/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 74 A car braked with a constant dec... [FREE SOLUTION] | 91Ó°ÊÓ

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A car braked with a constant deceleration of \(16 \mathrm{ft} / \mathrm{s}^{2},\) producing skid marks measuring 200 \(\mathrm{ft}\) before coming to a stop. How fast was the car traveling when the brakes were first applied?

Short Answer

Expert verified
The car was initially traveling at 80 ft/s.

Step by step solution

01

Understand the problem

We need to find the initial speed of the car when the brakes were applied, given the deceleration and the distance covered (which is the skid mark).
02

Identify formulas and variables

We are given the deceleration (\(a = -16 \, \text{ft/s}^2\)) and the skid mark (distance) (\(d = 200 \, \text{ft}\)). We need to find the initial speed (\(v_0\)). We can use the kinematic equation:\[v^2 = v_0^2 + 2ad\]where \(v\) is the final velocity (0 \, \text{ft/s} since the car stopped).
03

Rearrange formula to solve for initial velocity

Since the car stopped, \(v = 0 \, \text{ft/s}\). The formula \(v^2 = v_0^2 + 2ad\) becomes \(0 = v_0^2 + 2(-16)(200)\). Simplify to solve for \(v_0^2\):\[v_0^2 = -2(-16)(200)\].
04

Calculate the initial speed

Calculate \(-2(-16)(200)\):\(v_0^2 = 6400\). Take the square root of both sides to find \(v_0\):\(v_0 = \sqrt{6400} = 80 \, \text{ft/s}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Deceleration
Deceleration is a term used to describe the rate at which an object slows down. When a car applies its brakes, deceleration occurs because the vehicle's speed decreases over time. It is essentially a negative acceleration.
In our problem, the car decelerates at a constant rate of \(-16 \, \text{ft/s}^2\). This means that for every second the brakes are applied, the car's velocity decreases by 16 feet per second.
Some key points to keep in mind about deceleration are:
  • It is always a negative value in kinematic equations because it represents slowing down.
  • It is constant in this problem, which simplifies calculations and makes the mathematical model reliable.
  • Units of deceleration are the same as acceleration: distance per time squared, e.g., \(\text{ft/s}^2\).
Understanding how deceleration works helps us interpret the effect of forces on moving objects, such as the braking force on the car in this exercise.
Initial Velocity
Initial velocity is the speed at which an object starts its motion. In our exercise, we are seeking to find the car's initial velocity when it began braking, before it came to a stop.
The given kinematic equation is:\[v^2 = v_0^2 + 2ad\]where:
  • \(v\) is the final velocity, which is 0 \(\text{ft/s}\) because the car stops.
  • \(v_0\) is the initial velocity we need to find.
  • \(a\) is the deceleration, \(-16 \, \text{ft/s}^2\).
  • \(d\) is the distance of the skid mark, 200 \(\text{ft}\).
Initial velocity is vital for understanding how fast something was moving before forces, such as braking, became involved. By knowing the initial velocity, we can make informed predictions about motion and stopping distances.
Problem Solving
Effective problem solving in physics requires a systematic approach. In this scenario, we followed steps that illustrate the process clearly:
1. **Understand the Problem:** Recognize what needs to be found—here, it is the initial speed of the car.2. **Identify Formulas and Variables:** Locate the given values: a deceleration of \(-16 \, \text{ft/s}^2\) and a distance of 200 \(\text{ft}\). Select the kinematic equation that connects these values.3. **Rearrange Formulas:** With the final velocity as 0, alter the kinematic equation to solve for initial velocity.4. **Calculate and Conclude:** Perform the calculations to find \(v_0\). In our example, this calculation yielded an initial velocity of 80 \(\text{ft/s}\).
This structured strategy is crucial in physics, allowing us to break down complex problems into manageable parts.
Physics
Physics is the science that deals with the nature and properties of matter and energy. It covers a vast range of phenomena, from subatomic particles to galaxies, and everything in between. Our particular problem is an example of classical mechanics, an essential branch of physics.
Key physics principles involved in our exercise include:
  • Newton's laws of motion, which describe how objects respond to forces like braking.
  • Kinematic equations, which help calculate motion-related values such as distance, velocity, and time.
  • The concept of constant acceleration or deceleration, which simplifies our calculations.
Through these principles, physics enables us to predict and understand real-world behaviors and scenarios, such as a car's response to deceleration.

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Most popular questions from this chapter

During the summer months Terry makes and sells necklaces on the beach. Last summer he sold the necklaces for \(\$ 10\) each and his sales averaged 20 per day. When he increased the price by \(\$ 1 ,\) he found that the average decreased by two sales per day. (a) Find the demand function, assuming that it is linear. (b) If the material for each necklace costs Terry S6, what should the selling price be to maximize his profit?

What is the shortest possible length of the line segment that is cut off by the first quadrant and is tangent to the curve \(y = 3 / x\) at some point?

(a) Sketch the graph of a function on \([-1,2]\) that has an absolute maximum but no local maximum. (b) Sketch the graph of a function on \([-1,2]\) that has a local maximum but no absolute maximum.

In a beehive, each cell is a regular hexagonal prism, open at one end with a trihedral angle at the other end as in the figure. It is believed that bees form their cells in such a way as to minimize the surface area for a given volume, thus using the least amount of wax in cell construction. Examination of these cells has shown that the measure of the apex angle \(\theta\) is amazingly consistent. Based on the geometry of the cell, it can be shown that the surface area \(S\) is given by $$S = 6.5 h - \frac { 3 } { 2 } s ^ { 2 } \cot \theta + \left( 3 s ^ { 2 } \sqrt { 3 } / 2 \right) \csc \theta$$ where \(s ,\) the length of the sides of the hexagon, and \(h ,\) the height, are constants. (a) Calculate \(d S / d \theta\) (b) What angle should the bees prefer? (c) Determine the minimum surface area of the cell (in terms of \(s\) and \(h\) . Note: Actual measurements of the angle \(\theta\) in beehives have been made, and the measures of these angles seldom differ from the calculated value by more than \(2 ^ { \circ }\) .

(a) Sketch the graph of a function that has two local maxima, one local minimum, and no absolute minimum. (b) Sketch the graph of a function that has three local minima, two local maxima, and seven critical numbers.

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