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I-6 Write the composite function in the form \(f ( g ( x ) )\) . Ildentify the inner function \(u = g ( x )\) and the outer function \(y = f ( u ) .1\) Then find the derivative \(d y / d x\) $$y = \sqrt { 4 + 3 x }$$

Short Answer

Expert verified
The inner function is \( g(x) = 4 + 3x \) and the outer function is \( f(u) = \sqrt{u} \). The derivative is \( \frac{dy}{dx} = \frac{3}{2\sqrt{4 + 3x}} \).

Step by step solution

01

Identify the Composite Function Structure

The given function is \( y = \sqrt{4 + 3x} \). This can be expressed in composite function form as \( f(g(x)) \). The task is to determine what \( g(x) \) and \( f(u) \) are.
02

Identify the Inner Function

The inner function \( g(x) \) is the function inside the square root. Therefore, \( g(x) = 4 + 3x \). This represents the expression that is substituted into another function.
03

Identify the Outer Function

The outer function \( f(u) \) is applied to the result of \( g(x) \). Given \( y = \sqrt{u} \), the outer function becomes \( f(u) = \sqrt{u} \). Here, \( u \) is the substitution that represents the output from \( g(x) \).
04

Find the Derivative \(\frac{dy}{dx}\)

To find the derivative \( \frac{dy}{dx} \), apply the chain rule, which states \( \frac{dy}{dx} = \frac{dy}{du} \cdot \frac{du}{dx} \). First, find \( \frac{dy}{du} \). For \( f(u) = \sqrt{u} \), \( \frac{dy}{du} = \frac{1}{2\sqrt{u}} \). Then, find \( \frac{du}{dx} \). For \( g(x) = 4 + 3x \), \( \frac{du}{dx} = 3 \).
05

Apply the Chain Rule

Combine the derivatives to find \( \frac{dy}{dx} \):\[\frac{dy}{dx} = \frac{1}{2\sqrt{u}} \cdot 3 = \frac{3}{2\sqrt{u}}\]Substitute back \( u = 4 + 3x \) to get the final derivative:\[\frac{dy}{dx} = \frac{3}{2\sqrt{4 + 3x}}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chain Rule in Calculus
The Chain Rule is an essential tool for taking derivatives of composite functions. When you have a function nested inside another function, the Chain Rule is your go-to strategy to find how fast something is changing. Think of it like peeling the layers of an onion. To use the Chain Rule, you compute the derivative of the outer function and multiply it by the derivative of the inner function.

In math language, if you have a function written as a composition, such as \( f(g(x)) \), the Chain Rule tells you that the derivative \( \frac{dy}{dx} = \frac{dy}{du} \cdot \frac{du}{dx} \). Here:
  • \( \frac{dy}{du} \) is the derivative of the outer function.
  • \( \frac{du}{dx} \) is the derivative of the inner function.
By multiplying these derivatives, you get the overall rate of change for the composite function!Let's break it down further with the function \( y = \sqrt{4 + 3x} \). Here, you'll use the Chain Rule by first identifying the derivative of the outer and inner functions separately before combining them.
Understanding Derivatives
Derivatives are like math's way of saying how something is changing at any point. They tell us how a function behaves as its input changes. It’s like checking the speed of a car at every moment.

When you differentiate a function, you follow certain rules to find that derivative. One such rule is the Chain Rule we talked about. In our exercise, we started with the function \( y = \sqrt{4 + 3x} \).

You need derivatives of:
  • \( f(u) = \sqrt{u} \) which differentiates to \( \frac{dy}{du} = \frac{1}{2\sqrt{u}} \).
  • \( g(x) = 4 + 3x \) which differentiates to \( \frac{du}{dx} = 3 \).
The Chain Rule helps you combine these derivatives, leading to \( \frac{dy}{dx} = \frac{3}{2\sqrt{4 + 3x}} \). This gives the rate at which \( y \) changes with respect to \( x \). Each function step contributes a small part to the overall change!
Function Composition
Function composition is the process of combining two (or more) functions to form a new function. In simpler terms, it's like plugging one function into another.

For example, let’s say you have:
  • Inner function \( g(x) = 4 + 3x \).
  • Outer function \( f(u) = \sqrt{u} \).
In function composition, the inner function \( g(x) \) plugs into the outer function \( f(u) \), resulting in the composite function \( f(g(x)) = \sqrt{4 + 3x} \).

This is seen as ‘function inside another function’ and commonly represented as \( f(g(x)) \). Understanding how to express a problem this way is crucial because it allows us to apply tools like the Chain Rule effectively.
Inner and Outer Functions
An essential part of understanding composite functions is knowing the roles of inner and outer functions. Think of them as different layers of a function.

The **inner function** is often nested within another and is the first to be applied. In our example, \( g(x) = 4 + 3x \), which is inside the square root, represents the inner function. It acts as a foundation for the outer function.

The **outer function**, on the other hand, is the one that surrounds the inner function. For \( y = \sqrt{4 + 3x} \), \( f(u) = \sqrt{u} \) represents the outer function. It dictates how the output of the inner function is processed further.

Understanding these roles helps you manipulate and work with composite functions, whether you’re differentiating or just analyzing their behavior. The process of identifying these parts prepares you for applying the Chain Rule effectively, making your calculus journey smoother.

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Most popular questions from this chapter

$$ \begin{array}{l}{\text { The circumference of a sphere was measured to be } 84 \mathrm{cm}} \\ {\text { with a possible error of } 0.5 \mathrm{cm} .} \\\ {\text { (a) Use differentials to estimate the maximum error in the }} \\\ {\text { calculated surface area. What is the relative error? }} \\ {\text { (b) Use differentials to estimate the maximum error in the }} \\ {\text { calculated volume. What is the relative error? }}\end{array} $$

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