Chapter 3: Problem 16
\(3-32\) Differentiate the function. \(B(y)=c y^{-6}\)
Short Answer
Expert verified
The derivative of the function is \( B'(y) = -6c y^{-7} \).
Step by step solution
01
Identify the Function and Constant
The given function is \( B(y) = c y^{-6} \). Here, \( c \) is considered a constant and \( y^{-6} \) is the part of the function we will differentiate with respect to \( y \).
02
Differentiate the Power Function
Use the power rule for differentiation, which states that \( \frac{d}{dy} [y^n] = n y^{n-1} \). For \( y^{-6} \), applying the power rule gives \( \frac{d}{dy} [y^{-6}] = -6 y^{-7} \).
03
Apply the Constant Multiple Rule
The constant multiple rule states that if there is a constant multiplied by a function, its derivative can be found by multiplying the constant by the derivative of the function. Apply this rule: \( \frac{d}{dy} [c y^{-6}] = c \cdot (-6 y^{-7}) \).
04
Simplify the Expression
Multiply the constant \( c \) with \( -6 y^{-7} \) to obtain the derivative: \( B'(y) = -6c y^{-7} \). Thus, the differentiated form of the function is \( B'(y) = -6c y^{-7} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Power Rule in Differentiation
The power rule is a basic yet powerful tool in calculus for differentiating functions of the form \( y^n \). It simplifies the process by providing a straightforward formula: \( \frac{d}{dy}[y^n] = n y^{n-1} \). This rule is especially useful when dealing with polynomial functions, as it allows for quick computation of derivatives without complex procedures. In our exercise, the function is \( y^{-6} \), where the exponent is \(-6\). Using the power rule, the derivative becomes \(-6 y^{-7} \):
- Bring down the exponent as a coefficient.
- Reduce the exponent by one.
Constant Multiple Rule in Calculus
The constant multiple rule simplifies differentiating functions that include a constant coefficient. It states that if a function is multiplied by a constant, you can differentiate by multiplying the constant with the derivative of the function itself. For instance, consider a function \( f(y) = c \cdot y^n \). Its derivative can be quickly found as \( c \cdot \frac{d}{dy}[y^n] \).
In our given example, the function is \( B(y) = c y^{-6} \). We've already determined the derivative of \( y^{-6} \) to be \(-6 y^{-7} \). By using the constant multiple rule, we multiply this result by \( c \), which gives us \( -6c y^{-7} \). This rule helps ensure we maintain accuracy while simplifying calculations.
In our given example, the function is \( B(y) = c y^{-6} \). We've already determined the derivative of \( y^{-6} \) to be \(-6 y^{-7} \). By using the constant multiple rule, we multiply this result by \( c \), which gives us \( -6c y^{-7} \). This rule helps ensure we maintain accuracy while simplifying calculations.
Solving Calculus Problems with Differentiation
Differentiation plays a crucial role in solving calculus problems, as it provides insights into the rate of change of functions. When faced with a calculus problem requiring differentiation, it's essential to:
1. Applying the power rule to \( y^{-6} \) to get \(-6y^{-7}\).2. Utilizing the constant multiple rule to include \( c \).3. Combining these steps to simplify the derivative as \( B'(y) = -6c y^{-7} \).By following a structured approach, you can tackle even complex calculus problems with ease and confidence.
- Identify the function and any constants involved.
- Apply the appropriate differentiation rules (e.g., power rule, constant multiple rule).
- Simplify the result to its most basic form.
1. Applying the power rule to \( y^{-6} \) to get \(-6y^{-7}\).2. Utilizing the constant multiple rule to include \( c \).3. Combining these steps to simplify the derivative as \( B'(y) = -6c y^{-7} \).By following a structured approach, you can tackle even complex calculus problems with ease and confidence.