Chapter 4: Problem 59
\(5-64\) Find the limit. Use I'Hospital's Rule where appropriate. If there is a more elementary method, consider using it. If l'Hospital's Rule doesn't apply, explain why. $$\lim _{x \rightarrow \infty} x^{1 / x}$$
Short Answer
Expert verified
The limit is 1.
Step by step solution
01
Rewrite the Expression
We want to find \( \lim_{x \to \infty} x^{1/x} \). Start by rewriting the expression: \( x^{1/x} = e^{\ln(x^{1/x})} = e^{\frac{\ln x}{x}} \). This allows us to handle the limit using properties of logarithms and exponentials.
02
Set Up the Limit Problem for the Exponent
Now, consider the exponent itself: \( \lim_{x \to \infty} \frac{\ln x}{x} \). Our task now is to evaluate this limit to determine the limit of the entire expression.
03
Apply L'Hôpital's Rule
The limit \( \lim_{x \to \infty} \frac{\ln x}{x} \) is of the form \( \frac{\infty}{\infty} \), which is indeterminate. Therefore, we can apply L'Hôpital's Rule. Take the derivative of the numerator and the denominator.The derivative of \(\ln x\) is \(\frac{1}{x}\), and the derivative of \(x\) is \(1\). Applying L'Hôpital's Rule, the limit becomes:\[\lim_{x \to \infty} \frac{\ln x}{x} = \lim_{x \to \infty} \frac{1/x}{1} = \lim_{x \to \infty} \frac{1}{x}.\]
04
Evaluate the Limit of the Fraction
Now evaluate \( \lim_{x \to \infty} \frac{1}{x} \). As \(x\) approaches infinity, \(\frac{1}{x}\) approaches 0. Thus, \( \lim_{x \to \infty} \frac{\ln x}{x} = 0 \).
05
Determine the Limit of the Original Expression
Substitute back into the exponential form: \( e^{ \lim_{x \to \infty} \frac{\ln x}{x} } = e^0 = 1 \). This shows that the limit of the original expression is 1.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
L'Hôpital's Rule
L'Hôpital's Rule is a powerful tool for evaluating limits that result in indeterminate forms such as \( \frac{0}{0} \) or \( \frac{\infty}{\infty} \). This rule simplifies the evaluation by allowing us to take the derivatives of the numerator and the denominator separately.
Imagine you face a limit problem that makes no sense directly, like dividing infinity by infinity. That's where L'Hôpital's Rule comes in handy. It's like getting a hint to simplify things:
Imagine you face a limit problem that makes no sense directly, like dividing infinity by infinity. That's where L'Hôpital's Rule comes in handy. It's like getting a hint to simplify things:
- Check if the direct limit results in an indeterminate form.
- If it does, differentiate the top and bottom functions.
- Evaluate the new limit.
Exponential and Logarithmic Functions
Exponential and logarithmic functions are fundamental in calculus, especially when dealing with limits. They connect nicely through the identity \( y = a^x \) corresponding to \( \, \ln(y) = x \ln(a) \).
In our problem, writing the expression as \( e^{\ln(x^{1/x})} \) was strategic. Why? It allowed us to use the properties of logarithms and exponentials, making the limit easier to manage. This technique is about expressing a complex power function in a way that's simpler to analyze.
You often encounter logarithms to flatten exponentiation. Here it served us well. Remember, when you take the natural log of a power \( \ln(a^b) = b \ln a \). That switch turns tricky exponentiation into more workable multiplication.
In our problem, writing the expression as \( e^{\ln(x^{1/x})} \) was strategic. Why? It allowed us to use the properties of logarithms and exponentials, making the limit easier to manage. This technique is about expressing a complex power function in a way that's simpler to analyze.
You often encounter logarithms to flatten exponentiation. Here it served us well. Remember, when you take the natural log of a power \( \ln(a^b) = b \ln a \). That switch turns tricky exponentiation into more workable multiplication.
- Write power functions using natural logarithms when needed.
- Transform limits with exponential functions to handle indeterminate forms.
Indeterminate Forms
Indeterminate forms are expressions in calculus that don't have a straightforward limit value upon initial inspection. Common forms include \( \frac{0}{0} \), \( \frac{\infty}{\infty} \), and more.
Identifying an indeterminate form is key to knowing when tools like L'Hôpital's Rule or restructuring the expression are needed. In our exercise, the limit \( \frac{\ln x}{x} \) turned into \( \frac{\infty}{\infty} \) at first glance. That 'messy' form flag signals we can't just plug and solve.
Each form stems from a different type of limit situation:
Identifying an indeterminate form is key to knowing when tools like L'Hôpital's Rule or restructuring the expression are needed. In our exercise, the limit \( \frac{\ln x}{x} \) turned into \( \frac{\infty}{\infty} \) at first glance. That 'messy' form flag signals we can't just plug and solve.
Each form stems from a different type of limit situation:
- \( \frac{0}{0} \): When both parts get close to zero.
- \( \frac{\infty}{\infty} \): When both parts head towards infinity.
- Powers or products like \( 0^0 \) or \( \infty^0 \) suggest different approaches, like logarithmic transformation.