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\(3-26\) Differentiate. $$f(x)=\frac{a x+b}{c x+d}$$

Short Answer

Expert verified
The derivative is \( f'(x) = \frac{ad - bc}{(cx + d)^2} \).

Step by step solution

01

Understand the problem

We need to find the derivative of the function \( f(x) = \frac{a x + b}{c x + d} \). This function is in the form of a quotient \( \frac{u}{v} \), where \( u = ax + b \) and \( v = cx + d \).
02

Identify the differentiation rule

Since \( f(x) \) is a quotient, we will use the quotient rule for differentiation, which states: If \( f(x) = \frac{u}{v} \), then \( f'(x) = \frac{u'v - uv'}{v^2} \).
03

Differentiate the numerator and denominator

First, compute the derivatives of the numerator and the denominator: \( u = ax + b \Rightarrow u' = a \) (as the derivative of a linear function is the coefficient) and \( v = cx + d \Rightarrow v' = c \).
04

Apply the quotient rule

Plug in the derivatives into the quotient rule: \[ f'(x) = \frac{(a)(cx + d) - (ax + b)(c)}{(cx + d)^2} \].
05

Simplify the expression

Expand and simplify the expression: \[ f'(x) = \frac{acx + ad - acx - bc}{(cx + d)^2} \]. The \( acx \) terms cancel out, yielding: \[ f'(x) = \frac{ad - bc}{(cx + d)^2} \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quotient Rule
The quotient rule is a fundamental technique in calculus used to differentiate functions that are expressed as a fraction of two other functions. Imagine you have a function written as a quotient like \( f(x) = \frac{u}{v} \). Here, \( u \) and \( v \) are both differentiable functions of \( x \).
When we want to find the derivative of such a function, we use the quotient rule which states:
  • First, take the derivative of the numerator \( u \) to get \( u' \).
  • Next, take the derivative of the denominator \( v \) to get \( v' \).
  • Then apply the formula for the derivative: \( f'(x) = \frac{u'v - uv'}{v^2} \).
This formula is derived from the limit definition of a derivative and helps us efficiently find the derivative without directly applying complex algebraic methods.
It is essential in calculus whenever you encounter a quotient of functions as it simplifies the process and ensures accuracy.
Linear Function Differentiation
A linear function in its simplest form can be expressed as \( u(x) = ax + b \). This is a straight line graph where \( a \) is the slope and \( b \) is the y-intercept.
Differentiating a linear function is simple and straightforward:
  • Take the derivative of \( ax + b \), which is simply \( a \).
  • This means the rate of change of the linear function is constant and equal to the slope \( a \).
This differs from other functions, like quadratics or polynomials, where the derivative involves reducing powers.
In our exercise, both the numerator and the denominator of the function form linear functions \( u = ax + b \) and \( v = cx + d \). Thus, their derivatives are \( u' = a \) and \( v' = c \) respectively. With such functions, this simple linear differentiation proceeds seamlessly into more complex processes like applying the quotient rule.
Derivative of a Quotient
To find the derivative of a quotient of two functions, like \( f(x) = \frac{u}{v} \), you combine both the quotient rule and the process of linear differentiation.
In the exercise, the function to differentiate is \( f(x) = \frac{ax+b}{cx+d} \). This makes \( u = ax + b \) and \( v = cx + d \).
First, differentiate each component:
  • The derivative of the numerator is \( u' = a \).
  • The derivative of the denominator is \( v' = c \).
Using the quotient rule, the derivative is:
\[ f'(x) = \frac{(a)(cx + d) - (ax + b)(c)}{(cx + d)^2} \] Expand and simplify this to:
\[ f'(x) = \frac{ad - bc}{(cx + d)^2} \] This expression shows the rate of change of the quotient function.
Simplifying correctly is crucial to understanding internal cancellations like \( acx - acx \), which help to streamline the derivative.

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Most popular questions from this chapter

If \(p(x)\) is the total value of the production when there are \(x\) workers in a plant, then the average productivity of the workforce at the plant is $$A(x)=\frac{p(x)}{x}$$ (a) Find \(A^{\prime}(x) .\) Why does the company want to hire more workers if \(A^{\prime}(x)>0 ?\) (b) Show that \(A^{\prime}(x)>0\) if \(p^{\prime}(x)\) is greater than the average productivity.

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