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Use the method of cylindrical shells to find the volume generated by rotating the region bounded by the given curves about the y-axis. \( y = 4x - x^2 \) , \( y = x \)

Short Answer

Expert verified
The volume is \(13.5\pi\).

Step by step solution

01

Identify the region of integration

First, find the points of intersection between the curves \( y = 4x - x^2 \) and \( y = x \). Set the equations equal to each other:\[ 4x - x^2 = x \]Rearrange to find the intersection points:\[ x^2 - 3x = 0 \]Factor the equation:\[ x(x - 3) = 0 \]Thus, the points of intersection occur at \( x = 0 \) and \( x = 3 \).
02

Set up the shell method formula

The formula for the volume using the method of cylindrical shells when rotating around the y-axis is:\[ V = 2\pi \, \int_{a}^{b} x \, (f(x) - g(x)) \, dx \]In this case, \( f(x) = 4x - x^2 \) and \( g(x) = x \), and the bounds are from \( x = 0 \) to \( x = 3 \).
03

Substitute and simplify the integrand

Substitute \( f(x) \) and \( g(x) \) into the shell method formula:\[ V = 2\pi \, \int_{0}^{3} x \, ((4x - x^2) - x) \, dx \]Simplify the integrand:\[ V = 2\pi \, \int_{0}^{3} x \, (3x - x^2) \, dx \]\[ V = 2\pi \, \int_{0}^{3} (3x^2 - x^3) \, dx \]
04

Integrate the function

Compute the integral:\( \int_{0}^{3} (3x^2 - x^3) \, dx = [x^3 - \frac{x^4}{4}]_{0}^{3} \)Evaluate the definite integral:\[ = \left[ 3 \cdot \frac{3^3}{3} - \frac{3^4}{4} \right] - \left[ 0 \right] \]\[ = (27 - 20.25) = 6.75 \]
05

Calculate the final volume

Multiply by \(2\pi\) to find the volume:\[ V = 2\pi \, \cdot 6.75 = 13.5\pi \]
06

Final conclusion

The volume of the solid formed by rotating the region bounded by the curves \( y = 4x - x^2 \) and \( y = x \) about the y-axis is \( 13.5\pi \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Volume of Revolution
When you rotate a two-dimensional shape about an axis, you create a three-dimensional solid. The concept known as "volume of revolution" helps in finding the volume of such solids. In the exercise, we are looking at the region between two curves. Upon revolving this region around the specified axis, we can determine the volume of the resulting solid.

For this particular problem, we use the method of cylindrical shells. This involves integrating with respect to one variable, allowing us to "stack" cylinder-shaped shells to build up the volume of the solid. The volume is ultimately determined by measuring how much space these rotated shells take up as they combine to create the final shape.

Using the cylindrical shell method is particularly useful when rotating about the y-axis, as it simplifies the calculations by creating cylindrical shells that are easy to integrate over when stacked together.
Intersection of Curves
Before we can find the volume of the revolution, we need to understand where the curves intersect. The intersection points mark the limits for the integration, setting the bounds for which the region is enclosed.

In the given exercise, to find the intersection points, we equate the two functions:
  • The equation for the first curve is: \( y = 4x - x^2 \)
  • The second curve is: \( y = x \)
Setting these equal, we solve:\[ 4x - x^2 = x \]Rearranging gives\[ x^2 - 3x = 0 \].Factoring this equation results in the solutions \( x = 0 \) and \( x = 3 \).

These points of intersection define the limits \((0, 3)\) over which we calculate the volume by integrating the area between these curves.
Definite Integral
The concept of a definite integral is fundamental when calculating volumes of revolution. A definite integral allows us to find the exact area under a curve, between two specific points. In this exercise, it helps in determining the "integral" part of the cylindrical shell method formula.

The given integral calculation is:\[ V = 2\pi \, \int_{0}^{3} (3x^2 - x^3) \, dx \]
By performing this integration, we calculate:\[\int_{0}^{3} (3x^2 - x^3) \, dx = [x^3 - \frac{x^4}{4}]_{0}^{3} \]
We find this definite integral by evaluating the antiderivative at the upper limit and subtracting the value of the antiderivative at the lower limit.

This exact value gives the "integral shell," or space each shell occupies, and establishes the groundwork to further complete the total volume calculation.
Rotate About the Y-axis
The action of rotating a region about the y-axis creates a solid of revolution. It can sometimes seem complex, but the visualization helps in understanding how the shells build up the entire solid.

Consider a typical point on your curve. When this point, along with others in its vicinity, is rotated around the y-axis, you generate a series of concentric cylindrical shells. Each shell is a cross-sectional part of this generated solid.

The height of each shell, which varies across the x-values due to the intersection of those curves, dictates the portion of volume contributed by each shell. The shell method formula incorporates all these measurements:\[ V = 2\pi \, \int_{a}^{b} x \, (f(x) - g(x)) \, dx \]Collectively integrating these shells from the intersection points results in the full shape, and thus, the overall volume.

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Most popular questions from this chapter

The Great Pyramid of King Khufu was built of limestone in Egypt over a 20-year time period from 2580 bc to 2560 BC. Its base is a square with side length 756 ft and its height when built was 481 ft. (It was the tallest man-made structure in the world for more than 3800 years.) The density of the limestone is about \( 150 lb/ft^3 \). (a) Estimate the total work done in building the pyramid. (b) If each laborer worked 10 hours a day for 20 years, for 340 days a year, and did 200 ft-lb/h of work in lifting the limestone blocks into place, about how many laborers were needed to construct the pyramid?

Find the volume of the described solid \( S \). The base of \( S \) is an elliptical region with boundary curve \( 9x^2 + 4y^2 = 36 \). Cross-sections perpendicular to the x-axis are isosceles right triangles with hypotenuse in the base.

(a) Set up an integral for the volume of a solid torus (the donut-shaped solid shown in the figure) with radii \( r \) and \( R \). (b) By interpreting the integral as an area, find the volume of the torus.

Show how to approximate the required work by a Riemann sum. Then express the work as an integral and evaluate it. A circular swimming pool has a diameter of 24 ft, the sides are 5 ft high, and the depth of the water is 4 ft. How much work is required to pump all of the water out over the side? (Use the fact that water weighs \( 62.5 lb/ft^3 \).)

The velocity \( v \) of blood that flows in a blood vessel with radius \( R \) and length \( l \) at a distance \( r \) from the central axis is $$ v(r) = \frac{P}{4\eta l} (R^2 - r^2) $$ where \( P \) is the pressure difference between the ends of the vessel and \( \eta \) is the viscosity of the blood (see Example 3.7.7). Find the average velocity (with respect to \( r \)) over the interval \( 0 \le r \le R \). Compare the average velocity with the maximum velocity.

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