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Solve the differential equation. $$(1+\tan y) y^{\prime}=x^{2}+1$$

Short Answer

Expert verified
Separate variables using substitution, then solve and back-substitute to find \( y(x) \).

Step by step solution

01

Identify the Type of Differential Equation

The given differential equation is \((1 + \tan y) y^{\prime} = x^2 + 1\). This is a first-order, non-linear differential equation.
02

Rearrange the Equation

Separate the variables by rearranging the equation as \(\frac{dy}{dx} = \frac{x^2 + 1}{1 + \tan y}\). This setup suggests using separation of variables, but direct separation is not possible. We will use substitution instead.
03

Apply Substitution

Let \( u = \tan y \), which implies \( \frac{du}{dy} = \sec^2 y \). Therefore, \( dy = \frac{du}{\sec^2 y} = \cos^2 y \, du\). Use the identity \( 1 + \tan^2 y = \sec^2 y \) to solve \( \cos^2 y = \frac{1}{1 + u^2} \).
04

Substitute into the Differential Equation

Substitute \( u = \tan y \) into the equation \( \frac{dy}{dx} = \frac{x^2 + 1}{1 + u} \frac{1}{1 + u^2}\). This simplifies the equation to \( \frac{du}{dx} = (x^2 + 1) \cdot (1 + u) \cdot \cos^2 y\), or \( \frac{du}{dx} = (x^2 + 1)(1 + u)(1 - u^2)\).
05

Solve the Transformed Equation

Separate the variables in \( \frac{du}{(1 + u)(1 - u^2)} = (x^2 + 1) \, dx \). Integrate both sides: the left side requires partial fractions and the right side is a straightforward polynomial integration.
06

Integrate Through Partial Fractions

Decompose \( \frac{1}{(1 + u)(1 - u^2)} \) using partial fractions, finding coefficients, and then integrate term-by-term. Integrating both sides gives the solution in terms of \( u \) and \( x \).
07

Back-substitution

After finding \( u(x) \), substitute back \( u = \tan y \) to solve for \( y(x) \). Use inverse trigonometric functions as necessary to express \( y \) explicitly in terms of \( x \).
08

Evaluate Integration Constant

Use any given initial conditions or boundary conditions to evaluate the integration constant, if applicable, giving a specific solution to the differential equation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

first-order differential equations
First-order differential equations are mathematical expressions that involve the first derivative of a function with respect to an independent variable. They are of the form \( y' = f(x, y) \), where \( y' \) is the derivative of \( y \) with respect to \( x \), and \( f(x, y) \) is some function of \( x \) and \( y \).

In the given problem, the differential equation is \((1 + \tan y) y' = x^2 + 1\), a non-linear first-order differential equation. These equations are significant in various fields like physics, engineering, and economics because they are used to model dynamic systems and changes over time.
  • First-order means only the first derivative appears.
  • Non-linear suggests the function \(y \) or its derivative appears in a non-linear way, like multiplication or division.
Solving such equations involves finding the function \( y(x) \) that satisfies the equation.
substitution method
The substitution method is a versatile technique often used to simplify differential equations, making them more manageable to solve. This approach involves changing variables, usually to transform a complicated equation into a simpler one.

In this exercise, the substitution \( u = \tan y \) was used. By substituting \( u \) for \( \tan y \), the differential equation becomes easier to handle. This step simplifies the separation of variables or other solution methods. The transformation helps by linearizing terms or converting them into a form suitable for standard solution techniques.
  • Helps simplify complex terms.
  • Transforms non-linear forms into linear ones.
  • Can make the equation solvable using integration.
for more clarity. The ultimate goal is to return to the original variables for the final solution.
separation of variables
Separation of variables is a common method used for solving differential equations, especially when the variables can be neatly divided. It involves rearranging the equation such that each differential term is on a different side and involves only one of the variables.

Although originally considered for this problem, direct separation was not applicable. Instead, substitution had to be used first to enable separation. After substitution, the equation became suitable for separation of variables before proceeding with integration.
  • Each side of the equation should involve only one variable.
  • Facilitates straightforward integration.
  • The transformed equation is solved through integration of each side.
The purpose of separating variables is to integrate both sides with respect to their own variables, leading to the solution of the original equation.
partial fraction decomposition
Partial fraction decomposition is a technique employed to break down complex rational expressions into simpler fractions, which can be easily integrated or otherwise manipulated.

In solving the given differential equation, partial fraction decomposition was applied after substituting and rearranging terms. The expression \( \frac{1}{(1 + u)(1 - u^2)} \) was decomposed into simpler fractions that were more manageable for integration.
  • Provides simpler terms for integration.
  • Allows integration of terms that are otherwise difficult to solve directly.
  • Widely used when dealing with polynomial denominators.
This method is essential in calculus and differential equations as it simplifies the process of integrating complex fractions to find solutions.

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Most popular questions from this chapter

One model for the spread of a rumor is that the rate of spread is proportional to the product of the fraction \(y\) of the popula- tion who have heard the rumor and the fraction who have not heard the rumor. (a) Write a differential equation that is satisfied by \(y\) . (b) Solve the differential equation. (c) A small town has 1000 inhabitants. At 8 AM, 80 people have heard a rumor. By noon half the town has heard it. At what time will 90 \(\%\) of the population have heard the rumor?

Let's modify the logistic differential equation of Example 1 as follows: $$\frac{d P}{d t}=0.08 P\left(1-\frac{P}{1000}\right)-15$$ (a) Suppose \(P(t)\) represents a fish population at time \(t\) where \(t\) is measured in weeks. Explain the meaning of the term \(-15 .\) (b) Draw a direction field for this differential equation. (c) What are the equilibrium solutions? (d) Use the direction field to sketch several solution curves. Describe what happens to the fish population for various initial populations. (e) Solve this differential equation explicitly, either by using partial fractions or with a computer algebra system. Use the initial populations 200 and \(300 .\) Graph the solutions and compare with your sketches in part (d).

(a) Use Euler's method with each of the following step sizes to estimate the value of \(y(0.4),\) where \(y\) is the solution of the initial-value problem \(y^{\prime}=y, y(0)=1 .\) (i) \(h=0.4 \quad\) (ii) \(h=0.2 \quad\) (iii) \(h=0.1\) (b) We know that the exact solution of the initial-value problem in part (a) is \(y=e^{x} .\) Draw, as accurately as you can, the graph of \(y=e^{x}, 0 \leqslant x \leqslant 0.4,\) together with the Euler approximations using the step sizes in part (a).(Your sketches should resemble Figures \(12,\) i3, and \(14 .\) .) Use your skethes to decide whether your estimates in part (a) are underestimates or overestimates. (c) The error in Euler's method is the difference between the exact value and the approximate value. Find the errors made in part (a) in using Euler's method to estimate the true value of \(y(0.4),\) namely \(e^{0.4} .\) What happens to the error each time the step size is halved?

Find the orthogonal trajectories of the family of curves.Use a graphing device to draw several members of each family on a common screen. $$y=\frac{x}{1+k x}$$

A tank with a capacity of 400 \(\mathrm{L}\) is full of a mixture of water and chlorine with a concentration of 0.05 \(\mathrm{g}\) of chlorine per liter. In order to reduce the concentration of chlorine, fresh water is pumped into the tank at a rate of 4 \(\mathrm{L} / \mathrm{s}\) . The mixture is kept stirred and is pumped out at a rate of 10 \(\mathrm{L} / \mathrm{s}\) . Find the amount of chlorine in the tank as a function of time.

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