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(a) Use Euler's method with step size 0.2 to estimate \(y(1.4),\) where \(y(x)\) is the solution of the initial-value problem $$y^{\prime}=x-x y, y(1)=0$$ (b) Repeat part (a) with step size 0.1 .

Short Answer

Expert verified
(a) \(y(1.4) \approx 0.392\) with \(h = 0.2\); (b) \(y(1.4) \approx 0.3868\) with \(h = 0.1\).

Step by step solution

01

Understand Euler's Method

Euler's method is a numerical technique to approximate solutions for differential equations. Given an initial value problem \(y' = f(x, y), y(x_0) = y_0\), the formula is \(y_{n+1} = y_n + h f(x_n, y_n)\), where \(h\) is the step size. We'll use this to estimate \(y(1.4)\).
02

Establish Initial Conditions

For the given problem, we have \(y'(x) = x - xy\) with initial condition \(y(1) = 0\). We want to find \(y(1.4)\).
03

Apply Euler's Method with Step Size 0.2 (Part a)

Starting at \(x_0 = 1\), \(y_0 = 0\):1. Calculate \(f(x_0, y_0) = 1 - 1 \cdot 0 = 1\).2. Update with step size 0.2: \(y_1 = 0 + 0.2 \times 1 = 0.2\).3. Move to \(x_1 = 1.2\).4. Calculate \(f(x_1, y_1) = 1.2 - 1.2 \cdot 0.2 = 0.96\).5. Update \(y_2 = 0.2 + 0.2 \times 0.96 = 0.392\).6. Move to \(x_2 = 1.4\). Thus, \(y(1.4) \approx 0.392\).
04

Apply Euler's Method with Step Size 0.1 (Part b)

Repeat the steps with \(h = 0.1\):1. Start at \(x_0 = 1\), \(y_0 = 0\).2. For \(x_1 = 1.1\), calculate \(f(x_0, y_0) = 1\) and update \(y_1 = 0 + 0.1 \times 1 = 0.1\).3. For \(x_2 = 1.2\), calculate \(f(x_1, y_1) = 1.1 - 1.1 \times 0.1 = 0.99\) and update \(y_2 = 0.1 + 0.1 \times 0.99 = 0.199\).4. For \(x_3 = 1.3\), calculate \(f(x_2, y_2) = 1.2 - 1.2 \times 0.199 = 0.9612\) and update \(y_3 = 0.199 + 0.1 \times 0.9612 = 0.29512\).5. For \(x_4 = 1.4\), calculate \(f(x_3, y_3) = 1.3 - 1.3 \times 0.29512 = 0.916336\) and update \(y_4 = 0.29512 + 0.1 \times 0.916336 = 0.3867536\).Thus, \(y(1.4) \approx 0.3868\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Numerical Methods
Numerical methods are powerful tools in mathematics that help us approximate complex mathematical problems using simpler calculations. They are particularly useful for solving problems that do not have a straightforward analytical solution, like some differential equations. Euler's Method, for instance, is one of the most fundamental numerical methods. It allows us to approximate solutions to differential equations by creating a series of slopes between known and estimated values. Each step of this process is determined by a chosen step size, which affects the accuracy of the approximation. The smaller the step size, the more steps you take, leading to a potentially more precise result. However, this also requires more computational work. In essence, numerical methods like Euler's Method give us a practical way of tackling problems when traditional algebraic solutions are challenging to obtain.
Differential Equations
Differential equations are a type of equation that involve functions and their derivatives. These equations are essential in modeling various natural phenomena where change is a central concept. For example, differential equations can represent how populations grow, how heat transfers, or how waves propagate. In the context of Euler's method, we focus on first-order differential equations, which involve the first derivative of a function. The general form can be expressed as \( y' = f(x, y) \), where \( y' \) represents the rate of change of \( y \) with respect to \( x \), and \( f(x, y) \) is a given function describing that rate. Solving these equations analytically can be complicated, but numerical methods provide practical techniques for estimating solutions over a defined interval. By understanding the nature of the differential equation, we can use Euler's Method to iteratively approximate the solution, moving from the initial condition through calculated small steps.
Initial Value Problem
An initial value problem (IVP) is a specific kind of differential equation that comes with a given set of conditions. These conditions typically provide the starting point for the function, like a known value at the start of an interval. In mathematical terms, an IVP is expressed as \( y' = f(x, y) \) with a specific initial condition \( y(x_0) = y_0 \). This initial condition is crucial because it anchors the solution and provides the necessary starting point for methods like Euler's to approximate the function's behavior over a span of\( x \) values. It simplifies the application of numerical methods by reducing the problem to finding a path through a known point. In real-world applications, initial value problems are abundant. They appear in fields like physics, engineering, and economics, often representing systems where the future behavior hinges on initial conditions. Euler's Method effectively uses these initial conditions to plot the course of the function step by step.

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Most popular questions from this chapter

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