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Suppose that 3\(\leqslant \mathrm{f}^{\prime}(\mathrm{x}) \leqslant 5\) for all values of \(\mathrm{x}\) . Show that \(18 \leqslant \mathrm{f}(8)-\mathrm{f}(2) \leqslant 30\)

Short Answer

Expert verified
Yes, 18 ≤ f(8) - f(2) ≤ 30, as shown by the Mean Value Theorem.

Step by step solution

01

Understand the meaning of f'(x)

The derivative \( f'(x) \) represents the slope or rate of change of the function \( f(x) \). Knowing that \( 3 \leqslant f'(x) \leqslant 5 \) implies that at any point between \( x = 2 \) and \( x = 8 \), \( f(x) \) is increasing at a rate between 3 and 5.
02

Apply the Mean Value Theorem

According to the Mean Value Theorem, there exists a point \( c \) in the interval \( (2,8) \) such that \( f'(c) = \frac{f(8) - f(2)}{8 - 2} \). This is known as the average rate of change, which has to be between 3 and 5 due to the given condition on \( f'(x) \).
03

Set up inequalities

Using the information from Step 2, we set up the inequality: \[ 3 \leqslant \frac{f(8) - f(2)}{6} \leqslant 5 \]
04

Solve the inequalities

To eliminate the fraction, multiply the entire inequality by 6: \[ 6 \times 3 \leqslant f(8) - f(2) \leqslant 6 \times 5 \] Simplify the inequality: \[ 18 \leqslant f(8) - f(2) \leqslant 30 \]
05

Conclusion

We have shown that the difference \( f(8) - f(2) \) is bounded between 18 and 30, satisfying the conditions given in the problem.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Derivative
The derivative is a fundamental concept in calculus. It shows how a function changes as its input changes. When we talk about the derivative of a function like \(f(x)\), we denote this by \(f'(x)\). The derivative represents the rate at which the value of the function is changing at any point. For example, if \(f'(x) = 3\), it means the function's value increases by 3 units for each unit rise in \(x\).
In the exercise, we know that \(3 \leq f'(x) \leq 5\). This tells us that the function's rate of change lies between 3 and 5 for all values of \(x\). This range of rates ensures that as \(x\) goes from 2 to 8, the function \(f(x)\) increases consistently but at different possible speeds—always between 3 and 5 units per unit increase in \(x\).
Inequalities
Inequalities are used to show relationships between expressions that are not equal. They help determine the range of possible values that a certain variable can take.
In the given exercise, we use the inequalities \(3 \leq f'(x) \leq 5\) to set boundaries for \(f(x)\). We apply these inequalities to solve for \(f(8) - f(2)\), resulting in \(18 \leq f(8) - f(2) \leq 30\). This means that, despite not knowing the exact values, we understand that the change in \(f(x)\) over the interval from 2 to 8 is restricted to lie within this range.
This bounding is important because it supports planning and estimation in real-world situations where exact values may not be available.
Rate of Change
The rate of change is essentially how fast or slow a quantity increases or decreases. It's about comparing how one quantity changes relative to another. In mathematics, the rate of change is often expressed through the derivative.
For the problem at hand, the rate of change of \(f\) is given by \(f'(x)\), bounded between 3 and 5. This indicates that for each increase in \(x\), the function \(f(x)\) grows between 3 and 5 units. The average rate of change across the interval from \(x=2\) to \(x=8\) is expressed by \(\frac{f(8) - f(2)}{6}\). This falls within the same bounded rate provided.
Understanding the rate of change is crucial for analyzing trends and predicting future behavior of functions in calculus.
Calculus
Calculus is an area of mathematics that focuses on change. Its two major branches are differential calculus and integral calculus. Differential calculus, which includes the study of derivatives, allows us to understand change locally—how a function behaves at each point.
In the context of this problem, differential calculus is central since we explore the derivative and the rate of change of \(f\). When you apply the Mean Value Theorem like we did here, you're leveraging a powerful tool of calculus. It tells us that even if we don't know every detail of \(f(x)\), we can still predict its behavior over an interval based on the average rate of change.
This problem illustrates how calculus doesn't just stop at computation; it's about understanding relationships and drawing conclusions based on known rates and behaviors.

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Most popular questions from this chapter

\(13-16\) Use Newton's method to approximate the indicated root of the equation correct to six decimal places. The root of \(x^{4}-2 x^{3}+5 x^{2}-6=0\) in the interval \([1,2]\)

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