Chapter 11: Problem 9
\(3-10\) Find a power series representation for the function and determine the interval of convergence. $$ f(x)=\frac{1+x}{1-x} $$
Short Answer
Expert verified
The power series representation is \( 1 + 2 \sum_{n=0}^{\infty} x^{n+1} \) with an interval of convergence \( -1 < x < 1 \).
Step by step solution
01
Identify the Base Function
The given function is \( f(x) = \frac{1+x}{1-x} \). Notice that \( \frac{1}{1-x} \) resembles the geometric series \( \sum_{n=0}^{\infty} x^n \), valid for \( |x| < 1 \).
02
Decompose the Function
Rewrite \( f(x) = \frac{1}{1-x} + \frac{x}{1-x} \). This separates the constant term from the additional \( x \) in the numerator.
03
Find the Power Series Representation
First, substitute the geometric series for \( \frac{1}{1-x} = \sum_{n=0}^{\infty} x^n \). Since \( \frac{x}{1-x} \) can also be expressed by multiplying each term of the series by \( x \), it becomes \( \sum_{n=0}^{\infty} x^{n+1} = \sum_{n=1}^{\infty} x^n \). Therefore, \( f(x) = \sum_{n=0}^{\infty} x^n + \sum_{n=1}^{\infty} x^n \).
04
Simplify the Power Series
Combine the series from Step 3: \( \sum_{n=0}^{\infty} x^n + \sum_{n=1}^{\infty} x^n = 1 + 2x + 2x^2 + 2x^3 + \cdots = 1 + 2 \sum_{n=1}^{\infty} x^n \). This simplifies further to give the series \( 1 + 2 \sum_{n=0}^{\infty} x^{n+1} \).
05
Determine the Interval of Convergence
For geometric series, the convergence is within \( |x| < 1 \). Thus, the interval of convergence for our series is \( -1 < x < 1 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Geometric Series
The geometric series is a fundamental concept in calculus and sequences. It can be defined as the sum of a sequence where each term after the first is the preceding term multiplied by a constant, called the common ratio. For example, a simple geometric series can look like this:
Understanding the geometric series concept is crucial when dealing with power series representations of functions. In this particular problem, the function \( \frac{1}{1-x} \) can be represented as a geometric series \( \sum_{n=0}^{\infty} x^n \), as long as \( |x| < 1 \).
This is a powerful way to express functions, giving us tools to easily handle complex fractions by breaking them into infinite series.
- 1, x, x^2, x^3, ...
Understanding the geometric series concept is crucial when dealing with power series representations of functions. In this particular problem, the function \( \frac{1}{1-x} \) can be represented as a geometric series \( \sum_{n=0}^{\infty} x^n \), as long as \( |x| < 1 \).
This is a powerful way to express functions, giving us tools to easily handle complex fractions by breaking them into infinite series.
Interval of Convergence
The interval of convergence is a range of values for which a power series converges. Understanding this interval is important because it defines where the expression for our power series accurately represents the original function.
For a geometric series, the interval of convergence is determined by the condition \( |x| < 1 \). This criterion ensures that the sum of the infinite series is finite and meaningful. For the given function \( \frac{1+x}{1-x} \), the power series remains valid within the interval below:
Understanding intervals of convergence helps in analyzing where functions can be expanded into series solutions and the limits of these expansions.
For a geometric series, the interval of convergence is determined by the condition \( |x| < 1 \). This criterion ensures that the sum of the infinite series is finite and meaningful. For the given function \( \frac{1+x}{1-x} \), the power series remains valid within the interval below:
- \(-1 < x < 1\)
Understanding intervals of convergence helps in analyzing where functions can be expanded into series solutions and the limits of these expansions.
Function Decomposition
Function decomposition involves breaking a complex function into simpler parts to make calculations easier. In the context of our exercise, decomposing the function helps us derive its power series representation.
Given the function \( \frac{1+x}{1-x} \), we decompose it as follows:
Given the function \( \frac{1+x}{1-x} \), we decompose it as follows:
- \( \frac{1}{1-x} \) — representing the standard geometric series.
- \( \frac{x}{1-x} \) — a shifted series by multiplying \( x \), which shifts the indices of the sum.
- \( \frac{1}{1-x} = \sum_{n=0}^{\infty} x^n \)
- \( \frac{x}{1-x} = \sum_{n=1}^{\infty} x^n \)