/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 44 \(39-44\) Find the horizontal an... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

\(39-44\) Find the horizontal and vertical asymptotes of each curve. If you have a graphing device, check your work by graphing the curve and estimating the asymptotes. $$ y=\frac{2 e^{x}}{e^{x}-5} $$

Short Answer

Expert verified
Vertical asymptote: \(x = \ln(5)\), Horizontal asymptote: \(y = 2\).

Step by step solution

01

Identify Vertical Asymptotes

Vertical asymptotes occur where the denominator is zero and the numerator is non-zero. The denominator of the given function is \( e^x - 5 \). Set \( e^x - 5 = 0 \) to solve for \( x \): \( e^x = 5 \). Taking the natural logarithm of both sides gives \( x = \ln(5) \). Thus, the vertical asymptote is at \( x = \ln(5) \).
02

Determine Horizontal Asymptotes

Horizontal asymptotes are established by inspecting the behavior of the function as \( x \) approaches infinity or negative infinity. As \( x \to \infty \), both \( e^x \) in the numerator and denominator grow exponentially, and the leading behavior is determined by the ratio of their coefficients, which is \( \frac{2}{1} = 2 \). Thus, the horizontal asymptote is at \( y = 2 \). As \( x \to -\infty \), the function approaches zero because \( e^x \) approaches zero in both the numerator and denominator.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vertical Asymptotes
To understand vertical asymptotes, envision a point on a graph where a curve shoots up to positive or negative infinity. This can happen where the denominator of a fraction approaches zero, creating a limitless climb or drop. For the given function, \[ y = \frac{2e^x}{e^x - 5} \] in a vertical asymptote emerges when the denominator equates to zero, while the numerator remains non-zero. By setting \[ e^x - 5 = 0, \] we solve to find \[ e^x = 5. \] Taking the natural logarithm of both sides, we derive \[ x = \ln(5). \] Hence, the vertical asymptote here is at the line \[ x = \ln(5). \] Think of this line as a barrier that the curve can never cross on the graph, as it fiercely shoots upward or downward just beside it.
Horizontal Asymptotes
Horizontal asymptotes describe the behavior of a curve far out on the extremes of the x-axis, either heading towards positive or negative infinity. For the function \( y = \frac{2e^x}{e^x - 5} \), we investigate what happens when \( x \rightarrow \infty \) and \( x \rightarrow -\infty \). 💡 **Asymptotic Behavior:**- As \( x \rightarrow \infty, \) the term \( e^x \) in the numerator and denominator grows exceedingly large. In the limit, the behavior of the function depends on the ratio of the coefficient of \( e^x \), which is \( \frac{2}{1} = 2. \) Thus, the horizontal asymptote is located at \( y = 2. \)- In the case of \( x \rightarrow -\infty, e^x \) becomes negligible, leading the entire function towards zero. Hence, as \( x \rightarrow -\infty, y \rightarrow 0. \)Remember, horizontal asymptotes don't confine a curve as strictly as vertical ones; they merely suggest the direction the curve settles into over the long haul.
Exponential Functions
Exponential functions, characterized by expressions such as \( e^x, \)exhibit incredibly rapid growth or decay. Fundamental to many natural phenomena, they serve as building blocks for various mathematical concepts, including our function \( y = \frac{2e^x}{e^x - 5}. \)### Key characteristics of exponential functions include:- **Rapid Growth or Decay:** - As \( x \) increases, so does \( e^x, \) suggesting an accelerating upward trend. - Conversely, as \( x \) decreases, \( e^x \) swiftly drops towards zero. - **Continuous and Smooth Curves:** - Their graphs never break or abrupt, showcasing a smooth progression, whether increasing or decreasing.Exponential functions hold a special place in mathematics due to their unique growth patterns. With each step along the x-axis, they cover greater distances than their polynomial relatives. Understanding these traits can help you better comprehend their role in the overall structure of functions like the one we've just analyzed.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The number of bacteria after thours in a controlled laboratory experiment is \(\mathrm{n}=\mathrm{f}(\mathrm{t})\) . (a) What is the meaning of the derivative \(f^{\prime}(5) ?\) What are its units? (b) Suppose there is an unlimited amount of space and nutrients for the bacteria. Which do you think is larger, \(f^{\prime}(5)\) or \(f^{\prime}(10) ?\) If the supply of nutrients is limited, would that affect your conclusion? Explain.

$$ \begin{array}{l}{\text { Make a rough sketch of the curve } y=x^{n}(n \text { an integer })} \\ {\text { for the following five cases: }}\end{array} $$ $$ \begin{array}{ll}{\text { (i) } \mathrm{n}=0} & {\text { (ii) } \mathrm{n}>0, \mathrm{n} \text { odd }} \\ {\text { (iii) } \mathrm{n}>0, \mathrm{n} \text { even }} & {\text { (iv) } \mathrm{n}<0, \mathrm{n} \text { odd }}\end{array} $$ $$ \begin{array}{l}{\text { (v) } \mathrm{n}<0, \text { n even }} \\ {\text { Then use these sketches to find the following limits. }}\end{array} $$ (a) $$ \lim _{x \rightarrow \mathbb{u}^{+}} x^{n} \quad \text { (b) } \lim _{x \rightarrow 0^{-}} x^{n} $$ (c) $$ \lim _{x \rightarrow \infty} x^{n} \quad \text { (d) } \lim _{x \rightarrow-\infty} x^{n} $$

(a) By graphing the function \(f(x)=(\tan 4 x) / x\) and zooming in toward the point where the graph crosses the y-axis, estimate the value of \(\lim _{x \rightarrow 0} f(x)\). (b) Check your answer in part (a) by evaluating \(f(x)\) for values of \(x\) that approach \(0 .\)

Find the derivative of the function using the definition of derivative. State the domain of the function and the domain of its derivative. \(f(x)=\frac{3+x}{1-3 x}\)

Find the derivative of the function using the definition of derivative. State the domain of the function and the domain of its derivative. \(\mathrm{G}(\mathrm{t})=\frac{4 \mathrm{t}}{\mathrm{t}+1}\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.