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\(37-38\) Use a computer algebra system to find the exact volume of the solid obtained by rotating the region bounded by the given curves about the specified line. $$ y = \sin ^ { 2 } x , y = 0,0 \leqq x \leqslant \pi ; \quad \text { about } y = - 1 $$

Short Answer

Expert verified
The exact volume is \( 3\pi^2 \).

Step by step solution

01

Understand the Problem

We need to find the volume of a solid formed by rotating the area enclosed by the curves \( y = \sin^2 x \) and \( y = 0 \) from \( x = 0 \) to \( x = \pi \) about the line \( y = -1 \).
02

Identify the Method of Rotation

The solid is formed by rotating around a line parallel to the x-axis, so we will use the Washer Method, which involves integrating the area of circular washers to find the volume.
03

Determine the Radii of the Washers

The inner radius \( r_{\text{inner}}(x) \) from the axis of rotation \( y = -1 \) to the curve \( y = 0 \) is \( 1 \), and the outer radius \( r_{\text{outer}}(x) \) is from \( y = -1 \) to \( y = \sin^2 x \), giving us \( r_{\text{outer}}(x) = \sin^2 x + 1 \).
04

Express the Volume Integral

The volume \( V \) is given by the integral: \[ V = \pi \, \int_{0}^{\pi} \left( (\sin^2 x + 1)^2 - 1^2 \right) \, dx. \]
05

Simplify the Integral

Expand and simplify the integrand: \[ (\sin^2 x + 1)^2 - 1^2 = \sin^4 x + 2 \sin^2 x + 1 - 1. \] This simplifies to \[ \sin^4 x + 2 \sin^2 x.\]
06

Decompose the Integral

The integral becomes:\[ V = \pi \, \left( \int_{0}^{\pi} \sin^4 x \, dx + 2 \int_{0}^{\pi} \sin^2 x \, dx \right). \]
07

Solve the Integrals

Use the identities \( \sin^2 x = \frac{1 - \cos 2x}{2} \) and \( \sin^4 x = \left( \frac{1 - \cos 2x}{2} \right)^2 \) to solve each integral. This involves using trigonometric identities and performing substitutions to evaluate.
08

Compute the Final Volume

Evaluate the integrals and multiply by \( \pi \) to find the exact volume, ensuring calculations are exact, possibly using a computer algebra system to handle complex simplifications.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

washer method
The Washer Method is a technique used in calculus to find the volume of a solid of revolution. When we revolve a region around an axis that is not necessarily the boundary of the region, we end up with a shape like a donut or washer, hence the name.This method involves slicing the solid perpendicular to the axis of revolution and visualizing the solid as a series of thin washers. The volume of each washer can be calculated and then summed up to get the total volume of the solid.
  • The inner radius of a washer is the distance from the axis of rotation to the nearest edge of the region.
  • The outer radius is the distance from the axis to the farthest edge.
  • The washer consists of a hole, hence the need to subtract the volume of the inner disk from the outer disk.
To calculate the volume, we use the integral:\[V = \pi \, \int_{a}^{b} \left( r_{\text{outer}}^2(x) - r_{\text{inner}}^2(x) \right) \, dx,\]where \( r_{\text{outer}}(x) \) and \( r_{\text{inner}}(x) \) are the outer and inner radii of the washers.In our problem, we're rotating around the line \( y = -1 \), which isn't a boundary of our region, making the washer method appropriate. We identified the radii as \( r_{\text{inner}}(x) = 1 \) and \( r_{\text{outer}}(x) = \sin^2 x + 1 \). By integrating these properly, we find the volume of the solid of revolution.
volume of solids of revolution
The concept of the volume of solids of revolution is fundamental to understanding 3D shapes obtained by rotating a 2D area around an axis. This process creates shapes like cylinders, cones, and more complex figures.The classic methods to find these volumes are the Disk Method and the Washer Method. The difference between them centers on the presence of a hole in the rotated shape, which is why the Washer Method is often required when the solid has an inner void.The integral formula for the volume of a solid revolves around knowing how the shape changes as it rotates.
  • A key element is understanding the bounds of integration, which in our case runs from \( x = 0 \) to \( x = \pi \).
  • The axis of rotation is essential for determining the position of the inner and outer radii in our integrals.
For a clear visualization, consider the solid in cross-section as you perform integration along the x-axis. The result is a precise measurement of a 3D shape based on 2D functions expanded by rotation.
trigonometric integration
Trigonometric integration is crucial when dealing with functions involving sine and cosine, as is common in many physical applications, such as calculating pendulum motions or wave patterns.Trigonometric identities often simplify the integration process:
  • For instance, when you face terms like \( \sin^2 x \), it is easier to integrate using the identity \( \sin^2 x = \frac{1 - \cos 2x}{2} \).
  • Similar identities exist for \( \cos^2 x \) and other even powers of sine and cosine, which help break down these functions into manageable parts.
In the challenge of integrating \( \sin^4 x \) and \( \sin^2 x \) in our washer volume problem, these identities play a crucial role in simplifying our integral into solvable components by reducing the powers and making the integrals friendly for anti-differentiation. Proper use of these identities allows us to reach exact answers, which can be complex and involve multiple steps, sometimes assisted by computational tools.

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