Chapter 10: Problem 27
Sketch the curve in polar coordinates. $$ r=3(1+\sin \theta) $$
Short Answer
Expert verified
The curve is a limaçon with an inner loop, made from \( r = 3(1+\sin\theta) \).
Step by step solution
01
Identify the Polar Equation Type
The given polar equation is of the form \( r = a (1 + ext{something}) \), which suggests that it might be a limaçon. The equation \( r = 3(1 + \sin\theta) \) indicates it's a limaçon with a sine component.
02
Determine Specific Features
For \( r = a(1 + \sin\theta) \), if \( a = 3 \), it suggests that the limaçon will have a loop because the coefficient of \( \sin\theta \) is smaller than \( a \) which is 3 in this case.
03
Identify Key Points
To find key points, substitute angles such as \( \theta = 0, \frac{\pi}{2}, \pi, \frac{3\pi}{2} \) into the equation. Calculate \( r \) for these angles:- \( \theta = 0, r = 3(1 + 0) = 3 \)- \( \theta = \frac{\pi}{2}, r = 3(1 + 1) = 6 \)- \( \theta = \pi, r = 3(1 - 0) = 3 \)- \( \theta = \frac{3\pi}{2}, r = 3(1 - 1) = 0 \)
04
Plot the Curve
Begin plotting the points in polar coordinates, marking each with the corresponding \( r \) values at the calculated \( \theta \). Start at \( (3, 0) \), move to \( (6, \frac{\pi}{2}) \), then to \( (3, \pi) \), and finally to \( (0, \frac{3\pi}{2}) \). Sketch the curve smoothly through these points, ensuring the inner loop is visible.
05
Complete the ³¢¾±³¾²¹Ã§´Ç²Ô Sketch
Finalize your sketch by connecting the dots in a smooth, continuous manner as polar curves require. Ensure that from \( \theta = 0 \) to \( 2\pi \), the pattern of the curve shows a loop visible inside the graph circle of the limaçon. The symmetry with respect to the vertical axis helps in confirming the accuracy.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
³¢¾±³¾²¹Ã§´Ç²Ô
A limaçon is a type of polar curve. It can be identified by its defining equation: \( r = a \, (1 + b \, ext{function} \, \theta) \). The equation may include either a sine or cosine term. This influences the curve's orientation relative to the pole, which is the origin in polar coordinates.
³¢¾±³¾²¹Ã§´Ç²Ôs come in various forms, including those with loops, ones that do not touch the pole, or limaçons that appear like a cardioid. These forms depend on the ratio of \( a \) to \( b \):
³¢¾±³¾²¹Ã§´Ç²Ôs come in various forms, including those with loops, ones that do not touch the pole, or limaçons that appear like a cardioid. These forms depend on the ratio of \( a \) to \( b \):
- If \( |b| < a \), the limaçon has an inner loop.
- If \( |b| = a \), the limaçon forms a cardioid shape.
- If \( |b| > a \), the curve is an ordinary limaçon without a loop.
Polar Equation
The polar equation is a way to represent curves in a two-dimensional plane using polar coordinates. Instead of using the typical \( x \) and \( y \) coordinates, polar equations use \( r \) (the radial distance from the origin) and \( \theta \) (the angle from the positive x-axis). This is beneficial when dealing with circular and spiral patterns.For understanding polar equations, it's important to note:
- \( r \) represents how far away a point is from the origin.
- \( \theta \) is measured in radians and indicates the direction.
Curve Sketching
Curve sketching in polar coordinates starts by understanding how \( r \) changes with \( \theta \). To sketch the curve from \( r = 3(1 + \sin \theta) \), we begin by finding crucial points. This involves substituting notable angles into the equation such as \( \theta = 0, \frac{\pi}{2}, \pi, \) and \( \frac{3\pi}{2} \). At these angles, \( r \) is calculated to determine the points:
- At \( \theta = 0 \), \( r = 3 \).
- At \( \theta = \frac{\pi}{2} \), \( r = 6 \).
- At \( \theta = \pi \), \( r = 3 \).
- At \( \theta = \frac{3\pi}{2} \), \( r = 0 \).
- Identify symmetry in the curve, as it might reflect over an axis.
- Recognize the loop caused by polar function properties.
- Seek to reflect smooth, continuous connections through the polar plane.