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1-2 Determine whether the points \(P\) and \(Q\) lie on the given surface. $$\begin{array}{l}{\mathbf{r}(u, v)=\langle 2 u+3 v, 1+5 u-v, 2+u+v\rangle} \\\ { P(7,10,4), Q(5,22,5)}\end{array}$$

Short Answer

Expert verified
Point P does not lie on the surface, but point Q does.

Step by step solution

01

Understand the Surface Equation

The surface is defined parametrically by the function \( \mathbf{r}(u, v) = \langle 2u + 3v, 1 + 5u - v, 2 + u + v \rangle \). This means any point \( (x, y, z) \) on the surface can be expressed in terms of \( u \) and \( v \). To determine if given points are on this surface, set \( x = 2u + 3v \), \( y = 1 + 5u - v \), \( z = 2 + u + v \) and solve for \( u \) and \( v \).
02

Check Point P(7, 10, 4)

Substitute \( x = 7 \), \( y = 10 \), \( z = 4 \) into the parametric equations:Equation 1: \( 7 = 2u + 3v \)Equation 2: \( 10 = 1 + 5u - v \)Equation 3: \( 4 = 2 + u + v \)Solve these equations simultaneously to see if consistent values of \( u \) and \( v \) satisfy all three.
03

Solve Equations for P

From Equation 3: \( 4 = 2 + u + v \) implies: \( u + v = 2 \). Using this in Equation 1: \( 7 = 2u + 3v \) can be rearranged and combined with \( u + v = 2 \) to solve for \( u \) and \( v \). Substitute \( u = 2 - v \) into equation 1 and solve:\[ 7 = 2(2 - v) + 3v \]Simplify to find \( v \):\[ 7 = 4 - 2v + 3v \implies v = 3 \] \( u = 2 - 3 = -1 \).Check consistency with Equation 2.
04

Verify Consistency for P

Substitute \( u = -1 \) and \( v = 3 \) into Equation 2:\[ 10 = 1 + 5(-1) - 3 \]Simplifies to:\[ 10 = 1 -5 - 3 \implies 10 = -7 \]This is inconsistent, so point \( P(7, 10, 4) \) does not lie on the surface.
05

Check Point Q(5, 22, 5)

Substitute \( x = 5 \), \( y = 22 \), \( z = 5 \) into the parametric equations:Equation 1: \( 5 = 2u + 3v \)Equation 2: \( 22 = 1 + 5u - v \)Equation 3: \( 5 = 2 + u + v \)Solve these equations simultaneously especially check if consistent \( u \) and \( v \) satisfy all three.
06

Solve Equations for Q

From Equation 3: \( 5 = 2 + u + v \) simplifies to \( u + v = 3 \).Replace \( u \) by \( 3 - v \) in Equation 1:\[ 5 = 2(3 - v) + 3v \]Simplify to find \( v \):\[ 5 = 6 - 2v + 3v \implies v = -1 \] \( u = 3 + 1 = 4 \).Check consistency with Equation 2.
07

Verify Consistency for Q

Substitute \( u = 4 \) and \( v = -1 \) into Equation 2:\[ 22 = 1 + 5(4) + 1 \]Simplifies to:\[ 22 = 1 + 20 + 1 = 22 \]This holds true, so point \( Q(5, 22, 5) \) lies on the surface.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Surface Equation
In the context of parametric surfaces, the **surface equation** plays a crucial role. A surface is often described by a parametric vector function, denoted as \( \mathbf{r}(u, v) \). This function expresses the coordinates \( (x, y, z) \) of any point on the surface in terms of two parameters, \( u \) and \( v \). In this exercise, the surface equation is given as \( \mathbf{r}(u, v) = \langle 2u + 3v, 1 + 5u - v, 2 + u + v \rangle \).

Understanding this means that each point on the surface can be obtained by varying \( u \) and \( v \). The equations extracted from this description are:
  • \( x = 2u + 3v \)
  • \( y = 1 + 5u - v \)
  • \( z = 2 + u + v \)
These equations allow us to test whether a given point lies on the surface by substituting the point's coordinates \( (x, y, z) \) into them to find corresponding values of \( u \) and \( v \). This is a typical problem in exploring the properties of surfaces in three-dimensional space.
Simultaneous Equations
The heart of determining whether points lie on such a surface involves solving **simultaneous equations**. These are sets of equations that must all be satisfied for the given variables. For our parametric surface problem, we set up a system of three equations derived from substituting the point coordinates into the parametric equations.

To check if a point is on the surface, we simultaneously solve:
  • \( x = 2u + 3v \)
  • \( y = 1 + 5u - v \)
  • \( z = 2 + u + v \)
This means for each point, we substitute its \( (x, y, z) \) values into the equations and solve for \( u \) and \( v \).

The solution process involves:
  • Using algebraic manipulation to solve for one variable in terms of the other from one of the equations.
  • Substituting back into the other equations to find consistent values of \( u \) and \( v \).
This method ensures that both variables satisfy all equations simultaneously. Successfully solving them confirms that the point is indeed on the surface.
Point Verification
**Point verification** in parametric surfaces is all about determining if specific coordinates belong to the described surface. Once we manipulate and solve the simultaneous equations, we must verify if the solutions for \( u \) and \( v \) are consistent across all original parametric equations.

For point \( P(7, 10, 4) \), though calculations yield \( v = 3 \) and \( u = -1 \), verifying these in the equations proves inconsistent—showing the point doesn’t lie on the surface.

In contrast, for point \( Q(5, 22, 5) \), the values found, \( v = -1 \) and \( u = 4 \), satisfy all equations. Inserting these into all three of the original parametric equations holds true, confirming the point’s presence on the surface.

This verification stage is crucial as mistakes in earlier calculations could lead to incorrect conclusions. It’s always wise to ensure the values of \( u \) and \( v \) work in reality through such a comprehensive check.

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Most popular questions from this chapter

Evaluate $$\int_{C}(y+\sin x) d x+\left(z^{2}+\cos y\right) d y+x^{3} d z$$ where \(C\) is the curve \(\mathbf{r}(t)=\langle\sin t, \cos t, \sin 2 t\rangle, 0 \leqslant t \leqslant 2 \pi\) [Hint: Observe that \(C\) lies on the surface \(z=2 x y .]\)

(a) Evaluate the line integral \(\int_{C} \mathbf{F} \cdot d \mathbf{r},\) where \(\mathbf{F}(x, y)=e^{x-1} \mathbf{i}+x y \mathbf{j}\) and \(C\) is given by \(\mathbf{r}(t)=t^{2} \mathbf{i}+t^{3} \mathbf{j}, 0 \leqslant t \leqslant 1\) (b) Illustrate part (a) by using a graphing calculator or computer to graph \(C\) and the vectors from the vector field corresponding to \(t=0,1 / \sqrt{2},\) and 1 (as in Figure \(13 ) .\)

(a) Suppose that \(\mathbf{F}\) is an inverse square force field, that is, $$\mathbf{F}(\mathbf{r})=\frac{c \mathbf{r}}{|\mathbf{r}|^{3}}$$ for some constant \(c,\) where \(\mathbf{r}=x \mathbf{i}+y \mathbf{j}+z \mathbf{k} .\) Find the work done by \(\mathbf{F}\) in moving an object from a point \(P_{1}\) along a path to a point \(P_{2}\) in terms of the distances \(d_{1}\) and \(d_{2}\) from these noints to the origin (b) An example of an inverse square field is the gravita- tional field \(\mathbf{F}=-(m M G) \mathbf{r} /|\mathbf{r}|^{3}\) discussed in Example 4 in Section \(16.1 .\) Use part (a) to find the work done by the gravitational field when the earth moves from aph- elion (at a maximum distance of \(1.52 \times 10^{8}\) km from the sun) to perihelion (at a minimum distance of \(1.47 \times 10^{8} \mathrm{km}\) ). (Use the values \(m=5.97 \times 10^{24} \mathrm{kg}\) \(M=1.99 \times 10^{30} \mathrm{kg},\) and \(G=6.67 \times 10^{-11} \mathrm{N} \cdot \mathrm{m}^{2} / \mathrm{kg}^{2}\) ) (c) Another example of an inverse square field is the electric force field \(\mathbf{F}=\varepsilon q Q \mathbf{r} /|\mathbf{r}|^{3}\) discussed in Example 5 in Section \(16.1 .\) Suppose that an electron with a charge of \(-1.6 \times 10^{-19} \mathrm{C}\) is located at the origin. A positive unit charge is positioned a distance \(10^{-12} \mathrm{m}\) from the electron and moves to a possition half that distance from the elec- tron. Use part (a) to find the work done by the electric force field. (Use the value \(\varepsilon=8.985 \times 10^{9} . )\)

Let \(\mathbf{r}=x \mathbf{i}+y \mathbf{j}+z \mathbf{k}\) and \(r=|\mathbf{r}|\) \(\begin{array}{l}{\text { Verify each identity. }} \\ {\text { (a) } \nabla \cdot \mathbf{r}=3} \\ {\text { (c) } \nabla^{2} r^{3}=12 r}\end{array} \quad(b) \nabla \cdot(r \mathbf{r})=4 r\)

\(5-18\) Evaluate the surface integral. $$\iint_{S} y d S,$$ \(S\) is the part of the paraboloid \(y=x^{2}+z^{2}\) that lies inside the cylinder \(x^{2}+z^{2}=4\)

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