Chapter 16: Problem 15
\(12-18\) (a) Find a function \(f\) such that \(\mathbf{F}=\nabla f\) and \((b)\) use part (a) to evaluate \(\int_{C} \mathbf{F} \cdot d \mathbf{r}\) along the given curve \(C .\) $$\mathbf{F}(x, y, z)=y z \mathbf{i}+x z \mathbf{j}+(x y+2 z) \mathbf{k}$$ \(C\) is the line segment from \((1,0,-2)\) to \((4,6,3)\)
Short Answer
Step by step solution
Verify if \( \mathbf{F} \) is Conservative
Find the Potential Function \( f \)
Evaluate the Line Integral Using the Potential Function
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Potential Function
In the exercise, the vector field \( \mathbf{F}(x, y, z) = yz \mathbf{i} + xz \mathbf{j} + (xy + 2z) \mathbf{k} \) needed to be matched with a gradient. Each component of \( \mathbf{F} \) was integrated with respect to its variable. This produced part of the potential function:
- Integrating \( yz \) with respect to \( x \) resulted in \( xyz + g(y, z) \).
- Integrating \( xz \) with respect to \( y \) ensured compatibility with other components.
- Integrating \( (xy + 2z) \) with respect to \( z \) completed the function as \( xyz + z^2 + C \).
Line Integral
- The integral \( \int_{C} \mathbf{F} \cdot d \mathbf{r} \) captures the total effect of \( \mathbf{F} \) as it passes along the path \( C \).
- A line integral takes into account not only the path \( C \) itself but also the inclination of \( \mathbf{F} \) relative to \( C \).
In our exercise, instead of following the traditional path-dependent method, we were able to utilize the potential function to determine the integral across \( C \) by only considering the endpoints, thanks to the next concept: the fundamental theorem for line integrals.
Fundamental Theorem for Line Integrals
- \( \int_{C} \mathbf{F} \cdot d\mathbf{r} = f(B) - f(A) \), where \( A \) and \( B \) are start and end points on \( C \).
In the exercise, the path was a straight line segment from \( (1,0,-2) \) to \( (4,6,3) \). By applying the fundamental theorem, we computed the potential function at these points:
- \( f(4,6,3) = 81 \)
- \( f(1,0,-2) = 4 \)