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Find the distance from \((3,7,-5)\) to each of the following. \(\begin{array}{ll}{\text { (a) The } x y \text { -plane }} & {\text { (b) The } y z \text { -plane }} \\ {\text { (c) The } x z \text { -plane }} & {\text { (d) The } x \text { -axis }} \\ {\text { (e) The } y \text { -axis }} & {\text { (f) The } z \text { -axis }}\end{array}\)

Short Answer

Expert verified
(a) 5, (b) 3, (c) 7, (d) \(\sqrt{74}\), (e) \(\sqrt{34}\), (f) \(\sqrt{58}\).

Step by step solution

01

- Understand the Problem

You need to find the shortest distance from the point \((3,7,-5)\) to the listed geometric planes and axes. The distance from a point \((x_1, y_1, z_1)\) to a plane parallel to a coordinate plane passes through one coordinate, meaning the other coordinates are zero. The same applies to axes, where two coordinates are zero.
02

- Calculate Distance to the xy-plane

The distance from the point \((3,7,-5)\) to the \(xy\)-plane is given by the absolute value of the z-coordinate. Since the point in the \(xy\)-plane has coordinates \((3, 7, 0)\), the distance is \(|z| = |-5| = 5\).
03

- Calculate Distance to the yz-plane

The distance from the point \((3,7,-5)\) to the \(yz\)-plane is given by the absolute value of the x-coordinate. Since the point in the \(yz\)-plane has coordinates \((0, 7, -5)\), the distance is \(|x| = |3| = 3\).
04

- Calculate Distance to the xz-plane

The distance from the point \((3,7,-5)\) to the \(xz\)-plane is given by the absolute value of the y-coordinate. Since the point in the \(xz\)-plane has coordinates \((3, 0, -5)\), the distance is \(|y| = |7| = 7\).
05

- Calculate Distance to the x-axis

The distance from the point \((3,7,-5)\) to the \(x\)-axis is calculated using the formula: \[ \sqrt{(y-0)^2+(z-0)^2} = \sqrt{7^2+(-5)^2} = \sqrt{49+25} = \sqrt{74} \]
06

- Calculate Distance to the y-axis

The distance from the point \((3,7,-5)\) to the \(y\)-axis is calculated with the formula: \[ \sqrt{(x-0)^2+(z-0)^2} = \sqrt{3^2+(-5)^2} = \sqrt{9+25} = \sqrt{34} \]
07

- Calculate Distance to the z-axis

The distance from the point \((3,7,-5)\) to the \(z\)-axis is determined using the formula: \[ \sqrt{(x-0)^2+(y-0)^2} = \sqrt{3^2+7^2} = \sqrt{9+49} = \sqrt{58} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

xy-plane distance
When finding the distance from a point to the xy-plane in 3D geometry, you focus on the z-coordinate of the point. Imagine that the xy-plane lies flat like a floor, and any point off this plane will have a height corresponding to its z-value.

For a point \(3, 7, -5\), its height above or below this 'floor' is simply the absolute value of the z-coordinate. Here, the z-coordinate is -5, so the distance is \(|-5| = 5\). This distance can be thought of as how far up or down the point is from the xy-plane.

  • The formula for the distance to the xy-plane is \(|z|\).
  • This distance focuses solely on vertical displacement.
Knowing just the z-value is sufficient for this calculation.
yz-plane distance
The yz-plane is like a wall standing upright. Points not on this plane have an x-coordinate that tells us how far they are from the yz-plane.

In the example with the point \(3, 7, -5\), the x-coordinate is 3. Thus, the distance to the yz-plane is \(|3| = 3\).

What happens here is that we effectively ignore changes in y and z since moving along these does not affect how far the point is from the yz-plane.

  • The formula for distance to the yz-plane is \(|x|\).
  • This considers only horizontal displacement along the x-axis.
This is the simplest dimension to visualize: moving directly left or right away from the yz-plane.
xz-plane distance
The xz-plane distance draws focus to how high or low a point is relative to this plane. Here, you're checking the y-coordinate for position details.
Using the point \(3, 7, -5\), observe that the y-coordinate is 7. Hence, its distance from the xz-plane is \(|7| = 7\).

Since the xz-plane cuts through space like a vertical wall, distance is measured by how far above or below the wall the point sits, determined exclusively by y.

  • The formula for the distance to the xz-plane is \(|y|\).
  • This metric considers only vertical displacement along the y-axis, ignoring x and z.
One can imagine climbing a ladder, either up or down, to exit the plane.
coordinate axes distance
Distance to an axis uses two coordinates since an axis is where two planes intersect. Each axis forms a line in 3D space, requiring more precision to measure distance.

X-Axis

For distance from \((3,7,-5)\) to the x-axis, use the formula \[\sqrt{(y-0)^2+(z-0)^2}\]. Plugging in 7 and -5 yields \[\sqrt{49+25} = \sqrt{74}\]. This measures movement in both y and z to the x-axis.

Y-Axis

For the y-axis, calculate with \[\sqrt{(x-0)^2+(z-0)^2}\]. Using 3 and -5, we get \[\sqrt{9+25} = \sqrt{34}\]. Here, x and z are the distances of interest.

Z-Axis

Lastly, for the z-axis, distance is \[\sqrt{(x-0)^2+(y-0)^2}\]. With x=3 and y=7, this gives \[\sqrt{9+49} = \sqrt{58}\]. This involves moving along x and y axes.

  • Distances to axes use Pythagorean theorem across two coordinates.
  • This accounts for diagonal distance rather than single-axis measurement.
Finding these distances helps in visualizing three-dimensional navigation in relation to coordinate lines.

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