Chapter 12: Problem 42
Let \(\mathbf{v}=5 \mathbf{j}\) and let \(\mathbf{u}\) be a vector with length 3 that starts at the origin and rotates in the \(x y\) -plane. Find the maximum and minimum values of the length of the vector \(\mathbf{u} \times \mathbf{v} .\) In what direction does \(\mathbf{u} \times \mathbf{v}\) point?
Short Answer
Step by step solution
Understanding Vectors
Calculate the Cross Product
Magnitude of the Cross Product
Determine Maximum and Minimum Lengths
Direction of the Cross Product
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cross Product
A unique property of the cross product is that it tells us about the rotational effect and direction of the perpendicular vector. The vector \(\mathbf{u} \times \mathbf{v}\) results from the vectors \(\mathbf{u} = \langle u_1, u_2, 0 \rangle\) and \(\mathbf{v} = \langle 0, 5, 0 \rangle\). Thus, the cross product simplifies to \(\langle 0, 0, 5u_1 \rangle\).
- The resulting vector is perpendicular to the vectors \(\mathbf{u}\) and \(\mathbf{v}\).
- This reflects the fact that the direction of the result is dependent on the initial vectors' directions.
Magnitude of Vector
In our exercise, after calculating the cross product \(\mathbf{u} \times \mathbf{v}\ = \langle 0, 0, 5u_1 \rangle \), we find its magnitude by simply taking the absolute value of the z-component, which is \(\|5u_1\|\). Since the vector \(\mathbf{u}\) can vary as it rotates in the xy-plane, it can take values of \(-3 \le u_1 \le 3\). This variation gives us insight into the possible sizes of the cross product vector's magnitude.
The maximum magnitude occurs when \(u_1 \) is at its extremities of either 3 or -3, providing a max magnitude of 15. Meanwhile, the minimum value will be zero when \(u_1 \) is 0.
Direction of Vector
In this exercise, the direction of \(\mathbf{u} \times \mathbf{v}\) is affected by \(u_1\), the x-component of vector \(\mathbf{u}\). Since the resulting vector is \(\langle 0, 0, 5u_1 \rangle\), it indicates that the direction lies entirely along the z-axis. Whether it points in the positive or negative direction depends on the sign of \(u_1\). This results in:
- A positive z-direction, if \(u_1\) is positive.
- A negative z-direction, if \(u_1\) is negative.
XY-Plane Rotation
Here, vector \(\mathbf{u}\) describes such a rotation. It maintains a constant length but changes direction as it sweeps through different angles. This is expressed as its components, \(u_1\) and \(u_2\), satisfy the circle equation \(u_1^2 + u_2^2 = 9\).
Rotation in the xy-plane implies:
- Vector \(\mathbf{u}\) remains within the plane while changing its orientation.
- The length, or magnitude, stays constant.
- Different orientations of \(\mathbf{u}\) affect the cross-product results.