Chapter 2: Problem 15
\(15-20\) Explain why the function is discontinuous at the given number a. Sketch the graph of the function. \(f(x)=\ln |x-2| \quad a=2\)
Short Answer
Expert verified
The function is discontinuous at \( x = 2 \) because it is undefined at this point, causing a vertical asymptote.
Step by step solution
01
Define the Function
The function given is \( f(x) = \ln |x-2| \). To understand where the function might be discontinuous, we'll analyze its behavior at the point \( a = 2 \).
02
Analyze Domain of the Function
The domain of \( f(x) = \ln |x - 2| \) is all \( x \) such that \( |x - 2| > 0 \). This means \( x eq 2 \). Therefore, the function is not defined exactly at \( x = 2 \).
03
Check Limit from the Left
To check continuity, we examine the left-hand limit of the function as \( x \to 2^- \). As \( x \to 2^- \), \( |x-2| \to 0^+ \) and \( \ln |x-2| \to -\infty \).
04
Check Limit from the Right
Similarly, examine the right-hand limit as \( x \to 2^+ \). Again, \( |x-2| \to 0^+ \) and \( \ln |x-2| \to -\infty \).
05
Compare Limits to Check Continuity
For continuity at \( x = 2 \), the function must be defined at \( x = 2 \), and the left-hand and right-hand limits must be equal and equal to \( f(2) \). Since \( f(2) \) is undefined and both limits approach \(-\infty\), the function is discontinuous at \( x = 2 \).
06
Sketch the Graph
The function is drawn with a vertical asymptote at \( x = 2 \). As \( x \) approaches 2 from either side, \( f(x) \) decreases towards \(-\infty\). Away from \( x = 2 \), the graph resembles typical logarithmic behavior for \(|x-2|>0\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Logarithmic Functions
Logarithmic functions are the inverse of exponential functions. The function \( f(x) = \ln(x) \) denotes the natural logarithm of \( x \), which is the power to which the base \( e \) (approximately 2.718) must be raised to yield \( x \). When dealing with expressions like \( \ln |x-2| \), the behavior of the function is determined by the absolute value of \( x-2 \), ensuring the input to the logarithm is positive. - This is because the logarithm is undefined for non-positive numbers; that's why \( \ln 0 \) and \( \ln \text{(negative numbers)} \) don't exist.- The transformation using absolute value changes the function only in terms of where it can be evaluated, not how the logarithm behaves. The graph of a simple logarithmic function, like \( \ln(x) \), has a vertical asymptote at \( x = 0 \) because it approaches negative infinity as \( x \) nears zero from the positive side. Similarly, \( \ln |x-2| \) has an asymptotic behavior at the points where \( |x-2| = 0 \), particularly at \( x = 2 \). This contributes to the discontinuity we observe in some graphs.
Limits and Continuity
Continuity of a function at a point requires three main conditions:
- The function must be defined at that point.
- The left-hand limit and right-hand limit as you approach the point must exist.
- The limits from both sides must equal the function's value at that point.
Domain of a Function
The domain of a function is the set of all possible input values (\( x \) values) for which the function is defined. For a logarithmic function such as \( f(x) = \ln |x-2| \), the domain encompasses all \( x \) that keep \( |x-2| > 0 \).- This requirement stems from the fact that a logarithmic expression is undefined for zero and negative inputs.- Thus, the absolute value ensures that the part inside \( \ln \) is positive, leading to \( x eq 2 \) as a restriction.Consequently, this function's domain includes all real numbers except \( x = 2 \). When examining the function's graph, this results in a vertical asymptote precisely at the point where the domain restriction occurs, making \( x = 2 \) a critical point of discontinuity. Understanding the domain is crucial for evaluating where the logarithmic function will behave regularly and where it will show signs of discontinuity.