/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 19 Is there a vector field \(\mathb... [FREE SOLUTION] | 91Ó°ÊÓ

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Is there a vector field \(\mathbf{G}\) on \(\mathbb{R}^{3}\) such that curl \(\mathbf{G}=\langle x \sin y, \cos y, z-x y\rangle ?\) Explain.

Short Answer

Expert verified
No, the divergence is not zero; such a vector field \( \mathbf{G} \) does not exist.

Step by step solution

01

Understanding the Problem

We are asked to find if there exists a vector field \( \mathbf{G} \) such that its curl results in the vector field \( \langle x \sin y, \cos y, z - xy \rangle \). To solve this, we need to verify if the given vector field can be a curl of any other field.
02

Use of Curl Property

For a vector field \( \mathbf{F} = \langle P, Q, R \rangle \) to be a curl \( abla \times \mathbf{G} \), it must satisfy the condition that its divergence \( abla \cdot \mathbf{F} \) is zero. Therefore, we need to check if \( abla \cdot \langle x \sin y, \cos y, z - xy \rangle \) is equal to zero.
03

Calculating the Divergence

Calculate the divergence of the vector field \( \langle x \sin y, \cos y, z - xy \rangle \).\[ abla \cdot \langle x \sin y, \cos y, z - xy \rangle = \frac{\partial}{\partial x}(x \sin y) + \frac{\partial}{\partial y}(\cos y) + \frac{\partial}{\partial z}(z - xy) \]
04

Evaluate Partial Derivatives

- \( \frac{\partial}{\partial x}(x \sin y) = \sin y \) - \( \frac{\partial}{\partial y}(\cos y) = -\sin y \) - \( \frac{\partial}{\partial z}(z - xy) = 1 \)
05

Calculating Divergence Result

Combine the results from Step 4 to find the divergence:\[ abla \cdot \langle x \sin y, \cos y, z - xy \rangle = \sin y + (-\sin y) + 1 = 0 + 1 = 1 \]
06

Conclusion from Divergence

Since the divergence of the field is \( 1 \), which is not zero, the vector field \( \langle x \sin y, \cos y, z - xy \rangle \) cannot be expressed as the curl of another vector field \( \mathbf{G} \) in \( \mathbb{R}^3 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Curl
When we talk about the curl of a vector field, we're looking at a way to measure the way the field rotates around a point. The curl is itself a vector, and it helps us understand if and how the field swirls around. If you picture a rotating wheel, the curl would be similar to the direction of the wheel's axis.
In mathematical terms, to find the curl of a vector field \( \mathbf{G} = \langle P, Q, R \rangle \), we use the formula:\[ abla \times \mathbf{G} = \left( \frac{\partial R}{\partial y} - \frac{\partial Q}{\partial z}, \frac{\partial P}{\partial z} - \frac{\partial R}{\partial x}, \frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y} \right) \]
The presence of a non-zero curl suggests that the field has rotational components. It's important to note that not every vector field can be written as a curl, and some conditions need to be satisfied for this to be possible.
Divergence
Divergence is another way to analyze a vector field, but instead of focusing on rotation, it measures how much the field spreads out from a point. Imagine a field of arrows pointing outward from a source; the rate at which these arrows "diverge" or spread out is captured by the divergence.
Mathematically, the divergence of a vector field \( \mathbf{F} = \langle P, Q, R \rangle \) is calculated using:\[ abla \cdot \mathbf{F} = \frac{\partial P}{\partial x} + \frac{\partial Q}{\partial y} + \frac{\partial R}{\partial z} \]
A key point here is that if a vector field, which is the result of another field's curl, should have zero divergence. If its divergence isn't zero, then the field can't be expressed as the curl of any field. This property is crucial in vector calculus problems like the one given in the exercise.
Partial Derivatives
Partial derivatives are an essential tool in vector calculus, allowing us to examine how a function changes as we tweak one variable while holding the others constant. They help illuminate the structure of vector fields, providing insight into how the field behaves in different dimensions.
For example, if you have a vector component \( P(x, y, z) \), its partial derivative with respect to \( x \), \( \frac{\partial P}{\partial x} \), shows how \( P \) changes if we only vary \( x \) while keeping \( y \) and \( z \) unchanged. Similar logic applies for partial derivatives with respect to \( y \) and \( z \).
In our problem, calculating the partial derivatives helps us compute the divergence and verify if the vector field could be a curl. They are fundamental in mathematical processes that involve gradients, curls, and divergences, dissecting the vector field into more understandable parts.
Vector Calculus
Vector calculus is the branch of mathematics that deals with vector fields, providing the methods to study their properties and behavior. It combines differentiation and integration of vector fields, giving us tools like gradient, divergence, and curl to understand multi-dimensional spaces.
  • **Gradient:** Measures the rate and direction of change in a scalar field.
  • **Divergence:** Indicates how much a vector field spreads or contracts.
  • **Curl:** Reflects the rotational aspect of a vector field.
Vector calculus is critical in physics and engineering, often used to describe systems involving fluid flow, electromagnetic fields, and more. The problem in our exercise uses these concepts to explore if a vector field can be described as the curl of another, underscoring the practical applications of this mathematical area.

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Most popular questions from this chapter

\(19-30\) Evaluate the surface integral \(\iint_{s} \mathbf{F} \cdot d \mathbf{S}\) for the given vector field \(\mathbf{F}\) and the oriented surface \(S\) . In other words, find the flux of \(\mathbf{F}\) across \(S .\) For closed surfaces, use the positive (outward) orientation. $$\mathbf{F}(x, y, z)=y \mathbf{j}-z \mathbf{k},$$ \(S\) consists of the paraboloid \(y=x^{2}+z^{2}, 0 \leqslant y \leqslant 1\) and the disk \(x^{2}+z^{2} \leq 1, y=1\)

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