Chapter 4: Problem 36
Use the guidelines of this section to sketch the curve. \(y=\sec x+\tan x, \quad 0< x<\pi / 2\)
Short Answer
Expert verified
The curve \( y = \sec x + \tan x \) starts near 1 and increases towards infinity as \( x \) approaches \( \pi/2 \).
Step by step solution
01
Understand the Function Components
The given function is composed of two trigonometric functions: \( y = \sec x + \tan x \). The secant function, \( \sec x = \frac{1}{\cos x} \), and the tangent function, \( \tan x = \frac{\sin x}{\cos x} \). Both components depend on the cosine function and are undefined where \( \cos x = 0 \). In the interval \( 0 < x < \frac{\pi}{2} \), \( \cos x \) doesn't reach zero, so both functions are defined and finite. Notice that both \( \sec x \) and \( \tan x \) approach infinity as x approaches \( \frac{\pi}{2} \).
02
Determine the Domain and Range
Since the interval is \( 0 < x < \frac{\pi}{2} \), there are no zeros in the denominator of either function, ensuring they remain defined throughout. The range is complex due to the combined behavior, but generally, the function \( y = \sec x + \tan x \) increases as \( x \) approaches \( \frac{\pi}{2} \). As \( x \to \frac{\pi}{2} \), both components increase towards infinity.
03
Analyze Behavior at Key Points
Evaluate the function at key points to determine behavior. At \( x \to 0^{+} \), \( \cos x \approx 1 \) and \( \sin x \approx 0 \), so \( \sec x \to 1 \) and \( \tan x \to 0 \), which gives \( y \approx 1 \). As \( x \to \frac{\pi}{2}^{-} \), \( \cos x \to 0 \), pushing \( \sec x \to \infty \) and \( \tan x \to \infty \), so \( y \to \infty \).
04
Sketch the Curve
Begin the sketch at \((0, y\approx 1)\), with the curve moving upwards as it approaches \(x = \frac{\pi}{2}\). The curve should show a steady increase, heading to infinity just before \(x = \frac{\pi}{2}\). This indicates a vertical asymptote at \(x = \frac{\pi}{2}\). Be sure to show that the curve starts close to 1 and rises smoothly.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Secant Function
The secant function, denoted as \( \sec x \), plays a crucial role in trigonometry. It is defined as the reciprocal of the cosine function, specifically \( \sec x = \frac{1}{\cos x} \). Understanding this definition is key, as it helps you see why the secant function is undefined wherever the cosine function equals zero. However, in the interval \( 0 < x < \frac{\pi}{2} \), the cosine function remains positive and non-zero, ensuring \( \sec x \) is well-defined.
When exploring the behavior of \( \sec x \), it's important to recognize its tendency to increase without bound as the angle \( x \) approaches points where \( \cos x \) approaches zero. This can be visualized clearly as \( x \) nears \( \frac{\pi}{2} \), causing \( \cos x \) to get very close to zero, and thus \( \sec x \) shoots up to positive infinity.
These characteristics make \( \sec x \) a fascinating function with unique properties beneficial in graph analysis.
When exploring the behavior of \( \sec x \), it's important to recognize its tendency to increase without bound as the angle \( x \) approaches points where \( \cos x \) approaches zero. This can be visualized clearly as \( x \) nears \( \frac{\pi}{2} \), causing \( \cos x \) to get very close to zero, and thus \( \sec x \) shoots up to positive infinity.
- The secant function is periodic with a period of \( 2\pi \).
- It is positive when the cosine is positive, aligning with intervals where \( \cos x > 0 \).
- The graph of \( \sec x \) exhibits vertical asymptotes at points where \( \cos x = 0 \), excluding these in the specified interval.
These characteristics make \( \sec x \) a fascinating function with unique properties beneficial in graph analysis.
Tangent Function
The tangent function, represented by \( \tan x \), is another pivotal concept in trigonometry, given by the ratio of the sine function to the cosine function: \( \tan x = \frac{\sin x}{\cos x} \). This definition inherently means that the tangent function is undefined wherever the cosine function becomes zero. Fortunately, in the desired interval \( 0 < x < \frac{\pi}{2} \), the cosine function is positive, making \( \tan x \) valid throughout.
As \( x \) approaches \( \frac{\pi}{2} \), \( \cos x \) gets progressively smaller, pushing \( \tan x \) towards infinity. At the lower end of the interval, where \( x \to 0^{+} \), the tangent starts at zero because \( \sin x \approx 0 \) and \( \cos x \approx 1 \).
The increasing trend of \( \tan x \) as \( x \) approaches \( \frac{\pi}{2} \) is crucial for sketching its curve accurately.
As \( x \) approaches \( \frac{\pi}{2} \), \( \cos x \) gets progressively smaller, pushing \( \tan x \) towards infinity. At the lower end of the interval, where \( x \to 0^{+} \), the tangent starts at zero because \( \sin x \approx 0 \) and \( \cos x \approx 1 \).
- The tangent function repeats every \( \pi \) interval, manifesting periodic characteristics over its domain.
- It is positive where both \( \sin x \) and \( \cos x \) share the same sign, notably in the first quadrant \( 0 < x < \frac{\pi}{2} \).
- Similarly to the secant function, \( \tan x \) will also show vertical asymptotes where \( \cos x = 0 \).
The increasing trend of \( \tan x \) as \( x \) approaches \( \frac{\pi}{2} \) is crucial for sketching its curve accurately.
Vertical Asymptotes
Vertical asymptotes are lines that a curve approaches but never touches or crosses. They often appear in trigonometric functions where there is a division by zero in the function's expression, causing the values to increase or decrease indefinitely. For expressions involving \( \sec x \) and \( \tan x \), vertical asymptotes occur at points where the cosine function, \( \cos x \), equals zero.
In our context of \( 0 < x < \frac{\pi}{2} \), the significant vertical asymptote to consider is at \( x = \frac{\pi}{2} \). As \( x \) closes in on \( \frac{\pi}{2} \), both \( \sec x \) and \( \tan x \) approach infinity due to the denominator \( \cos x \) reaching closer to zero.
Understanding vertical asymptotes is crucial for predicting and visualizing the behavior of trigonometric function curves accurately.
In our context of \( 0 < x < \frac{\pi}{2} \), the significant vertical asymptote to consider is at \( x = \frac{\pi}{2} \). As \( x \) closes in on \( \frac{\pi}{2} \), both \( \sec x \) and \( \tan x \) approach infinity due to the denominator \( \cos x \) reaching closer to zero.
- Vertical asymptotes are indicative of points where a function heads towards infinity either positively or negatively.
- While the curve is never able to reach or cross the asymptote, it provides a boundary that helps in shaping the curve's path.
- In a sketch, vertical asymptotes are represented using dashed lines, signifying their role as imaginary barriers.
Understanding vertical asymptotes is crucial for predicting and visualizing the behavior of trigonometric function curves accurately.