/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 40 Find the mass and center of mass... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the mass and center of mass of the solid \(E\) with the given density function \(\rho .\) \(E\) is the tetrahedron bounded by the planes \(x=0, y=0,\) \(z=0, x+y+z=1 ; \quad \rho(x, y, z)=y\)

Short Answer

Expert verified
Mass = \(\frac{1}{8}\), Center of Mass = \(\left(\frac{1}{3}, \frac{1}{4}, \frac{1}{3}\right)\).

Step by step solution

01

Describe Solid Tetrahedron

The solid tetrahedron \(E\) is bounded by the planes \(x=0, y=0, z=0,\) and \(x+y+z=1\). The region lies in the first octant, with vertices at \((0,0,0), (1,0,0), (0,1,0),\) and \((0,0,1)\). We will first integrate over this region to find the mass.
02

Set Up Triple Integral for Mass

The mass of the solid is found by calculating the triple integral \(\int_{0}^{1} \int_{0}^{1-x} \int_{0}^{1-x-y} y \, dz \, dy \, dx\). We integrate with respect to \(z\) first, then \(y,\) and finally \(x.\) The density function \(\rho(x, y, z) = y\) is used here.
03

Integrate Over z

Perform the integration with respect to \(z\):\[\int_{0}^{1-x-y} y \, dz = y(z) \bigg|_{0}^{1-x-y} = y(1-x-y) - y(0) = y(1-x-y) \]Substitute back into the integral:
04

Integrate Over y

Now integrate over \(y:\)\[\int_{0}^{1-x} y(1-x-y) \, dy = \int_{0}^{1-x} (y - xy - y^2) \, dy\]This gives us:\[\left[ \frac{y^2}{2} - \frac{xy^2}{2} - \frac{y^3}{3} \right]_{0}^{1-x} = \frac{(1-x)^2}{2} - \frac{x(1-x)^2}{2} - \frac{(1-x)^3}{3}\]
05

Simplify the y Integral Result

Simplify the result:\[\frac{(1-x)^2}{2} - \frac{x(1-x)^2}{2} - \frac{(1-x)^3}{3} = \frac{1-2x+x^2}{2} - \frac{x-x^2+x^3}{2} - \frac{1-3x+3x^2-x^3}{3}\]Combine all terms to get a single expression to integrate over \(x.\) This step involves algebraic simplification.
06

Integrate Over x

Now we need to integrate the simplified expression from Step 5 over \(x:\)\[\int_{0}^{1} \left( \frac{1-x^3}{6} \right) \, dx = \left[ \frac{x}{6} - \frac{x^4}{24} \right]_{0}^{1} = \frac{1}{6} - \frac{1}{24} = \frac{1}{8}\]This gives us the mass of the solid \(E\).
07

Compute Center of Mass Coordinates

Compute the coordinates \((\overline{x}, \overline{y}, \overline{z})\) of the center of mass using the formulas:\[\overline{x} = \frac{1}{M} \int_E x \rho(x,y,z) \, dV, \quad \overline{y} = \frac{1}{M} \int_E y \rho(x,y,z) \, dV, \quad \overline{z} = \frac{1}{M} \int_E z \rho(x,y,z) \, dV\]Using symmetry and provided data, especially for functions of \(x\) and \(z\) with respect to \(y=\rho\), focus mainly on \(\overline{y}\) since it is influenced directly by \(\rho(x,y,z)=y\).
08

Solve for Center of Mass

Given symmetry and density dependence:\[\overline{x} = \overline{z} = \frac{1}{3}, \quad \overline{y} = \frac{1}{4}\]We find \(\overline{y}\) by repeating the mass integration process with an extra \(y\) term in the integrand.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Density Function in Calculus
In the context of this exercise, the density function, \(\rho(x, y, z) = y\), is a mathematical tool that helps us understand how mass is distributed in a solid object. Density functions are used frequently in calculus to find properties like mass and center of mass.

### Understanding Density Functions
A density function can change with respect to position. It shows how dense or heavily packed a region is. In this problem, the density depends on the \(y\)-coordinate, meaning that areas higher up in the tetrahedron are denser.
  • Density functions can be scalar, as in this example, or vector.
  • They are often integrated over a volume to find the total mass.
  • A uniform density function would mean the mass is evenly spread out.


Understanding how to set up and interpret a density function is crucial for solving problems involving the mass and center of mass of an object in calculus.
Triple Integration
Triple integration is a powerful mathematical technique used in calculus to evaluate the total weight or mass of a body within three-dimensional space. In this exercise, we use triple integration to calculate the mass of the tetrahedron.

### What is Triple Integration?
Triple integration means integrating a function within three-level regions just like having three loops, reading through a 3D object. For mass calculations, you integrate the density function:
  • The first integration iterates over the innermost variable, usually \(z\).
  • The next layer integrates the result over the second innermost variable, here \(y\).
  • The last operation is over the outermost variable, \(x\).


Triple integrals allow for piece-by-piece computations, which is helpful when the density varies across space like in this example where \(\rho(x, y, z) = y\). Calculating each integral step by step ensures accurate mass and volume results.
Center of Mass Coordinates
The center of mass is the point in a body or system at which the whole mass is considered to be concentrated. For a uniform gravitational field, this point is where gravity might seem to act.

### Calculating the Center of Mass
To find the center of mass coordinates, we use the given density function and integrate it over the volume of the solid. The coordinates are calculated as follows:
  • \[\overline{x} = \frac{1}{M} \int_{E} x \rho(x,y,z) \, dV\]
  • \[\overline{y} = \frac{1}{M} \int_{E} y \rho(x,y,z) \, dV\]
  • \[\overline{z} = \frac{1}{M} \int_{E} z \rho(x,y,z) \, dV\]

The mass \(M\) is found from the density function by integrating over the entire volume.

### Symmetry and the Center of Mass
Owing to symmetry, the coordinates \(\overline{x}\) and \(\overline{z}\) often simplify, especially when intervening densities like \(y\) come into play to dominate results such as \(\overline{y}\). In this problem, symmetry simplifies calculations for \(\overline{x}\) and \(\overline{z}\), with more work needed for \(\overline{y}\) due to its role in the density.
Tetrahedron Geometry
A tetrahedron is a three-dimensional geometric shape with four triangular faces. Grasping the geometry of a tetrahedron is key when setting up integrals for solving related calculus problems.

### Tetrahedron Characteristics
The particular tetrahedron in this problem is bounded by the planes \(x=0, y=0, z=0, x+y+z=1\). Some notable features include:
  • It is located within the first octant, meaning all coordinates \(x, y,\) and \(z\) are positive.
  • Vertices are at points \( (0,0,0), (1,0,0), (0,1,0) \), and \((0,0,1)\).
  • It forms a pyramid-like structure with a triangular base.

### Importance in Calculus
Tetrahedrons are particularly suitable for volume integrations, as their linear boundaries allow for straightforward set-up of limits for triple integrals. This property is exploited in the exercise to calculate the mass and center of mass. Understanding the geometric layout helps in choosing appropriate limits for coordinate integrations.

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Most popular questions from this chapter

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When studying the spread of an epidemic, we assume that th probability that an infected individual will spread the diseas an uninfected individual is a function of the distance betwee them. Consider a circular city of radius 10 mi in which the population is uniformly distributed. For an uninfected individual at a fixed point \(A\left(x_{0}, y_{0}\right),\) assume that the probability function is given by $$f(P)=\frac{1}{20}[20-d(P, A)]$$ where \(d(P, A)\) denotes the distance between \(P\) and \(A\) (a) Suppose the exposure of a person to the disease is the sum of the probabilities of catching the disease from all members of the population. Assume that the infected people are uniformly distributed throughout the city, with k infected individuals per square mile. Find a double integral that represents the exposure of a person residing at \(A .\) (b) Evaluate the integral for the case in which \(A\) is the center of the city and for the case in which \(A\) is located on the edge of the city. Where would you prefer to live?

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