/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 59 Find all points on the graph of ... [FREE SOLUTION] | 91Ó°ÊÓ

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Find all points on the graph of the function \(f ( x ) = 2 \sin x + \sin ^ { 2 } x\) at which the tangent line is horizontal.

Short Answer

Expert verified
The tangent is horizontal at \(x = \frac{\pi}{2} + n\pi\) and \(x = \frac{3\pi}{2} + 2n\pi\), where \(n\) is an integer.

Step by step solution

01

Understand the problem

The problem requires us to find points on the function where the tangent line is horizontal. A tangent line is horizontal when its slope is zero.
02

Find the derivative of the function

We need to differentiate the function \(f(x) = 2\sin x + \sin^2 x\) to find its slope. Using the chain rule and basic derivatives, we have: \(f'(x) = d/dx[2\sin x] + d/dx[\sin^2 x] = 2\cos x + 2\sin x \cdot \cos x\).
03

Solve for when the derivative is zero

Set the derivative equal to zero and solve for \(x\): \(2\cos x + 2\sin x \cdot \cos x = 0\). Factor out \(2\cos x\): \(2\cos x(1 + \sin x) = 0\). This gives two potential solutions: \(2\cos x = 0\) and \(1 + \sin x = 0\).
04

Solve each equation

For \(2\cos x = 0\), we have \(\cos x = 0\). Thus, \(x = \frac{\pi}{2} + n\pi\) where \(n\) is an integer.For \(1 + \sin x = 0\), we have \(\sin x = -1\). Thus, \(x = \frac{3\pi}{2} + 2n\pi\) where \(n\) is an integer.
05

Combine solutions

The solutions \(x = \frac{\pi}{2} + n\pi\) and \(x = \frac{3\pi}{2} + 2n\pi\) cover all points where the tangent line is horizontal. These need to be confirmed as solutions by substituting back if needed.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

sine function
The sine function, denoted as \( \sin x \), is a fundamental trigonometric function. It describes the ratio of the opposite side to the hypotenuse in a right-angled triangle. The sine function has a periodic nature, repeating its values in regular intervals known as its period, which is \( 2\pi \) for the sine function.
Knowing the sine function is crucial in understanding many mathematical and physical phenomena, including waves and oscillations.
  • The range of \( \sin x \) is between \(-1\) and \(1\).
  • The function is continuous and smooth, with smooth transitions across its entire range.
  • It exhibits symmetry known as odd symmetry, satisfying \( \sin(-x) = -\sin(x) \).
  • Critical points within one period are \(x = 0\), \(x = \pi/2\), \(x = \pi\), \(x = 3\pi/2\), and \(x = 2\pi\).
In the exercise, grasping the behavior of the sine function helps us solve for horizontal tangents where the function's rate of change is zero.
chain rule
The chain rule is a fundamental principle in calculus used for differentiating composite functions. When a function is composed of two or more functions, the chain rule is applied to determine its derivative. The formula for the chain rule involves taking the derivative of the outer function and multiplying it by the derivative of the inner function.
For example, in differentiating \(\sin^2 x\), consider it as \((\sin x)^2\):
  • Outer function: \(x^2\)
  • Inner function: \(\sin x\)
According to the chain rule, the derivative is: \(2 \sin x \cdot \cos x\).
Applying the chain rule is essential for accurately finding the slope of the tangent line in composite functions, as seen in the exercise.
differentiation
Differentiation is the process of finding the derivative of a function. The derivative represents the function's rate of change, often interpreted as the slope of the tangent line at any given point on the graph.
In this exercise, differentiation is employed to identify points on the function where the slope is zero, indicating horizontal tangents.
When differentiating \(f(x) = 2\sin x + \sin^2 x\), the individual components \(2\sin x\) and \(\sin^2 x\) are differentiated separately. The basic rules of differentiation and trigonometric identities like the derivative of \(\sin x\), which is \(\cos x\), are applied.
  • Derivative of \(2 \sin x\): \(2 \cos x\)
  • Derivative of \(\sin^2 x\) utilizing the chain rule: \(2 \sin x \cdot \cos x\)
Differentiation enables us to formulate the equation \(2 \cos x + 2 \sin x \cdot \cos x = 0\), essential for finding solutions.
trigonometric equations
Trigonometric equations involve trigonometric functions like sine, cosine, and tangent in the context of equations that need solving. Solving these equations often requires knowledge of trigonometric identities and properties.
In the exercise, the trigonometric equation derived from the derivative is \(2 \cos x(1 + \sin x) = 0\). This equation is solved by breaking it down into simpler parts:
  • \(2 \cos x = 0\), leading to \(\cos x = 0\) and solutions \(x = \frac{\pi}{2} + n\pi\) (where \(n\) is an integer).
  • \(1 + \sin x = 0\), leading to \(\sin x = -1\) and solutions \(x = \frac{3\pi}{2} + 2n\pi\) (where \(n\) is an integer).
Mastering the solution of such equations involves identifying the general solution across all possible values of \(x\), acknowledging its periodicity and symmetry of trigonometric functions.

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Most popular questions from this chapter

The frequency of vibrations of a vibrating violin string is given by $$\mathrm{f}=\frac{1}{2 \mathrm{L}} \sqrt{\frac{\mathrm{T}}{\rho}}$$ where \(L\) is the length of the string, T is its tension, and \(\rho\) is its linear density. [See Chapter 11 in D. E. Hall, Musical Acoustics, 3 \(\mathrm{d}\) ed. (Pacific Grove, CA: Brooks/Cole, \(2002 ) . ]\) (a) Find the rate of change of the frequency with respect to (i) the length (when T and \(\rho\) are constant), (ii) the tension (when L and \(\rho\) are constant), and (iii) the linear density (when L and T are constant). (b) The pitch of a note (how high or low the note sounds) is determined by the frequency f. (The higher the frequency, the higher the pitch.) Use the signs of the derivatives in part (a) to determine what happens to the pitch of a note (i) when the effective length of a string is decreased by placing a finger on the string so a shorter portion of the string vibrates, (ii) when the tension is increased by turning a tuning peg. (iii) when the linear density is increased by switching to another string.

\(37-48\) Use logarithmic differentiation to find the derivative of the function. $$y=(\sin x)^{\ln x}$$

Use the Chain Rule and the Product Rule to give an altermative proof of the Quotient Rule. $$\left[ Hint: Write f ( x ) / g ( x ) = f ( x ) [ g ( x ) ] ^ { - 1 } . \right]$$

A telephone line hangs between two poles 14 \(\mathrm{m}\) apart in the shape of the catenary \(y=20 \cosh (x / 20)-15,\) where \(x\) and y are measured in meters. $$\begin{array}{l}{\text { (a) Find the slope of this curve where it meets the right pole. }} \\ {\text { (b) Find the angle } \theta \text { between the line and the pole. }}\end{array}$$

Use the Chain Rule to show that if \(\theta\) is measured in degrees, then $$\frac { d } { d \theta } ( \sin \theta ) = \frac { \pi } { 180 } \cos \theta$$ This gives one reason for the convention that radian measure is always used when dealing with trigonometric functions in calculus: The differentiation formulas would not be as simple if we used degree measure.)

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