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Use the Midpoint Rule for triple integrals (Exercise 24 to estimate the value of the integral. Divide \(B\) into eight sub-boxes of equal size. $$ \begin{array}{l}{\iint_{B} \sin \left(x y^{2} z^{3}\right) d V, \text { where }} \\ {B=\\{(x, y, z) | 0 \leqslant x \leqslant 4,0 \leqslant y \leqslant 2,0 \leqslant z \leqslant 1\\}}\end{array} $$

Short Answer

Expert verified
Estimate the integral by using sub-box midpoints and summing their contributions.

Step by step solution

01

Determine the Dimensions of B

The region \(B\) is defined as \(0 \leq x \leq 4\), \(0 \leq y \leq 2\), and \(0 \leq z \leq 1\). These ranges create a box with dimensions 4 along \(x\), 2 along \(y\), and 1 along \(z\).
02

Identify the Volume of Each Sub-box

Divide the box into eight sub-boxes by splitting the ranges: 2 subdivisions along \(x\), 2 subdivisions along \(y\), and 2 subdivisions along \(z\). Each sub-box has dimensions of 2 along \(x\), 1 along \(y\), and 0.5 along \(z\).
03

Calculate the Midpoints of Each Sub-box

For each sub-box, calculate the midpoint \((x_i, y_j, z_k)\). For example, the midpoints along the \(x\)-axis are 1 and 3, along the \(y\)-axis are 0.5 and 1.5, and along the \(z\)-axis are \(0.25\) and \(0.75\).
04

Evaluate the Function at Midpoints

For each midpoint, evaluate the function \(\sin(xy^2z^3)\). Calculate for all combinations of midpoints: \((1, 0.5, 0.25)\), \((1, 0.5, 0.75)\), and so forth.
05

Calculate the Volume Contribution

Multiply each function evaluation by the volume of a sub-box, which is \(2 \times 1 \times 0.5 = 1\, \text{unit}^3\).
06

Sum All Contributions

Add all the multiplied values together to approximate the integral's value. This is the sum of function evaluations times the sub-box volume.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Triple Integrals
Triple integrals are an extension of double integrals to three dimensions. They allow you to calculate the integral of a function over a volume in three-dimensional space. Imagine calculating the accumulated value of a function inside a rectangular prism or box.
Triple integrals are used in physics and engineering whenever a problem involves three-dimensional space. They help in finding
  • total mass when the density varies across the volume
  • center of mass
  • electric charge in a space
Calculating a triple integral involves integrating with respect to three variables, commonly denoted as x, y, and z. For a given function f(x, y, z), you might integrate first with respect to x, then y, then z, although the order may vary depending on the problem. The general form for a triple integral over a region R is given by:\[\iiint_R f(x, y, z) \, dV\]where \(dV\) represents the differential volume element \(dx \, dy \, dz\).
Evaluation at Midpoints
Evaluating at midpoints is a technique to approximate the value of integrals, including triple integrals. It's particularly used in the Midpoint Rule, a numerical integration method.
Instead of calculating the exact value of an integral, which may be complex or impossible to find analytically, the Midpoint Rule provides an estimate by evaluating the function at specific points.
Here's how evaluating at midpoints works in the context of triple integrals:
  • Divide the entire region over which you are integrating into smaller subregions or sub-boxes.
  • Calculate the midpoint of each sub-box. For example, if a sub-box spans \([a, b]\) along an axis, the midpoint is \((a+b)/2\).
  • Evaluate the function at each of these midpoints. The idea is that this point gives a good average value of the function over the sub-box.
By using midpoints in each sub-box, we gain a relatively good approximation of the integral's value without too much computational effort. This method is especially helpful when dealing with integrals over complex or irregular regions.
Volume Integration
Volume integration is the process of integrating a function over a three-dimensional region. Unlike area integration, which calculates over a two-dimensional space, volume integration encompasses the complexity of a full 3D space.
It's often necessary when computing properties like mass, density, or energy distributed in a volume. The regions can range from simple rectangular boxes to more complex shapes, but the fundamental principle remains the same: sum over small volume elements to find the total quantity.
In volume integration, the differential volume element \(dV\) plays a critical role. Depending on the coordinate system (Cartesian, cylindrical, spherical, etc.), \(dV\) can take different forms:
  • In Cartesian coordinates, \(dV = dx \, dy \, dz\).
  • In cylindrical coordinates, \(dV = r \, dr \, d\theta \, dz\).
  • In spherical coordinates, \(dV = r^2 \, \sin\theta \, dr \, d\theta \, d\phi\).
By taking small volume elements and performing integration, volume integration effectively captures the accumulation of function values in three dimensions.
Numerical Integration Methods
Numerical integration methods are techniques used to approximate integrals, especially when an analytical solution is difficult or impossible to attain. They are crucial for handling integrals of complex functions or where data is known only in discrete form.
The Midpoint Rule, as applied in this exercise, is part of this family. Other methods include:
  • Trapezoidal Rule: Approximates the region under a curve as a series of trapezoids instead of rectangles. It generally provides better accuracy over the same subdivisions as compared to the Midpoint Rule.
  • Simpson's Rule: Uses parabolas to approximate the curve instead of straight lines, giving a much higher accuracy, especially for smooth functions.
  • Monte Carlo Integration: Utilizes random sampling to estimate the integral, often used for multi-dimensional integrals in complex domains.
These numerical methods are vital in scientific computations, where precision and computational feasibility need to be balanced. Depending on the complexity of the function and the required accuracy, different methods may be chosen.

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Most popular questions from this chapter

\(23-26\) A lamina with constant density \(\rho(x, y)=\rho\) occupies the given region. Find the moments of inertia \(I_{x}\) and \(I_{y}\) and the radii of gyration \(\overline{x}\) and \(\overline{y} .\) The region under the curve \(y=\sin x\) from \(x=0\) to \(x=\pi\)

The joint density function for random variables \(X, Y,\) and \(Z\) is \(f(x, y, z)=C x y\) if \(0 \leqslant x \leqslant 2,0 \leqslant y \leqslant 2,0 \leqslant z \leqslant 2,\) and \(f(x, y, z)=0\) otherwise. (a) Find the value of the constant \(C .\) (b) Find \(P(X \leq 1, Y \leq 1, Z \leq 1)\) (c) Find \(P(X+Y+Z \leqslant 1)\)

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The average value of a function \(f(x, y, z)\) over a solid region \(E\) is defined to be $$ f_{\mathrm{ave}}=\frac{1}{V E)} \iiint_{E} f(x, y, z) d V $$ where \(V(E)\) is the volume of \(E .\) For instance, if \(\rho\) is a density function, then \(\rho_{\text { ave is the average density of } E .}\) Find the average value of the function \(f(x, y, z)=x^{2} z+y^{2} z\) over the region enclosed by the paraboloid \(z=1-x^{2}-y^{2}\) and the plane \(z=0 .\)

The latitude and longitude of a point \(P\) in the Northern Hemisphere are related to spherical coordinates \(\rho, \theta, \phi\) as follows. We take the origin to be the center of the earth and the positive \(z\) -axis to pass through the North Pole. The positive \(x\) -axis passes through the point where the prime meridian (the meridian through Greenwich, England) intersects the equator. Then the latitude of \(P\) is \(\alpha=90^{\circ}-\phi^{\circ}\) and the longitude is \(\beta=360^{\circ}-\theta^{\circ} .\) Find the great-circle distance from Los Angeles (lat. \(34.06^{\circ} \mathrm{N},\) long. \(118.25^{\circ} \mathrm{W}\) ) to Montreal (lat. \(45.50^{\circ} \mathrm{N},\) long. \(73.60^{\circ} \mathrm{W} ) .\) Take the radius of the earth to be 3960 \(\mathrm{mi} .\) (A great circle is the circle of intersection of a sphere and a plane through the center of the sphere.)

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