Chapter 10: Problem 50
True–False Determine whether the statement is true or false. Explain your answer. The expression $$ \frac{1}{2} \int_{-\pi / 4}^{\pi / 4}(1-\sqrt{2} \cos \theta)^{2} d \theta $$ $$ \begin{array}{l}{\text { computes the area enclosed by the inner loop of the limaçon }} \\ {r=1-\sqrt{2} \cos \theta .}\end{array} $$
Short Answer
Step by step solution
Understanding the ³¢¾±³¾²¹Ã§´Ç²Ô
Determine Conditions for Inner Loop
Area Formulation for the Inner Loop
Compare to Given Integral
Final Judgment
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Polar Coordinates
- The angle \( \theta \) is usually measured in radians and can take any value, while the radius \( r \) is non-negative.
- Polar coordinates are particularly advantageous when dealing with curves like circles and spirals.
Integral Calculus
- The integral of the squared radius function, \( \int (r^2)d\theta \), calculates the area of sectors formed by the radius at small sections across \( \theta \).
- In the case of polar coordinates, the formula for area requires a factor of \( \frac{1}{2} \), since we're calculating the area of sectors.
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- If the magnitude of \( b \) is greater than that of \( a \), the limaçon graph will have an inner loop.
- When \( b = a \), it produces a cardioid shape, a special kind of limaçon.
- For \( a > b \), the limaçon forms a dimpled shape without an inner loop.
Area Computation
- The basic formula for area in polar coordinates is \( \frac{1}{2} \int r^2 d\theta \), which accounts for the radial segments covering the angle \( \theta \).
- To compute the area of the inner loop, you integrate over the angle interval where \( r < 0 \) and the loop is defined by the specific \( \theta \) values that meet this condition.
- Therefore, the task is to find the correct \( \theta\) interval where the loop is plotted, and apply the area formula over this interval specifically.