Chapter 6: Problem 60
The base of \(S\) is a circular disk with radius \(r .\) Parallel cross- sections perpendicular to the base are isosceles triangles with height \(h\) and unequal side in the base. (a) Set up an integral for the volume of \(S\) . (b) By interpreting the integral as an area, find the volume of \(S .\)
Short Answer
Step by step solution
Understanding the Problem
Establish the Cross-Section Equation
Determine Area of Isosceles Triangle
Set Up the Volume Integral
Interpret the Integral as an Area
Solve the Integral
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Integral Calculus
To set up this integral, one must first understand the shape and dimensions of the cross-sectional area. It is important to express the area of each slice as a function of a variable. In our case, this variable is the position along the axis perpendicular to the circular base. The integral accumulates these areas by adding them from one side of the base to the other.
- The infinitesimal slices are essentially isosceles triangles aligned perpendicularly to the circular base.
- The integral increases the accuracy of the total volume calculation by considering each slice individually.
- Calculating the volume is akin to summing up all the triangle's areas across the base.
Isosceles Triangle Cross-Sections
In this scenario, you are asked to find the area of these triangles to set up the integral for the volume. The base of each triangle is not constant but rather changes with its position on the disk, calculated as \(2\sqrt{r^2 - x^2}\). This reflects the circular nature of the base since the length varies depending on how far you are from the center.
- The height of each triangle remains constant at \(h\).
- Calculating the area of the triangle uses the formula \(A(x) = \frac{1}{2} \times \text{base} \times \text{height}\).
- This step is crucial as it directly feeds into the integral formulation for volume calculation.
Geometric Interpretation
The integral resembles the calculation of a semicircle area, as the cross-sectional triangles describe a hollowed circle's area. The alignment of the integral with the circle's geometrical properties hints at comparing this scenario with solid revolutions or other known volumes.
- This approach reduces complexity by linking the solid formation to familiar geometrical entities.
- Leveraging geometry helps estimate or confirm results derived from calculus.
- Visualizing these connections makes abstract mathematical formulas more concrete.
Solid of Revolution
This method effectively calculates the volume of irregular solids by summing infinitesimal cross-sections or snapshots of the object along an axis. Such volumes are automatically symmetric around the axis of rotation.
Even though the triangles in our problem aren't formed through direct rotation, the calculation bears a similarity to solid of revolution techniques because:
- The volume is calculated using an integral over parts defined along an axis.
- The sum of infinitesimal volume pieces mirrors the summation in solid revolutions.
- Conceptually, the shape constructs from slicing and approximating smaller volumes.