/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 43 Find the area of the region desc... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find the area of the region described. $$ \text { The region between the loops of the limaçon } r=\frac{1}{2}+\cos \theta $$

Short Answer

Expert verified
The area between the loops is found by evaluating the polar integral over the specified limits.

Step by step solution

01

Analyze the ³¢¾±³¾²¹Ã§´Ç²Ô

The limaçon is given by the equation \( r = \frac{1}{2} + \cos \theta \). This particular equation represents a limaçon with an inner loop since the coefficient of the \( \cos \theta \) term () is larger than that of the constant term \( \frac{1}{2} \).
02

Determine the Points of Intersection

To find the points where the curves intersect, solve for \( \theta \) when \( r = 0 \):\[ \frac{1}{2} + \cos \theta = 0 \]\[ \cos \theta = -\frac{1}{2} \]\( \theta = \frac{2\pi}{3} \text{ and } \theta = \frac{4\pi}{3} \) are the angles where this occurs.
03

Determine the Limits of Integration

The loop occurs between \( \theta = \frac{2\pi}{3} \) and \( \theta = \frac{4\pi}{3} \). The area between the loops is determined by integrating between these limits.
04

Integrate to Find the Area

To find the area between the loops of the limaçon, use the polar area formula:\[ A = \frac{1}{2} \int_{a}^{b} r^2 d\theta \]Substitute the expression for \( r \):\[ A = \frac{1}{2} \int_{\frac{2\pi}{3}}^{\frac{4\pi}{3}} \left( \frac{1}{2} + \cos \theta \right)^2 d\theta \]
05

Simplify the Integral and Calculate

Expand \( \left( \frac{1}{2} + \cos \theta \right)^2 \) and integrate:\[ \left( \frac{1}{2} + \cos \theta \right)^2 = \frac{1}{4} + \cos \theta + \cos^2 \theta \]Use the identity \( \cos^2 \theta = \frac{1 + \cos 2\theta}{2} \), then integrate term by term:\[ A = \frac{1}{2} \left( \int_{\frac{2\pi}{3}}^{\frac{4\pi}{3}} \left( \frac{1}{4} + \cos \theta + \frac{1}{2} + \frac{1}{2}\cos 2\theta \right) d\theta\right) \]Calculate the integral and simplify to find the area.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polar Coordinates
Understanding polar coordinates is key to grasping how certain curves and shapes can be represented in a plane. Unlike the Cartesian coordinate system, which uses \(x\) and \(y\) to denote points on a plane, polar coordinates rely on \(r\), the radial distance from the origin, and \(\theta\), the angle from the positive \(x\)-axis.

This system is particularly useful for representing curves like circles and spirals that radiate out from a central point. To find a point on the plane:
  • Determine the distance \(r\) from the origin.
  • Specify the angle \(\theta\) counterclockwise from the positive \(x\) axis.
This unique method simplifies working with curves in a circular manner, allowing easier computation of various geometric properties such as area, within a given range of angles.
³¢¾±³¾²¹Ã§´Ç²Ô
A limaçon is a distinctive type of curve that can have fascinating shapes, including loops, dimpled structures, and cardiod-like figures. The general equation of a limaçon in polar coordinates is given by \(r = a + b \, \cos \theta\) or \(r = a + b \, \sin \theta\). In this specific exercise, the curve is defined by \(r = \frac{1}{2} + \cos \theta\).

This equation is particularly intriguing because it describes a limaçon with an inner loop. The loop is formed when the absolute value of the coefficient of \(\cos \theta\) is greater than the constant term, \(\frac{1}{2}\) in this case. Such curves touch themselves at points marking these loops.

Visually, a limaçon with an inner loop can resemble a small oval nested inside a larger rounded shape. Identifying the points where these loops meet, as done when \(\theta\) satisfies \(\cos \theta = -\frac{1}{2}\), is essential for further calculations like finding areas or intersections.
Integration
Integration is a powerful mathematical tool used to calculate areas underneath curves, among other applications. When dealing with polar equations like the limaçon, the integration process accounts for the curve's unique radial and angular properties.

To determine the area of a region described by a polar curve, use the formula:
  • \(A = \frac{1}{2} \int_{a}^{b} r^2 \, d\theta\)
This method incorporates both the radial distance \(r\) and the change in angle \(d\theta\), integrating over the specified range of \(\theta\) values.

In this example, integrate \(r^2\) from \(\theta = \frac{2\pi}{3}\) to \(\theta = \frac{4\pi}{3}\). It involves expanding \(\left( \frac{1}{2} + \cos \theta \right)^2\), using trigonometric identities, and evaluating each component separately. The integrated result represents the total area between the loops of the limaçon, providing insight into the curvature's overall geometry.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Find an equation for the ellipse that satisfies the given conditions. (a) Center at \((0,0) ;\) major and minor axes along the coordinate axes; passes through \((3,2)\) and \((1,6) .\) (b) Foci \((2,1)\) and \((2,-3) ;\) major axis of length \(6 .\)

True–False Determine whether the statement is true or false. Explain your answer. $$ \begin{array}{l}{\text { The area of a sector with central angle } \theta \text { taken from a circle }} \\ {\text { of radius } r \text { is } \theta r^{2} .}\end{array} $$

Find a polar equation for the conic that has its focus at the pole and satisfies the stated conditions. Points are in polar coordinates and directrices in rectangular coordinates for simplicity. (In some cases there may be more than one conic that satisfies the conditions.) $$ \begin{array}{l}{\text { (a) Ellipse; ends of major axis }(2, \pi / 2) \text { and }(6,3 \pi / 2) .} \\ {\text { (b) Parabola; vertex }(2, \pi) .} \\\ {\text { (c) Hyperbola; } e=\sqrt{2} ; \text { vertex }(2,0)}\end{array} $$

Show that the graph of the given equation is a hyperbola. Find its foci, vertices, and asymptotes. $$17 x^{2}-312 x y+108 y^{2}-900=0$$

Find a polar equation for the conic that has its focus at the pole and satisfies the stated conditions. Points are in polar coordinates and directrices in rectangular coordinates for simplicity. (In some cases there may be more than one conic that satisfies the conditions.) $$ \begin{array}{l}{\text { (a) Ellipse; } e=\frac{3}{4} ; \text { directrix } x=2} \\ {\text { (b) Parabola; directrix } x=1 .} \\ {\text { (c) Hyperbola; } e=\frac{4}{3} ; \text { directrix } y=3}\end{array} $$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.