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91Ó°ÊÓ

Sketch the region bounded by the paraboloids \( z = x^2 + y^2 \) and \( z = 2 - x^2 - y^2 \).

Short Answer

Expert verified
The region is a 3D shape bounded by the intersection of two paraboloids, with base the circle \( x^2 + y^2 = 1 \).

Step by step solution

01

Understand the Question

We need to sketch the region bounded by two paraboloids: \( z = x^2 + y^2 \) (an upward opening paraboloid) and \( z = 2 - x^2 - y^2 \) (a downward opening paraboloid). The region we need to sketch is where these two surfaces intersect or enclose a space in 3D.
02

Find Points of Intersection

To find where the two surfaces intersect, set the equations equal:\[ x^2 + y^2 = 2 - x^2 - y^2 \]Combine like terms:\[ 2x^2 + 2y^2 = 2 \]Simplifying:\[ x^2 + y^2 = 1 \]This equation represents a circle with radius 1 centered at the origin in the xy-plane.
03

Sketch the Projections

In the xy-plane, the intersection of the paraboloids is the circle \( x^2 + y^2 = 1 \). Sketch this circle, which is the projection of the intersecting region onto the base plane (z = 0).
04

Sketch the Paraboloids

The upward paraboloid \( z = x^2 + y^2 \) opens upwards with its vertex at (0, 0, 0). The downward paraboloid \( z = 2 - x^2 - y^2 \) has its vertex at (0, 0, 2) and opens downward. Sketch both surfaces, ensuring they are symmetric about the z-axis and intersect along the circle derived in Step 2.
05

Sketch the Intersection and Enclosed Region

Identify the region between the two surfaces. Above the circle in the xy-plane, the region is enclosed between the upward opening paraboloid \( z = x^2 + y^2 \) and the downward opening paraboloid \( z = 2 - x^2 - y^2 \). Shade this enclosed volume to complete the sketch.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Paraboloids
Paraboloids are a type of surface in three-dimensional geometry. They are quadratic surfaces that can open either upwards or downwards. A paraboloid is similar to the shape of a parabola, but instead of being in two dimensions, it extends into a third dimension. This creates a bowl-like shape. In this exercise, we have two paraboloids to consider:
  • The upward-opening paraboloid is given by the equation \( z = x^2 + y^2 \). Its vertex is at the origin (0,0,0), and it opens towards the positive z-axis.
  • The downward-opening paraboloid is described by \( z = 2 - x^2 - y^2 \). It has its vertex at (0,0,2), opening downwards towards the xy-plane.
Understanding these shapes' orientations and vertices helps us visualize their intersection in a 3D space.
Intersection
The intersection of two surfaces is the set of points they both share. To find where our two paraboloids intersect, we equate their respective equations: \( x^2 + y^2 = 2 - x^2 - y^2 \). Combining like terms, we get \( 2x^2 + 2y^2 = 2 \), which simplifies to \( x^2 + y^2 = 1 \).
This equation signifies a circle with a radius of 1, centered at the origin in the xy-plane. This circle represents the projection of the paraboloids' intersection in the base plane (z = 0). Identifying this intersection is crucial because it delineates where the two paraboloids meet and enclose space.
3D Sketching
Sketching in 3D can be tricky, but understanding the basics of 3D sketching is essential. We start by sketching the projection of the intersection on the xy-plane, which in this case, is the circle \( x^2 + y^2 = 1 \). This forms the boundary of the region we are interested in.
Next, we sketch the individual paraboloids based on their equations and orientations:
  • The upward paraboloid \( z = x^2 + y^2 \) opens upward from the origin.
  • The downward paraboloid \( z = 2 - x^2 - y^2 \) opens downward from (0,0,2).
By accurately sketching these surfaces, we can visually identify the volume enclosed between them, making the 3D concept more tangible.
Region Bounded
The region bounded by the two paraboloids is essentially the volume they enclose. Once we have identified the intersection as the circle \( x^2 + y^2 = 1 \), we focus on the space above this circle. This is where the two surfaces physically enclose a region. The upward paraboloid rises from the circle at the base, while the downward paraboloid descends to meet it.
The volume formed between these paraboloids showcases the beautiful intersection and boundary in 3D space. Shading or marking this area in sketches helps emphasize the region of interest, making the concept of bounded regions clearer.
Mathematics
At the heart of this exercise lies mathematics, which provides the foundation to explore and describe these complex surfaces. Using algebraic manipulation, we derived the intersection equation \( x^2 + y^2 = 1 \), which is crucial for further sketching and understanding of 3D objects.
Mathematics allows us to reconcile abstract shapes and concepts, like paraboloids, with practical visualization techniques such as 3D sketching. Equations aren't just numbers and variables; they tell a story about shapes, forms, and spaces in our environment. Emphasizing this fundamental aspect of mathematics can make it easier for students to grasp these concepts and apply them in solving similar problems.

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Most popular questions from this chapter

Find the lengths of the sides of the triangle \( PQR \). Is it a right triangle? Is it an isosceles triangle? \( P (3, -2, -3) \) , \( Q (7, 0, 1) \) , \( R (1, 2, 1) \)

Three forces act on an object. Two of the forces are at an angle of \( 100^\circ \) to each other and have magnitudes 25 N and 12 N. The third is perpendicular to the plane of these two forces and has magnitude 4 N. Calculate the magnitude of the force that would exactly counterbalance these three forces.

(a) Find the point at which the given lines intersect: $$ r = \langle 1, 1, 0 \rangle + t \langle 1, -1, 2 \rangle $$ $$ r = \langle 2, 0, 2 \rangle + s \langle -1, 1, 0 \rangle $$ (b) Find an equation of the plane that contains these lines.

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