/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 23 \(3-32\) Differentiate the funct... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

\(3-32\) Differentiate the function. \(y=\frac{x^{2}+4 x+3}{\sqrt{x}}\)

Short Answer

Expert verified
The derivative is \( y' = \frac{3}{2}x^{1/2} + 2x^{-1/2} - \frac{3}{2}x^{-3/2} \).

Step by step solution

01

Rewrite the Function

First, rewrite the function so that it's easier to differentiate. You begin with \( y = \frac{x^2 + 4x + 3}{\sqrt{x}} \), which can be rewritten as \( y = \frac{x^2}{\sqrt{x}} + \frac{4x}{\sqrt{x}} + \frac{3}{\sqrt{x}} \). Simplifying, the expression becomes \( y = x^{3/2} + 4x^{1/2} + 3x^{-1/2} \). This makes it easier to apply standard differentiation rules for each term.
02

Differentiate Term by Term

Apply the power rule to differentiate each term. For \( x^{3/2} \), the derivative is \( \frac{3}{2}x^{1/2} \). For \( 4x^{1/2} \), the derivative is \( 2x^{-1/2} \). For \( 3x^{-1/2} \), the derivative is \( -\frac{3}{2}x^{-3/2} \).
03

Combine the Derivatives

Combine the derivatives from each term to get the derivative of the entire function. Thus, the derivative \( y' \) is given by:\[ y' = \frac{3}{2}x^{1/2} + 2x^{-1/2} - \frac{3}{2}x^{-3/2} \]. This is the final differentiated form of the given function.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Power Rule
The power rule is a fundamental tool in calculus used to differentiate functions of the form \( x^n \), where \( n \) is any real number.
It's a simple yet powerful method that states: to find the derivative of \( x^n \), multiply the power by the coefficient and then subtract one from the power.
This can be expressed as: \[ \frac{d}{dx}x^n = nx^{n-1}\] Let's consider how the power rule applies to our example. After rewriting the function \( y = x^{3/2} + 4x^{1/2} + 3x^{-1/2} \), the power rule allows us to differentiate each term individually:
  • For \( x^{3/2} \), the derivative is \( \frac{3}{2}x^{1/2} \).
  • For \( 4x^{1/2} \), we have the derivative \( 2x^{-1/2} \).
  • For \( 3x^{-1/2} \), we find \( -\frac{3}{2}x^{-3/2} \).
Using the power rule simplifies the process of differentiation especially when dealing with polynomial terms indicated by different exponents.
Derivative
A derivative represents the rate at which a function is changing at any given point.
It's essentially the function's slope or steepness at specific points along its curve.
This is vital for understanding how functions behave, especially in the context of physics, engineering, and economics.
In essence, calculating a derivative helps gauge how a small change in \( x \) influences \( y \). In our example with the function \( y = \frac{x^2 + 4x + 3}{\sqrt{x}} \), finding \( y' \) means determining how the value of \( y \) changes with \( x \).
The process of differentiation involves using rules like the power rule, as applied in our solution:
  • Step by step differentiation of terms \( x^{3/2}, 4x^{1/2}, \text{and } 3x^{-1/2} \) gives us insight about their respective rates of change.
  • These individual derivatives are then combined into one expression to describe the overall rate of change for the entire function.
Derivatives are crucial for predicting behavior and understanding trends in various functions.
Simplifying Expressions
Simplifying expressions is an essential technique in calculus that makes the process of differentiation much more manageable.
The primary goal is to transform the function into a simpler form that is easier to work with.
In our exercise, we start with a relatively complex form: \( y = \frac{x^2 + 4x + 3}{\sqrt{x}} \). By simplifying each term separately:
  • Convert \( \frac{x^2}{\sqrt{x}} \) into \( x^{3/2} \).
  • Turn \( \frac{4x}{\sqrt{x}} \) into \( 4x^{1/2} \).
  • Simplify \( \frac{3}{\sqrt{x}} \) as \( 3x^{-1/2} \).
This results in an expression, \( y = x^{3/2} + 4x^{1/2} + 3x^{-1/2} \), which is far more straightforward for applying differentiation techniques.
Simplifying expressions not only expedites differentiation but also reduces the likelihood of errors. By having a tidy form, using rules like the power rule becomes much simpler and more direct.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Water is leaking out of an inverted conical tank at a rate of \(10,000 \mathrm{cm}^{3} / \mathrm{min}\) at the same time that water is being pumped into the tank at a constant rate. The tank has height 6 \(\mathrm{m}\) and th diameter at the top is 4 \(\mathrm{m} .\) If the water level is rising at a rate of 20 \(\mathrm{cm} / \mathrm{min}\) when the height of the water is \(2 \mathrm{m},\) find the rate at which water is being pumped into the tank.

\(37-48\) Use logarithmic differentiation to find the derivative of the function. $$y=(\cos x)^{x}$$

The gas law for an ideal gas at absolute temperature T (in kelvins), pressure \(P\) (in atmospheres), and volume \(V\) ( in liters) is \(P V=n R T\) , where \(n\) is the number of moles of the gas and \(R=0.0821\) is the gas constant. Suppose that, at a certain instant, \(\mathrm{P}=8.0\) atm and is increasing at a rate of 0.10 atm/min and \(\mathrm{V}=10 \mathrm{L}\) and is decreasing at a rate of 0.15 \(\mathrm{L} / \mathrm{min}\) . Find the rate of change of \(\mathrm{T}\) with respect to time at that instant if \(\mathrm{n}=10 \mathrm{mol} .\)

Establish the following rules for working with differentials (where c denotes a constant and u and \(v\) are functions of \(x )\) . (a) \(\mathrm{dc}=0\) $$ \mathrm{d}(\mathrm{u}+v)=\mathrm{du}+\mathrm{d} v \quad \text { (d) } \mathrm{d}(\mathrm{u} v)=\mathrm{u} \mathrm{d} v+v $$ $$ \mathrm{d}\left(\frac{\mathrm{u}}{v}\right)=\frac{v \mathrm{du}-\mathrm{u} \mathrm{d} v}{v^{2}} \quad \text { (f) } \mathrm{d}\left(\mathrm{x}^{\mathrm{n}}\right)=\mathrm{nx}^{\mathrm{n}-1} \mathrm{d} \mathrm{x} $$

Find the derivative. Simplify where possible. $$f(t)=\operatorname{sech}^{2}\left(e^{t}\right)$$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.