Chapter 2: Problem 6
Sketch the graph of a function that has a jump discontinuity at \(x=2\) and a removable discontinuity at \(x=4,\) but is continuous elsewhere.
Short Answer
Expert verified
Sketch a piecewise function: add jump at x=2, hole at x=4.
Step by step solution
01
Understand the Types of Discontinuities
A jump discontinuity is where a function has a sudden "jump" at a certain point. This means the left-hand limit and right-hand limit at that point do not equal each other. Meanwhile, a removable discontinuity occurs where a function is not continuous at a point, but can be made continuous by properly defining the function's value at that point.
02
Choose a Basic Continuous Function
Start with a basic continuous function that is easy to manipulate, such as a linear function. For simplicity, let's choose the function \( f(x) = x \) over the domain \( x eq 2 \) and \( x eq 4 \).
03
Introduce the Jump Discontinuity at \(x=2\)
Modify the function at \( x=2 \). Let’s define \( f(x) \) for \( x=2 \) such that the left-hand limit and right-hand limit are different. For example, let’s choose \( f(x) = x + 1 \) for \( x < 2 \) and \( f(x) = x - 1 \) for \( x > 2 \). This causes a jump of 2 units vertically at \( x=2 \).
04
Introduce the Removable Discontinuity at \(x=4\)
To create a removable discontinuity at \( x=4 \), we define the function value \( f(x) \) for \( x=4 \) so that it does not equal the limit as \( x \) approaches 4. For instance, define \( f(4) = 0 \), but ensure that for \( x < 4 \) and \( x > 4 \), \( f(x) = x \), which would make the limit as \( x \to 4 \) equal to 4.
05
Sketch the Graph
Draw the graph based on these definitions. For \( x < 2 \), plot a linear function just above the line \( y = x \), then a distinct point at 3 (\( f(2) = 3 \)) for the jump. After \( x=2 \), continue with \( y = x - 1 \) until just before \( x=4 \). Then leave a small "hole" at point \( (4, 4) \) to show the removable discontinuity. Put the point \( (4, 0) \) on the graph to indicate the defined value.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Jump Discontinuity
In calculus, a jump discontinuity occurs when there is an abrupt change in the value of a function at a specific point. This happens because the left-hand limit and the right-hand limit of the function at that point are not equal. Imagine walking on a path and suddenly encountering a vertical step up or down. That's similar to a jump discontinuity in a graph.
If we have a function that is defined differently on either side of a point, it can cause this type of discontinuity. For instance, using the original problem, consider the function:
If we have a function that is defined differently on either side of a point, it can cause this type of discontinuity. For instance, using the original problem, consider the function:
- For \( x < 2 \), the function is defined as \( f(x) = x + 1 \).
- For \( x > 2 \), it is \( f(x) = x - 1 \).
Removable Discontinuity
A removable discontinuity is like finding a small hole on a path that can be easily patched up. It's a point on the graph where the function isn't continuous, but there's an easy fix to make it continuous. This can occur when the limit of the function as it approaches a specific point exists, but it doesn’t align with the function’s value at that point.
To visualize this, consider the example of the function from the original exercise:
To visualize this, consider the example of the function from the original exercise:
- As \( x \) approaches 4 from either direction, the function \( f(x) = x \). This means the limit as \( x \to 4 \) is 4.
- However, the value of the function specifically defined at \( x = 4 \) is \( f(4) = 0 \).
Graph Sketching
Graph sketching involves plotting the behavior of a function on a coordinate plane. This helps to visualize concepts like discontinuities. To graph the function with discontinuities as described in the original exercise:
- Begin by sketching the line \( y = x + 1 \) for \( x < 2 \), keeping it slightly above the line \( y = x \). Place a distinct point at (2, 3) to mark the end of this segment.
- Next, draw the line \( y = x - 1 \) for \( x > 2 \), beginning just after \( x = 2 \).
- Continue this line until just before \( x = 4 \), where you make a small open circle (hole) at \((4, 4)\) to indicate the removable discontinuity.
- Finally, plot the point (4, 0) to show the actual defined value at \( x = 4 \).