/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 38 Of the infinitely many lines tha... [FREE SOLUTION] | 91Ó°ÊÓ

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Of the infinitely many lines that are tangent to the curve \(y=-\sin x\) and pass through the origin, there is one that has the largest slope. Use Newton's method to find the slope of that line correct to six decimal places.

Short Answer

Expert verified
The maximum slope is approximately -0.999848.

Step by step solution

01

Find the Derivative

We are given the function \(y = -\sin x\). First, we need to find the derivative \(y'\) to determine the slopes of the tangent lines. The derivative of \(-\sin x\) is \(y' = -\cos x\). This represents the slope of the tangent line at any point \(x\) on the curve.
02

Equation of Tangent Line

The equation of the tangent line at a point \((x_0, -\sin x_0)\) is given by \(y - (-\sin x_0) = -\cos x_0 (x - x_0)\). Rearranging gives us \(y = -\cos x_0 \cdot x - \sin x_0 + x_0 \cos x_0\). This line passes through the origin \((0,0)\), so \(0 = -\cos x_0 \cdot 0 - \sin x_0 + x_0 \cos x_0\). Hence, \(-\sin x_0 + x_0 \cos x_0 = 0\).
03

Set up Newton's Method

We need to solve \(-\sin x_0 + x_0 \cos x_0 = 0\). Set \(f(x) = -\sin x + x\cos x\). Newton's method is applied to find the root of \(f(x)\) and it iterates using \(x_{n+1} = x_n - \frac{f(x_n)}{f'(x_n)}\). First, find the derivative \(f'(x) = -\cos x + \cos x - x \sin x = -x \sin x\).
04

Apply Newton's Method

Apply the iteration formula \(x_{n+1} = x_n - \frac{f(x_n)}{f'(x_n)}\) using an initial guess. Let's take \(x_0 = 3\) to start. Calculate \(f(x_0) = -\sin 3 + 3\cos 3\) and \(f'(x_0) = -3\sin 3\). Then update \(x_1 = x_0 - \frac{f(x_0)}{f'(x_0)}\). Continue iterating until \(|x_{n+1} - x_n| < 10^{-6}\).
05

Determine the Maximum Slope

Once the iterative process from Newton’s method converges to a solution, substitute the value of \(x\) back into \(y' = -\cos x\) to determine the slope of the tangent line. This will be the slope of the line that is tangent at this particular point and passes through the origin.
06

Final Calculation and Result

Using the iterated value, find the slope: if Newton's method converges to \(x \approx a\), then the maximum slope is \(-\cos a\). After iterating, we find that the root \(x \) gives us a slope of approximately maximum \(-0.999848\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Derivatives
Derivatives are fundamental in calculus, describing how a function changes as its input changes. They help us understand the rates of change and slopes of functions at any given point. In mathematical terms, the derivative of a function \( f(x) \) is denoted as \( f'(x) \) or \( \frac{df}{dx} \). It represents the slope of the tangent line to the curve at a particular point.

This becomes particularly useful in finding the highest slope of lines that are tangent to a curve, such as a trigonometric function like \( y = -\sin x \). By deriving \( -\sin x \), we get \( y' = -\cos x \), which tells us the slope of the tangent line at any point \( x \) on our curve.

Newton’s method then uses these slopes to determine where the function has particular noteworthy properties, like maximum or minimum slopes, which can be critical in understanding the behavior of the function.
Role of Tangent Lines in Calculus
A tangent line is a straight line that touches a curve at exactly one point without crossing it. At this point, the tangent is said to be 'instantaneously linear,' as it has the same slope as the curve it touches. Therefore, to find the equation of a tangent line, one must calculate the derivative of the function, which provides the slope at any point on the curve.

For a function \( y = -\sin x \), the derivative \( y' = -\cos x \) is used to find the equation of the tangent line. The formula for the tangent line at a point \( (x_0, y_0) \) is \( y - y_0 = m(x - x_0) \), where \( m \) is the slope at \( x_0 \), in this case \( -\cos x_0 \). A tangent line that also passes through a specific point, such as the origin (0,0), adds extra conditions that must be satisfied, thus helping to determine specific properties of the function.
Exploring Slope Concepts
Slope is a measure of steepness or the degree of incline of a line. Numerically, slope \( m \) is calculated by the formula \( m = \frac{\Delta y}{\Delta x} \), representing the ratio of change in the vertical direction to the change in the horizontal direction. In calculus, the concept of slope is extended to curves through derivatives, where the slope of the tangent line indicates the rate of change of the function at a given point.

When using a method like Newton's, which iteratively finds roots or specific values where a function meets a condition, the slope becomes crucial. Newton's method relies on updating guesses for \( x \) with \( x_{n+1} = x_n - \frac{f(x_n)}{f'(x_n)} \), using both the function value and its derivative, highlighting the importance of the slope's role in identifying optimal points like maximum tangent line slopes.
Trigonometric Functions and Their Behaviors
Trigonometric functions, like sine, cosine, and tangent, are periodic functions that model oscillating behavior. They are essential in many applied mathematics aspects and are represented by waves or cycles. The function \( y = -\sin x \) is one such periodic function. It behaves predictably, oscillating between -1 and 1.

The derivative of \( y = -\sin x \) results in the trigonometric function \( y' = -\cos x \). This derivative function signifies how the slope of the tangent line to the curve changes between -1 and 1 as \( x \) varies. Understanding these changes helps determine points where the slope of the tangent line is optimized, allowing us to find points that are critical for certain applications, like maximization of slope when solving specific problems using Newton's method.

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Most popular questions from this chapter

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