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7-46 Evaluate the indefinite integral. \(\int e^{\ln x} \sec ^{2} x d x\)

Short Answer

Expert verified
The integral evaluates to \( x \tan x + \ln |\cos x| + C \).

Step by step solution

01

Simplify the Integrand

First, recognize that \( e^{\ln x} \) simplifies to \( x \). This is because the exponential and the natural logarithm are inverse functions. So, the integrand \( e^{\ln x} \sec^2 x \) becomes \( x \sec^2 x \).
02

Identify the Integration Technique

Now, we need to integrate \( x \sec^2 x \). Notice that \( \sec^2 x \) is the derivative of \( \tan x \). This hints at using integration by parts, where one function is \( x \) and the other is \( \sec^2 x \).
03

Apply Integration by Parts

For integration by parts, select \( u = x \) and \( dv = \sec^2 x \, dx \). Then, compute \( du = dx \) and \( v = \tan x \). Apply the formula \( \int u \, dv = uv - \int v \, du \). Substitute these into the formula:\[\int x \sec^2 x \, dx = x \tan x - \int \tan x \, dx.\]
04

Integrate \( \tan x \)

Remember that \( \int \tan x \, dx = -\ln |\cos x| \). So, \[\int x \sec^2 x \, dx = x \tan x + \ln |\cos x| + C.\]
05

Write the Final Expression

Substitute the integration results back into the original problem, so the indefinite integral becomes:\[\int e^{\ln x} \sec^2 x \, dx = x \tan x + \ln |\cos x| + C.\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Integration by Parts
Integration by parts is an essential technique used in calculus to integrate products of functions. It is based on the product rule for differentiation. The formula for integration by parts is expressed as:\[ \int u \, dv = uv - \int v \, du \]Here is a breakdown of how you apply this to solve integrals:
  • Choose 'u' and 'dv' from the integrand, such that 'u' becomes simpler when differentiated, and 'dv' is easily integrable.
  • Differentiate 'u' to find 'du', and integrate 'dv' to obtain 'v'.
  • Substitute these into the integration by parts formula to solve the integral.
For the integral \( \int x \sec^2 x \, dx \), we set \( u = x \) and \( dv = \sec^2 x \, dx \). So, \( du = dx \) and \( v = \tan x \), leading us to the expression:\[ \int x \sec^2 x \, dx = x \tan x - \int \tan x \, dx \]This method can greatly simplify integrating difficult expressions, especially when a function is multiplied by another function that is the derivative of an inverse trigonometric function.
Natural Logarithm
Natural logarithms, denoted as \( \ln(x) \), are logarithms to the base 'e', where 'e' is approximately 2.718. They are vital in calculus because they serve as the inverse function of the exponential function \( e^x \).
  • Relationship with Exponentials: \( e^{\ln x} = x \). This shows that taking the natural log of 'x' and then raising 'e' to that power gives back 'x'.
  • This identity helps to simplify expressions in integrals, as seen when simplifying \( e^{\ln x} \sec^2 x \) to \( x \sec^2 x \).
  • The property \( \ln(ab) = \ln a + \ln b \) and \( \ln(a/b) = \ln a - \ln b \) aid in transforming complex expressions.
In the context of the original problem, converting \( e^{\ln x} \) to 'x' simplifies the integral and allows effective use of integration techniques. Mastering natural logarithms and their properties is indispensable for solving integrals involving exponential and logarithmic functions.
Trigonometric Functions
Trigonometric functions play a crucial role in integrating many expressions. Important functions include sine, cosine, secant, and tangent, each with unique properties and derivatives that can be leveraged in calculus.
  • The function \( \sec^2 x \) is especially noteworthy because it is the derivative of \( \tan x \).
  • Understanding the derivatives and integrals of trigonometric functions is key. For instance, \( \int \sec^2 x \, dx = \tan x + C \) and \( \int \tan x \, dx = -\ln |\cos x| + C \).
  • Trigonometric identities like \( \tan x = \frac{\sin x}{\cos x} \) and \( \sec x = \frac{1}{\cos x} \) help in transforming and simplifying complex integrals.
In the integral \( \int x \sec^2 x \, dx \), recognizing \( \sec^2 x \) as the derivative of \( \tan x \) enables strategic integration by parts. Trigonometric functions' familiarity and their relationships unlock simplification paths for integrals, enhancing the efficacy of calculus techniques.

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Most popular questions from this chapter

Economists use a cumulative distribution called a Lorenz curve to describe the distribution of income between house- holds in a given country. Typically, a Lorenz curve is defined on \([0,1]\) with endpoints \((0,0)\) and \((1,1),\) and is continuous, increasing, and concave upward. The points on this curve are determined by ranking all households by income and then computing the percentage of households whose income is less than or equal to a given percentage of the total income of the country. For example, the point (a/100, b/ 100 ) is on the Lorenz curve if the bottom a \(\%\) of the households receive less than or equal to \(b \%\) of the total income. Absolute equality of income distribution would occur if the bottom a \(\%\) of the households receive a \(\%\) of the income, in which case the Lorenz curve would be the line \(y=x\) . The area between the Lorenz curve and the line \(y=x\) measures how much the income distribution differs from absolute equality. The coefficient of inequality is the ratio of the area between the Lorenz curve and the line \(y=x\) to the area under \(y=x\) . $$\begin{array}{c}{\text { (a) Show that the coefficient of inequality is twice the area }} \\ {\text { between the Lorenz curve and the line } y=x \text { , that is, }} \\ {\text { show that }} \\ {\quad \text { coefficient of inequality }=2 \int_{0}^{1}[x-L(x)] d x}\end{array}$$ $$\begin{array}{c}{\text { (b) The income distribution for a certain country is repre- }} \\ {\text { sented by the Lorenz curve defined by the equation }} \\ {L(x)=\frac{5}{12} x^{2}+\frac{7}{12} x}\end{array}$$ What is the percentage of total income received by the bottom 50\(\%\) of the households? Find the coefficient of inequality.

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