Chapter 3: Problem 44
\(\begin{array}{l}{\text { Suppose that } f(2)=-3, g(2)=4, f^{\prime}(2)=-2, \text { and }} \\ {g^{\prime}(2)=7 . \text { Find } h^{\prime}(2)}.\end{array}\) $$ { (a) } h(x)=5 f(x)-4 g(x) \quad \text { (b) } h(x)=f(x) g(x)$$ $$ { (c) } h(x)=\frac{f(x)}{g(x)} \quad \text { (d) } h(x)=\frac{g(x)}{1+f(x)}$$
Short Answer
Step by step solution
Understand the Problem
Step 2a: Find \( h'(2) \) for \( h(x) = 5f(x) - 4g(x) \)
Step 2b: Find \( h'(2) \) for \( h(x) = f(x)g(x) \)
Step 2c: Find \( h'(2) \) for \( h(x) = \frac{f(x)}{g(x)} \)
Step 2d: Find \( h'(2) \) for \( h(x) = \frac{g(x)}{1+f(x)} \)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Derivative Rules
There are several derivative rules that are important to understand:
- **Constant Rule:** If a function is a constant, its derivative is zero. For example, if \( c \) is a constant, then \( \frac{d}{dx}(c) = 0 \).
- **Power Rule:** For a function \( f(x) = x^n \), the derivative is \( f'(x) = nx^{n-1} \).
- **Linearity of Derivatives:** The derivative of a sum or difference of functions can be broken down as the sum or difference of their derivatives. For example, \( \frac{d}{dx}(af(x) + bg(x)) = af'(x) + bg'(x) \) where \( a \) and \( b \) are constants.
- **Special Functions:** Trigonometric, exponential, and logarithmic functions have their own unique derivatives. For example, \( \frac{d}{dx}(e^x) = e^x \) and \( \frac{d}{dx} \ln(x) = \frac{1}{x} \).
Product Rule
If you have two functions, \( f(x) \) and \( g(x) \), the product rule states:\[ (fg)' = f'g + fg' \]This is important because, unlike sums, the derivative of a product isn't simply the product of the individual derivatives due to the interaction between the two functions.
To apply this in practice, you follow these steps:
- Differentiate the first function \( f(x) \) to get \( f'(x) \).
- Keep the second function \( g(x) \) as it is.
- Then, differentiate the second function \( g(x) \) to get \( g'(x) \).
- Keep the first function \( f(x) \) as it is.
- Finally, add the two results: \( f'(x)g(x) + f(x)g'(x) \).
Quotient Rule
If you have two functions, \( f(x) \) and \( g(x) \), the quotient rule formula is:\[ \left(\frac{f}{g}\right)' = \frac{f'g - fg'}{g^2} \]This rule helps ensure the correct differentiation of a ratio of functions, capturing both numerator and denominator influences.
Here's how you can apply the quotient rule:
- Differentiate the numerator \( f(x) \) to get \( f'(x) \).
- Differentiate the denominator \( g(x) \) to get \( g'(x) \).
- Multiply \( f'(x) \) by \( g(x) \) and \( f(x) \) by \( g'(x) \).
- Subtract the second product from the first: \( f'(x)g(x) - f(x)g'(x) \).
- Divide this difference by the square of the denominator \( g(x)^2 \).
Chain Rule
For a composite function \( g(f(x)) \), the chain rule is written as:\[ (g(f(x)))' = g'(f(x)) \cdot f'(x) \]This means you first differentiate the outer function \( g \) evaluated at the inner function \( f(x) \), and then multiply by the derivative of the inner function \( f(x) \).
When applying this rule:
- Identify the outer function, \( g \), and differentiate it to find \( g' \).
- Identify the inner function, \( f(x) \), and differentiate it to find \( f'(x) \).
- Substitute \( f(x) \) into the differentiated outer function, and multiply by \( f'(x) \).