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Prove: (a) \(\sin ^{-1}(-x)=-\sin ^{-1} x\) (b) \(\tan ^{-1}(-x)=-\tan ^{-1} x\)

Short Answer

Expert verified
Both identities hold because sine and tangent are odd functions, thus \( \sin^{-1}(-x) = -\sin^{-1}(x) \) and \( \tan^{-1}(-x) = -\tan^{-1}(x) \).

Step by step solution

01

Understand the Inverse Sine Property

The function \( \sin^{-1} \) is the inverse of the sine function. By definition, \( \sin(\sin^{-1}(x)) = x \). We also know that sine is an odd function, which means \( \sin(-\theta) = -\sin(\theta) \). Using these properties, we can reason about \( \sin^{-1}(-x) \).
02

Use the Odd Function Property for Sine

Given that sine is an odd function, for \( y = \sin^{-1}(-x) \), it follows that \( \sin(y) = -x \). Since \( \sin^{-1}(-x) \) must give us an angle whose sine is \(-x\), we also realize that \( \sin(-y) = -\sin(y) \), leading to the conclusion that \( \sin^{-1}(-x) = -\sin^{-1}(x) \).
03

Prove Part (a) with an Example

Consider \( x \) within the range of \([-1, 1]\). For example, let \( x = \frac{1}{2} \). Then, \( \sin^{-1}(x) = \frac{\pi}{6} \). Following our proof, \( \sin^{-1}(-x) = \sin^{-1}(-\frac{1}{2}) = -\frac{\pi}{6} \), confirming that \( \sin^{-1}(-x) = -\sin^{-1}(x) \).
04

Understand the Inverse Tangent Property

The function \( \tan^{-1} \) is the inverse of the tangent function. By definition, \( \tan(\tan^{-1}(x)) = x \). Tangent, like sine, is also an odd function: \( \tan(-\theta) = -\tan(\theta) \).
05

Use the Odd Function Property for Tangent

If \( y = \tan^{-1}(-x) \), it follows that \( \tan(y) = -x \). This implies \( \tan(-y) = -\tan(y) \), leading us to conclude that \( \tan^{-1}(-x) = -\tan^{-1}(x) \).
06

Prove Part (b) with an Example

Consider \( x \) within the real numbers, for example, \( x = 1 \). Then, \( \tan^{-1}(x) = \frac{\pi}{4} \). For \( -x = -1 \), \( \tan^{-1}(-x) = \tan^{-1}(-1) = -\frac{\pi}{4} \), confirming that \( \tan^{-1}(-x) = -\tan^{-1}(x) \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Inverse Sine Function
The inverse sine function, denoted as \( \sin^{-1}(x) \), is used to find the angle whose sine is \( x \). This operation "undoes" the sine function, working within specific bounds. Specifically, the range of \( \sin^{-1}(x) \) is \([-\frac{\pi}{2}, \frac{\pi}{2}]\). This is because these are the angles in which sine covers all its possible output values from \(-1\) to \(1\).

Understanding \( \sin^{-1}(x) \) is crucial because it allows us to solve problems involving angles formed by opposite and adjacent sides of a triangle. The notation \( \sin^{-1} \) can sometimes be mistaken for a negative exponent, but it actually represents the inverse function, also known as arcsine. So, \( \sin^{-1}(-x) = -\sin^{-1}(x) \) uses the property of sine being an odd function.

In application, when we have an equation such as \( \sin(y) = -x \), the \( \sin^{-1} \) allows us to determine \( y \), the angle, would simply be \(-\sin^{-1}(x)\). This equation reflects the odd property of sine where \( \sin(-\theta) = -\sin(\theta) \). Therefore, \( \sin^{-1}(-x) \) is indeed \(-\sin^{-1}(x)\).
Inverse Tangent Function
The inverse tangent function, denoted \( \tan^{-1}(x) \), helps in finding the angle whose tangent is \( x \). This function is critical when solving problems where you need to determine the angle from the ratio of the opposite to the adjacent side of a right-angled triangle. The range for \( \tan^{-1}(x) \) is \((-\frac{\pi}{2}, \frac{\pi}{2})\). This ensures that each \( x \) value has a unique \( \theta \) making the inverse function well-defined.

Much like the inverse sine function, \( \tan^{-1} \) undoes the tangent function, but it's important to note that \( \tan^{-1} \) and \( \tan \) operate on different numeric domains because tangent can approach infinity. In trigonometry, the notation \( \tan^{-1} \) specifically indicates the inverse tangent, also known as arctangent, rather than reciprocal.

For practical uses, if \( \tan(y) = -x \), then \( y = \tan^{-1}(-x) \) will give you \(-\tan^{-1}(x)\). This once again uses the odd property of tangent, where \( \tan(-\theta) = -\tan(\theta) \), verifying our result that the inverse tangent of a negative is negative of the inverse tangent.
Odd Functions Property
The concept of odd functions is crucial when dealing with trigonometric identities and their transformations. An odd function is defined by the property \( f(-x) = -f(x) \). This property is visualized on a graph as symmetry about the origin. In simpler terms, if a function is odd, flipping the input value will mirror the result around the origin.

Both sine and tangent functions are classic examples of odd functions. Therefore, when working with inverse sine and tangent functions, this characteristic simplifies calculations. It means that the inverse function of a negative input is the negative of the inverse of the corresponding positive input.

This can be used practically to simplify calculations in trigonometry, physics, and engineering, where symmetry and other properties are necessary to reduce complexity in expressions or equations. For example, verifying the relationships such as \( \sin^{-1}(-x) = -\sin^{-1}(x) \) and \( \tan^{-1}(-x) = -\tan^{-1}(x) \) rely on this fundamental property, allowing us to streamline solving many real-world problems.

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