6)^2} = \sqrt{49 + 0 + 36} = \sqrt{85}\]
The magnitude is a crucial property as it describes how long the vector is, which is often used to scale or compare vectors.
For three-dimensional vectors like \(\mathbf{v} = \langle 7, 0, -6 \rangle\), the process is similar, you just include the third component: \[||\mathbf{v}|| = \sqrt{7^2 + 0^2 + (-6)^2} = \sqrt{49 + 0 + 36} = \sqrt{85}\]
The magnitude is a crucial property as it describes how long the vector is, which is often used to scale or compare vectors.
Vector Direction
The direction of a vector indicates where it points. For instance, when you change a vector to its opposite direction, you are essentially flipping the signs of all its components.
For example, if \(\mathbf{v} = \langle 3, -4 \rangle\), the opposite vector is \(-\mathbf{v} = \langle -3, 4 \rangle\). This doesn't change the vector's magnitude, only its direction.
Similarly, if you're asked for a vector that has the same direction as \(\mathbf{v} = \langle 7, 0, -6 \rangle\), you want a vector that points in that same way. For this, you can find a unit vector — a vector with the same direction but magnitude of 1. You achieve this by dividing each component by the vector's magnitude:\[\text{Unit Vector} = \frac{\mathbf{v}}{||\mathbf{v}||}\]This scaling process will maintain the direction of the original vector.
For example, if \(\mathbf{v} = \langle 3, -4 \rangle\), the opposite vector is \(-\mathbf{v} = \langle -3, 4 \rangle\). This doesn't change the vector's magnitude, only its direction.
Similarly, if you're asked for a vector that has the same direction as \(\mathbf{v} = \langle 7, 0, -6 \rangle\), you want a vector that points in that same way. For this, you can find a unit vector — a vector with the same direction but magnitude of 1. You achieve this by dividing each component by the vector's magnitude:\[\text{Unit Vector} = \frac{\mathbf{v}}{||\mathbf{v}||}\]This scaling process will maintain the direction of the original vector.
Vector Scaling
Vector scaling involves changing the magnitude of a vector while maintaining its direction. If you think of a vector being resized, that's scaling. For example, if we have \(\mathbf{v} = \langle 3, -4 \rangle\) and we need a vector half its length but in the opposite direction, we first find the opposite vector \(-\mathbf{v} = \langle -3, 4 \rangle\).
Then, multiply the vector by a factor that adjusts its magnitude to half: \[\mathbf{w} = \frac{1}{2} \langle -3, 4 \rangle = \langle -1.5, 2 \rangle\]This new vector \(\mathbf{w}\) is half the length of the original and travels in the opposite direction.
Similarly, for a vector in the same direction as another but with a specific new length, like \(\mathbf{u} = \frac{\sqrt{17}}{\sqrt{85}} \langle 7, 0, -6 \rangle\)\, the scaling factor \(\frac{\sqrt{17}}{\sqrt{85}}\) changes its magnitude, keeping the direction constant. By scaling a vector, we can effectively control its size while still pointing in the intended direction.
Then, multiply the vector by a factor that adjusts its magnitude to half: \[\mathbf{w} = \frac{1}{2} \langle -3, 4 \rangle = \langle -1.5, 2 \rangle\]This new vector \(\mathbf{w}\) is half the length of the original and travels in the opposite direction.
Similarly, for a vector in the same direction as another but with a specific new length, like \(\mathbf{u} = \frac{\sqrt{17}}{\sqrt{85}} \langle 7, 0, -6 \rangle\)\, the scaling factor \(\frac{\sqrt{17}}{\sqrt{85}}\) changes its magnitude, keeping the direction constant. By scaling a vector, we can effectively control its size while still pointing in the intended direction.