Chapter 7: Problem 50
Make a substitution to express the integrand as a rational function and then evaluate the integral. \( \displaystyle \int \frac{e^x}{(e^x - 2)(e^{2x} + 1)}\ dx \)
Short Answer
Expert verified
The integral evaluates to \( \frac{1}{5} \ln|e^x - 2| - \frac{1}{10} \ln|e^{2x} + 1| - \frac{2}{5} \arctan(e^x) + C \).
Step by step solution
01
Identify the Substitution
To simplify the integrand, let's first make a substitution. Notice that the expression inside the integral has terms involving \( e^x \). So, we will try the substitution \( u = e^x \). Then, \( du = e^x \, dx \), or \( dx = \frac{du}{u} \). We replace \( e^x \) with \( u \) in the integrand.
02
Substitute into the Integral
Substitute \( e^x \) with \( u \) and \( dx \) with \( \frac{du}{u} \) in the given integral:\[\int \frac{u}{(u - 2)(u^2 + 1)} \cdot \frac{du}{u}\]This simplifies the integral to:\[\int \frac{1}{(u - 2)(u^2 + 1)} \, du\].Now, the integrand is a rational function in terms of \( u \).
03
Partial Fraction Decomposition
We perform partial fraction decomposition on \( \frac{1}{(u - 2)(u^2 + 1)} \). Assume:\[\frac{1}{(u - 2)(u^2 + 1)} = \frac{A}{u - 2} + \frac{Bu + C}{u^2 + 1}.\]Multiply through by \((u - 2)(u^2 + 1)\) and equate coefficients to solve for \(A\), \(B\), and \(C\).
04
Solve for Coefficients
Setting up the equation from Step 3, we have:\[1 = A(u^2 + 1) + (Bu + C)(u - 2).\]Expand and equate coefficients:- Coefficient of \(u^2\): \( A + B = 0 \)- Coefficient of \(u\): \( -2B + C = 0 \)- Constant: \( A - 2C = 1 \).From these, solving gives \(A = \frac{1}{5}, B = -\frac{1}{5}, C = -\frac{2}{5}\).
05
Integrate Each Term Separately
Substitute the coefficients back into the partial fraction:\[\int \left( \frac{1/5}{u - 2} + \frac{(-1/5)u - 2/5}{u^2 + 1} \right) du.\]Separate the integral:\[\frac{1}{5} \int \frac{1}{u - 2} \, du + \int \frac{(-1/5)u - 2/5}{u^2 + 1} \, du.\]Integrate each term separately:
06
Evaluate the Integrals
The first integral is:\[\frac{1}{5} \ln|u - 2| + C_1.\]The second integral splits into two:\((1)\) \(-\frac{1}{5}\int \frac{u}{u^2 + 1} du\)\((2)\) \(-\frac{2}{5}\int \frac{1}{u^2 + 1} du\).Determine the integrals:- \( \int \frac{u}{u^2 + 1} du = \frac{1}{2} \ln|u^2 + 1| + C_2 \)- \( \int \frac{1}{u^2 + 1} du = \arctan(u) + C_3 \)Hence, the evaluated form with constants is combined as needed.
07
Substitute Back to Original Variable
Substitute \( u = e^x \) back into the integrals:\[\frac{1}{5} \ln|e^x - 2| - \frac{1}{10} \ln|e^{2x} + 1| - \frac{2}{5} \arctan(e^x) + C \].This result is the integral expressed in terms of \( x \).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Substitution Method
The substitution method is a powerful technique for simplifying integrals that involve composite functions. In the context of our problem, we identified the exponential function \( e^x \), which appears repeatedly in the integrand. By substituting \( u = e^x \), we transform a complex expression into a simpler one. This is because the derivative \( du = e^x \, dx \) or \( dx = \frac{du}{u} \), allows us to rewrite the integral entirely in terms of \( u \).
The substitution helps reduce the problem of integrating a complicated expression to a form that can be more easily managed. Once the substitution is made, the original integrand becomes a rational function, making further application of advanced techniques like partial fraction decomposition feasible.
Key points to remember about substitution:
The substitution helps reduce the problem of integrating a complicated expression to a form that can be more easily managed. Once the substitution is made, the original integrand becomes a rational function, making further application of advanced techniques like partial fraction decomposition feasible.
Key points to remember about substitution:
- Look for composite or repeated functions in the integrand.
- Choose a substitution that will simplify the derivative multiplication.
- Apply the substitution consistently throughout the integral.
Partial Fraction Decomposition
Once a rational function is obtained after substitution, partial fraction decomposition becomes useful. The technique involves expressing a complex rational function as a sum of simpler fractions. Here, our problem required decomposing \( \frac{1}{(u - 2)(u^2 + 1)} \). This decomposition allows for the separation of the integral into terms that are easier to integrate individually.
We assume the expression:
\( \frac{1}{(u - 2)(u^2 + 1)} = \frac{A}{u - 2} + \frac{Bu + C}{u^2 + 1} \).
By multiplying through by the common denominator, and then comparing coefficients, we solve for constants \( A, B, \text{and} C \). This is crucial for setting up integrals that match easily integrable forms.
Steps in partial fraction decomposition:
We assume the expression:
\( \frac{1}{(u - 2)(u^2 + 1)} = \frac{A}{u - 2} + \frac{Bu + C}{u^2 + 1} \).
By multiplying through by the common denominator, and then comparing coefficients, we solve for constants \( A, B, \text{and} C \). This is crucial for setting up integrals that match easily integrable forms.
Steps in partial fraction decomposition:
- Identify the degree of the numerator is less than the degree of the denominator, ensuring it's a proper fraction.
- Write the expression as a sum of fractions, each having simpler denominators.
- Multiply through by the original denominator and equate coefficients to find unknowns.
Rational Functions
Rational functions are fractions where the numerator and denominator are polynomials. They play a pivotal role in calculus, especially when solving integrals through techniques like substitution and partial fraction decomposition. In our example, the substitution \( u = e^x \) simplified the integrand, transforming it into a rational function \( \frac{1}{(u - 2)(u^2 + 1)} \).
Working with rational functions often involves looking for ways to express them in simpler forms using algebraic techniques. This can involve:
Working with rational functions often involves looking for ways to express them in simpler forms using algebraic techniques. This can involve:
- Simplifying expressions where possible.
- Identifying potential methods of integration such as by parts, or partial fractions.
- Recognizing special forms that yield specific integration results (e.g., logarithmic forms).
Exponential Functions
Exponential functions are characterized by their constant relative growth rate and are expressed in the form \( e^x \). In calculus, these functions often complicate integral calculations due to their non-algebraic nature. In our integration problem, the exponential function \( e^x \) could be an initial obstacle.
By employing the substitution \( u = e^x \), we exploit the derivative property \( e^x \) by transforming it into a more straightforward variable representation, thereby simplifying the integration process.
Key characteristics of exponential functions in integration:
By employing the substitution \( u = e^x \), we exploit the derivative property \( e^x \) by transforming it into a more straightforward variable representation, thereby simplifying the integration process.
Key characteristics of exponential functions in integration:
- They grow or decay at rates proportional to their current value.
- Substitutions can transform them into polynomial or simpler forms for easier integration.
- They have a unique property where the derivative of \( e^x \) is \( e^x \), maintaining form across calculations.