Chapter 12: Problem 10
Find the distance from \((3,7,-5)\) to each of the following. \(\begin{array}{ll}{\text { (a) The } x y \text { -plane }} & {\text { (b) The } y z \text { -plane }} \\ {\text { (c) The } x z \text { -plane }} & {\text { (d) The } x \text { -axis }} \\ {\text { (e) The } y \text { -axis }} & {\text { (f) The } z \text { -axis }}\end{array}\)
Short Answer
Step by step solution
- Understand the Problem
- Calculate Distance to the xy-plane
- Calculate Distance to the yz-plane
- Calculate Distance to the xz-plane
- Calculate Distance to the x-axis
- Calculate Distance to the y-axis
- Calculate Distance to the z-axis
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
xy-plane distance
For a point \(3, 7, -5\), its height above or below this 'floor' is simply the absolute value of the z-coordinate. Here, the z-coordinate is -5, so the distance is \(|-5| = 5\). This distance can be thought of as how far up or down the point is from the xy-plane.
- The formula for the distance to the xy-plane is \(|z|\).
- This distance focuses solely on vertical displacement.
yz-plane distance
In the example with the point \(3, 7, -5\), the x-coordinate is 3. Thus, the distance to the yz-plane is \(|3| = 3\).
What happens here is that we effectively ignore changes in y and z since moving along these does not affect how far the point is from the yz-plane.
- The formula for distance to the yz-plane is \(|x|\).
- This considers only horizontal displacement along the x-axis.
xz-plane distance
Using the point \(3, 7, -5\), observe that the y-coordinate is 7. Hence, its distance from the xz-plane is \(|7| = 7\).
Since the xz-plane cuts through space like a vertical wall, distance is measured by how far above or below the wall the point sits, determined exclusively by y.
- The formula for the distance to the xz-plane is \(|y|\).
- This metric considers only vertical displacement along the y-axis, ignoring x and z.
coordinate axes distance
X-Axis
For distance from \((3,7,-5)\) to the x-axis, use the formula \[\sqrt{(y-0)^2+(z-0)^2}\]. Plugging in 7 and -5 yields \[\sqrt{49+25} = \sqrt{74}\]. This measures movement in both y and z to the x-axis.Y-Axis
For the y-axis, calculate with \[\sqrt{(x-0)^2+(z-0)^2}\]. Using 3 and -5, we get \[\sqrt{9+25} = \sqrt{34}\]. Here, x and z are the distances of interest.Z-Axis
Lastly, for the z-axis, distance is \[\sqrt{(x-0)^2+(y-0)^2}\]. With x=3 and y=7, this gives \[\sqrt{9+49} = \sqrt{58}\]. This involves moving along x and y axes.- Distances to axes use Pythagorean theorem across two coordinates.
- This accounts for diagonal distance rather than single-axis measurement.