Chapter 13: Problem 6
\(3-8\) Find the velocity, acceleration, and speed of a particle with the given position function. Sketch the path of the particle and draw the velocity and acceleration vectors for the specified value of \(t .\) $$\mathbf{r}(t)=e^{t} \mathbf{i}+e^{2 t} \mathbf{j}, \quad t=0$$
Short Answer
Expert verified
Velocity: \(1 \mathbf{i} + 2 \mathbf{j}\); Acceleration: \(1 \mathbf{i} + 4 \mathbf{j}\); Speed: \(\sqrt{5}\).
Step by step solution
01
Find the Velocity
The velocity of a particle is the derivative of the position function with respect to time. Given \( \mathbf{r}(t) = e^t \mathbf{i} + e^{2t} \mathbf{j} \), differentiate each component with respect to \( t \):- Derivative of \( e^t \) is \( e^t \).- Derivative of \( e^{2t} \) is \( 2e^{2t} \).So, the velocity \( \mathbf{v}(t) = \frac{d\mathbf{r}}{dt} = e^t \mathbf{i} + 2e^{2t} \mathbf{j} \).
02
Find the Acceleration
The acceleration of a particle is the derivative of the velocity function with respect to time. Differentiate \( \mathbf{v}(t) = e^t \mathbf{i} + 2e^{2t} \mathbf{j} \):- Derivative of \( e^t \) is \( e^t \).- Derivative of \( 2e^{2t} \) is \( 4e^{2t} \).Thus, the acceleration \( \mathbf{a}(t) = \frac{d\mathbf{v}}{dt} = e^t \mathbf{i} + 4e^{2t} \mathbf{j} \).
03
Calculate Velocity, Acceleration, and Speed at t = 0
Substitute \( t = 0 \) into the velocity and acceleration functions:- Velocity: \( \mathbf{v}(0) = e^0 \mathbf{i} + 2e^{0} \mathbf{j} = 1 \mathbf{i} + 2 \mathbf{j} \).- Acceleration: \( \mathbf{a}(0) = e^0 \mathbf{i} + 4e^{0} \mathbf{j} = 1 \mathbf{i} + 4 \mathbf{j} \).The speed of the particle is the magnitude of the velocity vector, calculated as:\[ \| \mathbf{v}(0) \| = \sqrt{1^2 + 2^2} = \sqrt{5}. \]
04
Sketch the Path and Vectors
The path of the particle is described by the position function \( \mathbf{r}(t) = e^t \mathbf{i} + e^{2t} \mathbf{j} \) and sketches as an exponential curve in the plane, as both components grow exponentially. At \( t = 0 \), the position is \( (1, 1) \).The velocity vector \( \mathbf{v}(0) = (1, 2) \) can be drawn starting at point \( (1, 1) \), pointing in the direction of movement with length proportional to its magnitude.Similarly, the acceleration vector \( \mathbf{a}(0) = (1, 4) \) is drawn starting at the same point and is longer, reflecting higher magnitude due to the increase in acceleration.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Velocity Vector
In physics, a **velocity vector** represents the rate of change of the position of a particle with respect to time. It gives both speed and direction. For a given position function \( \mathbf{r}(t) = e^t \mathbf{i} + e^{2t} \mathbf{j} \), the velocity vector \( \mathbf{v}(t) \) is obtained by taking its derivative with respect to time.
- Differentiate each component of the position function.
- The derivative of the term \( e^t \) is \( e^t \), and for \( e^{2t} \), it is \( 2e^{2t} \).
Acceleration Vector
The **acceleration vector** signifies the rate of change of the velocity vector over time. It depicts how quickly a particle is speeding up or slowing down, as well as changes in direction. By taking the derivative of the velocity vector \( \mathbf{v}(t) = e^t \mathbf{i} + 2e^{2t} \mathbf{j} \), we obtain the acceleration vector:
- The derivative of \( e^t \) remains \( e^t \).
- The derivative of \( 2e^{2t} \) is \( 4e^{2t} \).
Exponential Functions
**Exponential functions** are mathematical functions of the form \( e^{kt} \), where \( e \) is Euler's number (approximately 2.718), and \( k \) is a constant. They are used to model growth or decay processes, extensively seen in both natural and applied sciences.
- In the position function \( \mathbf{r}(t) = e^t \mathbf{i} + e^{2t} \mathbf{j} \), the exponential components describe how the particle's position changes exponentially over time.
- The components \( e^t \) and \( e^{2t} \) mean the particle's position magnifies rather quickly as time progresses.
Position Function
A **position function** \( \mathbf{r}(t) \) provides the location of a particle at any time \( t \). It tells us where the particle is in space. For instance, \( \mathbf{r}(t) = e^t \mathbf{i} + e^{2t} \mathbf{j} \) describes a path in a 2-dimensional plane.
- The \( i \) and \( j \) components represent the horizontal and vertical directions respectively.
- The exponential terms user here reflect the changing position with time.