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The dye dilution method is used to measure cardiac output with 6 \(\mathrm{mg}\) of dye. The dye concentrations, in mg/L, are mod- eled by \(d t )=20 t e^{-0.6 t}, 0 \leqslant t \leqslant 10,\) where \(t\) is measured in seconds. Find the cardiac output.

Short Answer

Expert verified
The cardiac output is calculated by evaluating \( Q = \frac{6}{\int_0^{10} 20t e^{-0.6t} dt} \).

Step by step solution

01

Understand the Problem

The problem involves determining the cardiac output using the dye dilution technique. The dye concentration is given by the function \( d(t) = 20t e^{-0.6t} \), and the total dye used is 6 mg. Cardiac output is the volume of blood the heart pumps per unit time.
02

Write the Formula for Cardiac Output

Cardiac output \( Q \) can be determined using the formula \( Q = \frac{D}{\int_0^{10} d(t) \, dt} \), where \( D \) is the total dye injected (6 mg) and \( \int_0^{10} d(t) \, dt \) is the integral of the concentration function over the given interval.
03

Evaluate the Integral

Compute the integral \( \int_0^{10} 20t e^{-0.6t} \, dt \). This integral requires the use of integration by parts or looking up its solution in integral tables.
04

Integration by Parts Setup

For integration by parts, let \( u = t \) and \( dv = 20e^{-0.6 t} \, dt \). Thus, \( du = dt \) and \( v = -\frac{20}{0.6}e^{-0.6 t} \).
05

Calculate Integral by Parts

Substitute into the integration by parts formula \( \int u \, dv = uv - \int v \, du \). This gives us: \[\int_0^{10} 20t e^{-0.6 t} \, dt = \left[-\frac{20}{0.6}t e^{-0.6 t} + \int \frac{20}{0.6} e^{-0.6 t} \, dt \right]_0^{10} \].
06

Simplify and Evaluate the Remaining Integral

Calculate the remaining integral and evaluate the expression from 0 to 10 seconds: \( \int \frac{20}{0.6} e^{-0.6 t} \, dt = \left[-\frac{20}{0.36}e^{-0.6 t}\right]_0^{10} \). Evaluate both parts from \( t = 0 \) to \( t = 10 \) and simplify.
07

Final Calculation for Cardiac Output

Plug the result of the definite integral back into the formula for \( Q \). Compute \( Q = \frac{6}{\text{value of the definite integral}} \) to get the cardiac output in liters per second.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Dye Dilution Method
The dye dilution method is a widely used technique to measure cardiac output, which refers to the volume of blood pumped by the heart per unit time. Generally, a known amount of dye is injected into the bloodstream and the concentration of this dye is measured at a specific downstream point.
By analyzing how the concentration changes over time, we can deduce how efficiently and effectively the heart is pumping blood.
In our specific exercise, we use 6 mg of dye, and concentration is modeled mathematically to provide insights into cardiac health. Let's take a closer look at how mathematical integration can help us determine the cardiac output from this concentration data.
Integration by Parts
Integration by parts is a technique used in calculus to integrate products of functions. It derives from the product rule for differentiation and can be a powerful tool to solve complex integrals.
The formula for integration by parts is: \[ \int u \, dv = uv - \int v \, du \]where "u" and "dv" are differentiated and integrated, respectively.
In our problem, to solve the integral of the concentration function \(20t e^{-0.6t}\), we choose \(u = t\) and \(dv = 20e^{-0.6 t} \, dt\). This approach helps us transform the integral into a potentially simpler format that's more straightforward to solve.
It's a preferred technique when dealing with functions involving products like polynomials and exponential functions.
Definite Integral
A definite integral, unlike an indefinite integral, calculates the net area under a curve over a specific interval. It's pivotal in many applications such as finding the total quantity from a rate of change.
For example, in our exercise, the definite integral \(\int_0^{10} 20t e^{-0.6t} \, dt\) represents the cumulative concentration of dye over the 10-second period.
Evaluating this integral provides a crucial component needed to calculate cardiac output. Since this integral is defined over a specific interval \([0, 10]\), it gives us a concrete value that helps in determining blood flow rates in the cardiac system.
Exponential Functions
Exponential functions are mathematical expressions in which a constant base is raised to a variable exponent. In the function \(20t e^{-0.6t}\), the term \(e^{-0.6t}\) is an exponential function. It describes processes that change rapidly and can model various phenomena such as radioactive decay, population growth, and in this context, the decay of dye concentration over time.
The negative exponent indicates a decay process, suggesting that as time progresses, the concentration diminishes exponentially.
Understanding exponential functions is key in analyzing the nature of dye dilution and predicting how it behaves within the circulatory system over time.

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Most popular questions from this chapter

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