/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 18 Find the limits. $$ \lim _{x... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the limits. $$ \lim _{x \rightarrow+\infty} \sin \left(\frac{\pi x}{2-3 x}\right) $$

Short Answer

Expert verified
The limit is \( -\frac{\sqrt{3}}{2} \).

Step by step solution

01

Understand the Function's Behavior

The given function is \( \sin \left( \frac{\pi x}{2-3x} \right) \). Our goal is to evaluate its behavior as \( x \to +\infty \). Notice that the argument of the sine function is a rational function.
02

Analyze the Rational Function

Consider \( \frac{\pi x}{2-3x} \). As \( x \to +\infty \), the leading term in both the numerator and the denominator is \( x \), thus the expression simplifies to \( \frac{\pi x}{2-3x} \approx \frac{\pi}{-3} \cdot 1 \), due to the negative sign in front of \( 3x \).
03

Simplify the Expression

The simplified form of \( \frac{\pi x}{2-3x} \) as \( x \to +\infty \) becomes \( -\frac{\pi}{3} \). Therefore, the problem reduces to finding the limit of \( \sin \left(-\frac{\pi}{3}\right) \).
04

Calculate \( \sin \left(-\frac{\pi}{3}\right) \)

The sine function is periodic and continuous, hence the sine of a constant is simply the sine of that value. Therefore, \( \sin \left(-\frac{\pi}{3}\right) = -\sin \left(\frac{\pi}{3}\right) = -\frac{\sqrt{3}}{2} \).
05

Conclusion

Since the limit of the argument \( \frac{\pi x}{2-3x} \) converges to \( -\frac{\pi}{3} \) as \( x \to +\infty \), the overall limit of the function is \( -\frac{\sqrt{3}}{2} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rational Functions
A rational function is a tool that's often seen in calculus. It's a fraction where both the numerator and the denominator are polynomials. Understanding the behavior of rational functions is important. It helps in evaluating limits, especially as variables approach infinity.

Here's a quick example: Consider a rational function of the form \( f(x) = \frac{a_nx^n + \text{...}}{b_mx^m + \text{...}} \). When you're examining this function as \( x \to \infty \), the leading terms \( a_nx^n \) and \( b_mx^m \) dictate its behavior. These are the terms with the highest powers \( n \) and \( m \) of \( x \).
  • If \( n = m \), the limit of \( f(x) \) is the simplification of the leading coefficients \( a_n / b_m \).
  • If \( n > m \), the limit is typically infinity or negative infinity, depending on the sign.
  • If \( n < m \), the limit is usually zero.
For the exercise problem, the function \( \frac{\pi x}{2-3x} \) simplifies based on the dominant \(-3x\) term of the denominator when \( x \to \infty \). This makes the function approach \(-\frac{\pi}{3}\).
Sine Function
The sine function is a classic part of trigonometry, representing smooth periodic oscillations. It cycles through its pattern over a period of \(2\pi\). Its values range from -1 to 1, repeating regularly.
  • A peculiar property of the sine function is its periodicity, allowing for prediction of values far into its cycle. This periodicity helps determine the limit once the argument resolves to a constant value, like \(-\frac{\pi}{3} \) in this exercise.
  • The function is also odd, which means that \( \sin(-x) = -\sin(x) \). This feature is directly utilized when simplifying expressions like \( \sin(-\frac{\pi}{3})\).
  • Using the known values, \( \sin(\frac{\pi}{3}) = \frac{\sqrt{3}}{2} \), allows us to find \( \sin(-\frac{\pi}{3}) = -\frac{\sqrt{3}}{2} \).
This property is crucial for solving the exercise, to find the limit of the original sine function as \( x \to \infty \).
Asymptotic Analysis
Asymptotic analysis is a technique used to describe the behavior of functions as they approach infinity or some other boundary point. This concept is particularly useful in calculus when evaluating limits and understanding end-behavior of functions.

In our problem, conducting asymptotic analysis helps us recognize how the dominant term in the argument of the sine function simplifies to a constant.
  • Through this method, we follow the dominant terms \( \pi x \) and \(-3x\) in \( \frac{\pi x}{2-3x} \), which leads the expression to simplify. The less significant terms are dropped as they become negligible compared to the leading terms.
  • This mathematical simplification reduces the complexity of otherwise tough calculations. It allows focus on understanding the general behavior of the function as \( x \to \infty \).
Asymptotic analysis thus serves a significant role in effectively estimating limits and understanding functions' ultimate behavior with simplicity.

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