/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 23 Sketch the graph of \(f\) by han... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Sketch the graph of \(f\) by hand and use your sketch to find the absolute and local maximum and minimum values of \(f .\) (Use the graphs and transformations of Sections 1.2 and \(1.3 .\) ) \(f(x)=\ln x, \quad 0< x \leqslant 2\)

Short Answer

Expert verified
Local minimum at (1, 0), absolute maximum at (2, \ln 2).

Step by step solution

01

Understanding the Function

The function given is \( f(x) = \ln x \). It is the natural logarithm function, which is defined for \( x > 0 \). The domain specified is \( 0 < x \leq 2 \). The natural logarithm function has a vertical asymptote at \( x = 0 \) and increases without bound as \( x \) increases.
02

Analyzing Behavior of \( f(x) \)

The natural logarithm function is continuous and increasing over its domain. It starts from negative infinity as \( x \to 0^+ \) (approaching from the right) and continues to increase, reaching \( \ln 2 \) when \( x = 2 \). Since the function is increasing on this interval, it doesn't dip or rise dramatically; it smoothly increases.
03

Sketching the Graph

To sketch \( f(x) = \ln x \) for \( 0 < x \leq 2 \), plot a curve starting near negative infinity just right of the origin and rising towards the value at \( x = 2 \), which is \( \ln 2 \). At \( x = 1 \), the value is \( \ln 1 = 0 \). These key points help in sketching: (1, 0) and (2, \( \ln 2 \)). The curve is always above the x-axis since \( \ln x \) is positive for \( x > 1 \).
04

Identifying Maximum and Minimum

Because \( \ln x \) is always increasing on \( 0 < x \leq 2 \), the lowest point in this interval is as we approach \( 0 \) from the right (approaching \(-\infty\)), but this is not in the domain set for our graph. At the endpoint \( x = 2 \), it attains its maximum on this interval at \( \ln 2 \). At \( x = 1 \), the value is \( 0 \). Thus, there's a local minimum at (1, 0) and an absolute maximum at (2, \ln 2).
05

Summarizing the Findings

From the sketch and analysis, we can conclude: the function does not have an absolute minimum in the provided domain since \( x \to 0^+ \) implies \( f(x) \to -\infty \). It has a local minimum at (1, 0). The absolute maximum value in the interval is \( \ln 2 \) at \( x = 2 \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Natural Logarithm Function
The natural logarithm function, often denoted as \( \ln x \), is a fundamental mathematical function that is particularly useful in calculus and real-world applications. It is the inverse of the exponential function \( e^x \). This means that if \( y = \ln x \), then \( x = e^y \). The function grows slowly compared to power functions.

The graph of \( \ln x \) only exists for positive values of \( x \) (meaning \( x > 0 \)). Its domain does not include zero or negative numbers. You'll notice that it crosses the x-axis at the point (1,0) because \( \ln 1 = 0 \). This serves as an anchor point for sketching its graph.

The key property of \( \ln x \) is that it increases as \( x \) increases, but this growth happens very gradually compared to linear or quadratic functions. This exponential relationship is what makes the natural logarithm so unique and applicable across various fields such as science, engineering, and finance.
Exploring Asymptote Behavior
An important concept in understanding graphs like that of \( \ln x \) is the notion of asymptotes. An asymptote is a line that the graph of a function approaches but never actually touches or crosses.

For the natural logarithm function \( \ln x \), there is a vertical asymptote at \( x = 0 \). This means that as \( x \) approaches zero from the right (denoted as \( x \to 0^+ \)), the value of \( \ln x \) decreases towards negative infinity. On a graph, you would see the curve getting closer to the y-axis but never intersecting it.

This asymptotic behavior is crucial in understanding the limits of \( \ln x \) and helps describe how the function behaves near its boundary. When sketching or analyzing such a function, asymptotes serve as guides for predicting and explaining the shape of the graph as it extends outwards from where it begins.
Recognizing Increasing Functions
The concept of an increasing function refers to a function that consistently rises as you move from left to right along the x-axis. The natural logarithm function \( \ln x \) is a classic example of an increasing function.

Over its domain \( (0, \infty) \), \( \ln x \) is strictly increasing. This means that if \( x_1 < x_2 \) then \( \ln x_1 < \ln x_2 \). This property indicates that there are no dips or peaks within its continuous curve. The effects of an increasing function can be visually seen when sketching a graph; the slope of the curve continually rises without any downward turn.

Understanding this characteristic helps in determining maximum and minimum values in specific intervals. Within the interval \( 0 < x \leq 2 \), the function retains its increasing nature, meaning it doesn’t change direction. This plays an essential role in concluding whether the function has a local or absolute extremum at given points.
Identifying Local Minima and Maxima
Local minimum and maximum values help us understand the turning points within a graph. For \( f(x) = \ln x \), finding these extrema is simplified by its increasing nature. Always pay close attention to the domain provided.

In the specific interval \( 0 < x \leqslant 2 \), the function does not have an absolute minimum because approaching \( x \to 0^+ \) leads \( f(x) \to -\infty \). Instead, \( x = 1 \) provides a local minimum with a value of 0, as this is the lowest point connected to the defined positive section of the domain.

The absolute maximum within the mentioned domain occurs at \( x = 2 \) with \( f(x) = \ln 2 \). The conclusion comes from analyzing the graph and how it behaves at specified points, which is crucial for clear determination of how the graph behaves and where its peaks and troughs occur.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A high-speed bullet train accelerates and decelerates at the rate of 4 \(\mathrm{ft} / \mathrm{s}^{2} .\) Its maximum cruising speed is 90 \(\mathrm{mi} / \mathrm{h}\) . (a) What is the maximum distance the train can travel if it accelerates from rest until it reaches its cruising speed and then runs at that speed for 15 minutes? (b) Suppose that the train starts from rest and must come to a complete stop in 15 minutes. What is the maximum distance it can travel under these conditions? (c) Find the minimum time that the train takes to travel between two consecutive stations that are 45 miles apart. (d) The trip from one station to the next takes 37.5 minutes. How far apart are the stations?

Describe how the graph of \(f\) varies as \(c\) varies. Graph several members of the family to illustrate the trends that you discover. In particular, you should investigate how maximum and minimum points and inflection points move when c changes. You should also identify any transitional values of \(c\) at which the basic shape of the curve changes. \(f(x)=x \sqrt{c^{2}-x^{2}}\)

During the summer months Terry makes and sells necklaces on the beach. Last summer he sold the necklaces for \(\$ 10\) each and his sales averaged 20 per day. When he increased the price by \(\$ 1 ,\) he found that the average decreased by two sales per day. (a) Find the demand function, assuming that it is linear. (b) If the material for each necklace costs Terry S6, what should the selling price be to maximize his profit?

If an object with mass \(m\) is dropped from rest, one model for its speed \(v\) after \(t\) seconds, taking air resistance into account, is $$v=\frac{m g}{c}\left(1-e^{-c t / m}\right)$$ where \(g\) is the acceleration due to gravity and \(c\) is a positive constant. (In Chapter 9 we will be able to deduce this equa- tion from the assumption that the air resistance is propor- tional to the speed of the object; \(c\) is the proportionality constant.) (a) Calculate \(\lim _{t \rightarrow \infty} v\) What is the meaning of this limit? (b) For fixed t, use I'Hospital's Rule to calculate \(\lim _{\mathrm{c} \rightarrow 0^{+}} v\) What can you conclude about the velocity of a falling object in a vacuum?

Use a computer algebra system to graph \(f\) and to find \(f^{\prime}\) and \(f^{\prime \prime} .\) Use graphs of these derivatives to estimate the intervals of increase and decrease, extreme values, intervals of concavity, and inflection points of \(f\). \(f(x)=\frac{x^{2 / 3}}{1+x+x^{4}}\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.