Chapter 4: Problem 32
\(23-46\) Find \(f\) $$f^{\prime}(x)=2 x-3 / x^{4}, \quad x>0, \quad f(1)=3$$
Short Answer
Expert verified
The function is \( f(x) = x^2 + x^{-3} + 1 \).
Step by step solution
01
Introduction to Integration
To find the function \( f(x) \), we need to integrate the derivative \( f'(x) \). Given that \( f'(x) = 2x - \frac{3}{x^4} \), we need to integrate each term separately.
02
Integrate the First Term
The first term is \( 2x \). The integral of \( 2x \) with respect to \( x \) is calculated using the power rule: \( \int 2x \, dx = x^2 + C_1 \).
03
Integrate the Second Term
For the second term, \( -\frac{3}{x^4} \) can be rewritten as \( -3x^{-4} \). The integral is: \( \int -3x^{-4} \, dx = -\frac{3}{-3}x^{-3} = x^{-3} + C_2 \).
04
Combine Integrals
Combine the results from Steps 2 and 3: \( \int f'(x) \, dx = x^2 + x^{-3} + C \), where \( C = C_1 + C_2 \) is the constant of integration.
05
Use Initial Condition
Apply the initial condition \( f(1) = 3 \) to solve for \( C \). Substitute \( x = 1 \) and \( f(1) = 3 \) into the equation: \( 1^2 + 1^{-3} + C = 3 \), simplifying gives \( 1 + 1 + C = 3 \), which results in \( C = 1 \).
06
Write the Final Function
Substitute the value of \( C \) back into the integrated function: \( f(x) = x^2 + x^{-3} + 1 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Power Rule
The power rule is a fundamental concept in integration and differentiation. It is used to find the integral of terms in the form of \( ax^n \). When you apply the power rule to integrate, you add 1 to the exponent of the power of \( x \), and then divide the term by the new exponent. For example, when integrating \( 2x \), the exponent of \( x \) is 1. By applying the power rule:
- Increase the exponent by 1 (from 1 to 2).
- Divide the coefficient by the new exponent: \( \frac{2}{2} = 1 \).
Initial Condition
An initial condition is a piece of additional information that allows us to determine the constant of integration in an indefinite integral. In practical scenarios, the initial condition often represents a specific value of the function for a particular \( x \) value. For example, in our exercise, the initial condition is given as \( f(1) = 3 \). This information helps us find the specific constant \( C \) needed to complete the definite form of the antiderivative. To apply the initial condition:
- Insert the given values into the integrated formula \( f(x) \).
- Solve for \( C \) using the provided condition.
Constant of Integration
When integrating a function, we need to include a constant of integration, usually represented by \( C \). This arises because integration is the inverse operation of differentiation, and the derivative of a constant is zero. Therefore, when finding an antiderivative, there could be an infinite number of functions that differ only by a constant. For instance, the integral of \( f'(x) \) could be \( f(x) = x^2 + x^{-3} + C \). Adding \( C \):
- Ensures that we account for all possible vertical shifts in the antiderivative.
- Allows the use of initial conditions to find a particular solution.
Indefinite Integral
The indefinite integral, also known as the antiderivative, is the reverse process of differentiation. It gives a broad set of functions that could have produced a given derivative. Indefinite integrals are expressed with an integral sign, function to be integrated, and differential \( dx \), along with a constant of integration. For a function \( f(x) \), its indefinite integral is written as:\[ \int f'(x) \, dx = F(x) + C \]Where \( F(x) \) represents the antiderivative and \( C \) is any real number, called the constant of integration. Key characteristics include:
- No upper and lower limits on the integral sign unlike a definite integral.
- Symbolically represents the set of all antiderivatives of the integrand.