Chapter 11: Problem 15
Find the direction cosines of v and confirm that they satisfy Equation (5). Then use the direction cosines to approximate the direction angles to the nearest degree. $$ \text { (a) } \mathbf{v}=\mathbf{i}+\mathbf{j}-\mathbf{k} \quad \text { (b) } \mathbf{v}=2 \mathbf{i}-2 \mathbf{j}+\mathbf{k} $$
Short Answer
Expert verified
(a) Direction angles: \(55^\circ, 55^\circ, 125^\circ\); (b) Direction angles: \(48^\circ, 132^\circ, 71^\circ\).
Step by step solution
01
Calculate Magnitude of Vector v for (a)
For the vector \( \mathbf{v} = \mathbf{i} + \mathbf{j} - \mathbf{k} \), calculate the magnitude \( |\mathbf{v}| \) using the formula: \( |\mathbf{v}| = \sqrt{i^2 + j^2 + k^2} \). Substitute the components: \( |\mathbf{v}| = \sqrt{1^2 + 1^2 + (-1)^2} = \sqrt{1 + 1 + 1} = \sqrt{3} \).
02
Compute Direction Cosines for (a)
The direction cosines \( (l, m, n) \) are given by \( l = \frac{1}{\sqrt{3}} \), \( m = \frac{1}{\sqrt{3}} \), and \( n = \frac{-1}{\sqrt{3}} \). These are derived from \( l = \frac{i}{|\mathbf{v}|} \), \( m = \frac{j}{|\mathbf{v}|} \), and \( n = \frac{k}{|\mathbf{v}|} \).
03
Confirm Equation (5) for (a)
Verify that \( l^2 + m^2 + n^2 = 1 \). Calculate: \( \left(\frac{1}{\sqrt{3}}\right)^2 + \left(\frac{1}{\sqrt{3}}\right)^2 + \left(\frac{-1}{\sqrt{3}}\right)^2 = \frac{1}{3} + \frac{1}{3} + \frac{1}{3} = 1 \). Hence, the direction cosines satisfy Equation (5).
04
Approximate Direction Angles for (a)
The direction angles \( \alpha, \beta, \gamma \) can be approximated as: \ \( \alpha = \cos^{-1}(l) \approx 55^ ext{o} \), \( \beta = \cos^{-1}(m) \approx 55^ ext{o} \), \( \gamma = \cos^{-1}(n) \approx 125^ ext{o} \).
05
Calculate Magnitude of Vector v for (b)
For the vector \( \mathbf{v} = 2\mathbf{i} - 2\mathbf{j} + \mathbf{k} \), calculate the magnitude \( |\mathbf{v}| \) with the formula: \( |\mathbf{v}| = \sqrt{(2)^2 + (-2)^2 + (1)^2} = \sqrt{4 + 4 + 1} = \sqrt{9} = 3 \).
06
Compute Direction Cosines for (b)
The direction cosines \( (l, m, n) \) are \( l = \frac{2}{3} \), \( m = \frac{-2}{3} \), and \( n = \frac{1}{3} \). These are found using \( l = \frac{2}{3} \), \( m = \frac{-2}{3} \), and \( n = \frac{1}{3} \) based on the components of \( \mathbf{v} \).
07
Confirm Equation (5) for (b)
Verify \( l^2 + m^2 + n^2 = 1 \). Calculate: \( \left(\frac{2}{3}\right)^2 + \left(\frac{-2}{3}\right)^2 + \left(\frac{1}{3}\right)^2 = \frac{4}{9} + \frac{4}{9} + \frac{1}{9} = 1 \). Therefore, the direction cosines satisfy Equation (5).
08
Approximate Direction Angles for (b)
The direction angles \( \alpha, \beta, \gamma \) can be approximated as: \( \alpha = \cos^{-1}(l) \approx 48^ ext{o} \), \( \beta = \cos^{-1}(m) \approx 132^ ext{o} \), \( \gamma = \cos^{-1}(n) \approx 71^ ext{o} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vector Magnitude
Vector magnitude refers to the length or size of a vector. It is calculated using the components of the vector itself. For example, in three-dimensional space, a vector \( \mathbf{v} = a\mathbf{i} + b\mathbf{j} + c\mathbf{k} \) has a magnitude given by:
In our example, for \( \mathbf{v} = \mathbf{i} + \mathbf{j} - \mathbf{k} \), the magnitude is \( \sqrt{1 + 1 + 1} = \sqrt{3} \). Similarly, for another vector \( \mathbf{v} = 2\mathbf{i} - 2\mathbf{j} + \mathbf{k} \), the magnitude is \( \sqrt{4 + 4 + 1} = 3 \). These magnitudes help in understanding and visualizing the size of vectors in the solutions.
- \( |\mathbf{v}| = \sqrt{a^2 + b^2 + c^2} \)
In our example, for \( \mathbf{v} = \mathbf{i} + \mathbf{j} - \mathbf{k} \), the magnitude is \( \sqrt{1 + 1 + 1} = \sqrt{3} \). Similarly, for another vector \( \mathbf{v} = 2\mathbf{i} - 2\mathbf{j} + \mathbf{k} \), the magnitude is \( \sqrt{4 + 4 + 1} = 3 \). These magnitudes help in understanding and visualizing the size of vectors in the solutions.
Direction Angles
Direction angles are the angles that a vector makes with the positive x, y, and z-axes. These angles, denoted by \( \alpha, \beta, \text{and} \gamma \), help in expressing the direction of the vector. To find these angles, one uses the direction cosines. The direction angles satisfy the equations:
This approximation helps provide a more intuitive sense of the vector's orientation in space.
- \( \alpha = \cos^{-1}(l) \)
- \( \beta = \cos^{-1}(m) \)
- \( \gamma = \cos^{-1}(n) \)
This approximation helps provide a more intuitive sense of the vector's orientation in space.
Equation (5)
Equation (5) is fundamental in the understanding of direction cosines of a vector. It states that the sum of the squares of the direction cosines should equal one. This is mathematically represented as:
For instance, for the vector \( \mathbf{v} = \mathbf{i} + \mathbf{j} - \mathbf{k} \), the calculation is \( \left( \frac{1}{\sqrt{3}} \right)^2 + \left( \frac{1}{\sqrt{3}} \right)^2 + \left( \frac{-1}{\sqrt{3}} \right)^2 = 1 \). Similarly, for \( \mathbf{v} = 2\mathbf{i} - 2\mathbf{j} + \mathbf{k} \), verify \( \left( \frac{2}{3} \right)^2 + \left( \frac{-2}{3} \right)^2 + \left( \frac{1}{3} \right)^2 = 1 \).
This equation confirms that direction cosines are calculated accurately, ensuring the representation of vector orientation is correct.
- \( l^2 + m^2 + n^2 = 1 \)
For instance, for the vector \( \mathbf{v} = \mathbf{i} + \mathbf{j} - \mathbf{k} \), the calculation is \( \left( \frac{1}{\sqrt{3}} \right)^2 + \left( \frac{1}{\sqrt{3}} \right)^2 + \left( \frac{-1}{\sqrt{3}} \right)^2 = 1 \). Similarly, for \( \mathbf{v} = 2\mathbf{i} - 2\mathbf{j} + \mathbf{k} \), verify \( \left( \frac{2}{3} \right)^2 + \left( \frac{-2}{3} \right)^2 + \left( \frac{1}{3} \right)^2 = 1 \).
This equation confirms that direction cosines are calculated accurately, ensuring the representation of vector orientation is correct.